1 Introduction
 Since their introduction [Reference Kumjian and Pask26], higher-rank graphs, or k-graphs, have been a source of interesting new higher-dimensional phenomena: in algebra [Reference Aranda Pino, Clark, an Huef and Raeburn2, Reference Clark, Flynn and an Huef13, Reference Rosjanuardi40], dynamics [Reference Kakariadis22, Reference Pask, Raeburn and Weaver34, Reference Skalski and Zacharias43, Reference Spielberg44], 
 $C^*$
-algebras [Reference Armstrong and Brownlowe3, Reference Clark, an Huef and Sims12, Reference Ruiz, Sims and Sørensen41], K-theory [Reference Evans16, Reference Gillaspy18, Reference Pask, Rennie and Sims35], topology [Reference Kaliszewski, Kumjian, Quigg and Sims23, Reference Kumjian, Pask, Sims and Whittaker28, Reference Pask, Raeburn and Quigg32, Reference Pask, Raeburn and Quigg33] and geometry [Reference Konter and Vdovina24, Reference Robertson and Steger38, Reference Vdovina45]. However, many natural questions about their structure theory remain difficult to unravel.
$C^*$
-algebras [Reference Armstrong and Brownlowe3, Reference Clark, an Huef and Sims12, Reference Ruiz, Sims and Sørensen41], K-theory [Reference Evans16, Reference Gillaspy18, Reference Pask, Rennie and Sims35], topology [Reference Kaliszewski, Kumjian, Quigg and Sims23, Reference Kumjian, Pask, Sims and Whittaker28, Reference Pask, Raeburn and Quigg32, Reference Pask, Raeburn and Quigg33] and geometry [Reference Konter and Vdovina24, Reference Robertson and Steger38, Reference Vdovina45]. However, many natural questions about their structure theory remain difficult to unravel.
 One such question, and the primary motivation for this paper, is: when can a k-graph 
 $C^*$
-algebra be realised, modulo Rieffel–Morita equivalences, as a crossed product of a commutative
$C^*$
-algebra be realised, modulo Rieffel–Morita equivalences, as a crossed product of a commutative 
 $C^*$
-algebra? For
$C^*$
-algebra? For 
 $1$
-graphs, the answer is ‘always’: given a row-finite source-free directed graph E, the middle two authors showed [Reference Kumjian and Pask25] that the
$1$
-graphs, the answer is ‘always’: given a row-finite source-free directed graph E, the middle two authors showed [Reference Kumjian and Pask25] that the 
 $C^*$
-algebra of its universal cover F is Rieffel–Morita equivalent to a commutative approximately finite-dimensional (AF) algebra, and there is an action of the fundamental group
$C^*$
-algebra of its universal cover F is Rieffel–Morita equivalent to a commutative approximately finite-dimensional (AF) algebra, and there is an action of the fundamental group 
 $\pi _1(E, v)$
 on
$\pi _1(E, v)$
 on 
 $C^*(F)$
 whose crossed product is Rieffel–Morita equivalent to
$C^*(F)$
 whose crossed product is Rieffel–Morita equivalent to 
 $C^*(E)$
. For k-graphs, the answer is more nuanced and is related to two other intriguing structural questions: when does a k-graph embed in its fundamental groupoid and when is the boundary of its universal cover Hausdorff?
$C^*(E)$
. For k-graphs, the answer is more nuanced and is related to two other intriguing structural questions: when does a k-graph embed in its fundamental groupoid and when is the boundary of its universal cover Hausdorff?
 Our main 
 $C^*$
-algebraic theorem, Theorem 4.1, clarifies the relationships between these questions: the
$C^*$
-algebraic theorem, Theorem 4.1, clarifies the relationships between these questions: the 
 $C^*$
-algebra
$C^*$
-algebra 
 $C^*(\Lambda )$
 of any connected row-finite source-free k-graph is a crossed product of an AF algebra
$C^*(\Lambda )$
 of any connected row-finite source-free k-graph is a crossed product of an AF algebra 
 $C^*(\Sigma )$
 by the fundamental group of
$C^*(\Sigma )$
 by the fundamental group of 
 $\Lambda $
; if
$\Lambda $
; if 
 $\Lambda $
 embeds in its fundamental groupoid, then the AF algebra
$\Lambda $
 embeds in its fundamental groupoid, then the AF algebra 
 $C^*(\Sigma )$
 is a Fell algebra; and if, additionally, a naturally arising sub-1-graph of
$C^*(\Sigma )$
 is a Fell algebra; and if, additionally, a naturally arising sub-1-graph of 
 $\Sigma $
 is simply connected, then the boundary of
$\Sigma $
 is simply connected, then the boundary of 
 $\Sigma $
 is Hausdorff, and
$\Sigma $
 is Hausdorff, and 
 $C^*(\Sigma )$
 is Rieffel–Morita equivalent to a commutative AF algebra. The point is that the first part of the program of [Reference Kumjian and Pask25] above goes through smoothly for k-graphs: every connected k-graph
$C^*(\Sigma )$
 is Rieffel–Morita equivalent to a commutative AF algebra. The point is that the first part of the program of [Reference Kumjian and Pask25] above goes through smoothly for k-graphs: every connected k-graph 
 $\Lambda $
 has a fundamental group
$\Lambda $
 has a fundamental group 
 $\pi (\Lambda , v)$
 [Reference Pask, Raeburn and Quigg32] and a universal cover
$\pi (\Lambda , v)$
 [Reference Pask, Raeburn and Quigg32] and a universal cover 
 $\Sigma $
 [Reference Pask, Raeburn and Quigg33] that carries an action of
$\Sigma $
 [Reference Pask, Raeburn and Quigg33] that carries an action of 
 $\pi (\Lambda , v)$
, and when
$\pi (\Lambda , v)$
, and when 
 $\Lambda $
 is row-finite and source-free, the resulting crossed product is Rieffel–Morita equivalent to
$\Lambda $
 is row-finite and source-free, the resulting crossed product is Rieffel–Morita equivalent to 
 $C^*(\Lambda )$
 [Reference Kumjian and Pask26]. Our main contribution is the analysis of
$C^*(\Lambda )$
 [Reference Kumjian and Pask26]. Our main contribution is the analysis of 
 $C^*(\Sigma )$
.
$C^*(\Sigma )$
.
 Motivated by this, we study the question of when a k-graph 
 $\Lambda $
 embeds in its fundamental groupoid. Many k-graphs do not embed: we give three examples in Section 3.1; and any k-graph containing a copy of one of these (of which there are many) also fails to embed. So we focus on checkable sufficient conditions. We show that singly connected k-graphs always embed (Proposition 3.9(ii)), and highlight a surprising difference between k-graphs and
$\Lambda $
 embeds in its fundamental groupoid. Many k-graphs do not embed: we give three examples in Section 3.1; and any k-graph containing a copy of one of these (of which there are many) also fails to embed. So we focus on checkable sufficient conditions. We show that singly connected k-graphs always embed (Proposition 3.9(ii)), and highlight a surprising difference between k-graphs and 
 $1$
-graphs: universal covers of k-graphs need not be singly connected. We include a proof that
$1$
-graphs: universal covers of k-graphs need not be singly connected. We include a proof that 
 $1$
-graphs always embed (Theorem 3.14). We then show that many standard k-graph constructions preserve embeddability: coverings (Proposition 3.13), affine pullbacks, Cartesian products, crossed-products and skew-products (Corollary 3.15), and action graphs (Corollary 3.18). The workhorse in this is Theorem 3.8, which exploits the universal properties of the fundamental groupoid and fundamental group. In Proposition 3.25, we reduce the embeddability of a connected k-graph to group-embeddability of the subsemigroup based at any vertex. Using Dilian Yang’s work [Reference Yang47] on k-graphs and Yang–Baxter solutions, we show that there are many embeddable k-graphs for all k (Lemma 3.22). We are far from a complete answer to the embeddability question. Johnstone’s general results [Reference Johnstone21] characterise groupoid-embeddability of categories, but the hypotheses seem uncheckable: we gleaned no practical conditions—either necessary or sufficient—from Johnstone’s work, beyond the neat result of Lawson and Vdovina [Reference Lawson and Vdovina29, Theorem 11.14] presented in Remark 3.24. One might hope for help from Ore’s theorem [Reference Dehornoy, Digne, Godelle, Krammer and Michel15, Proposition II.3.11], but by the factorisation property, no interesting k-graphs are Ore. Remarks 4.17 and 4.18 indicate how much we still do not know about embeddability.
$1$
-graphs always embed (Theorem 3.14). We then show that many standard k-graph constructions preserve embeddability: coverings (Proposition 3.13), affine pullbacks, Cartesian products, crossed-products and skew-products (Corollary 3.15), and action graphs (Corollary 3.18). The workhorse in this is Theorem 3.8, which exploits the universal properties of the fundamental groupoid and fundamental group. In Proposition 3.25, we reduce the embeddability of a connected k-graph to group-embeddability of the subsemigroup based at any vertex. Using Dilian Yang’s work [Reference Yang47] on k-graphs and Yang–Baxter solutions, we show that there are many embeddable k-graphs for all k (Lemma 3.22). We are far from a complete answer to the embeddability question. Johnstone’s general results [Reference Johnstone21] characterise groupoid-embeddability of categories, but the hypotheses seem uncheckable: we gleaned no practical conditions—either necessary or sufficient—from Johnstone’s work, beyond the neat result of Lawson and Vdovina [Reference Lawson and Vdovina29, Theorem 11.14] presented in Remark 3.24. One might hope for help from Ore’s theorem [Reference Dehornoy, Digne, Godelle, Krammer and Michel15, Proposition II.3.11], but by the factorisation property, no interesting k-graphs are Ore. Remarks 4.17 and 4.18 indicate how much we still do not know about embeddability.
 Finally, as definitive general results about embeddability are still beyond reach, we present a class of examples arising from the combinatorial objects used by Roberston and Steger to construct higher-rank Cuntz–Krieger 
 $C^*$
-algebras in [Reference Robertson and Steger38, Reference Robertson and Steger39], which first inspired the middle two authors to develop the concept of a higher-rank graph. We show in Theorem 5.17 and Proposition 5.20 that every
$C^*$
-algebras in [Reference Robertson and Steger38, Reference Robertson and Steger39], which first inspired the middle two authors to develop the concept of a higher-rank graph. We show in Theorem 5.17 and Proposition 5.20 that every 
 $\tilde {A_2}$
-group
$\tilde {A_2}$
-group 
 $\Gamma _{\mathcal {T}}$
 yields
$\Gamma _{\mathcal {T}}$
 yields 
 $2$
-graphs
$2$
-graphs 
 $\Lambda _{\mathcal {T}}$
 and
$\Lambda _{\mathcal {T}}$
 and 
 $\Sigma _{\mathcal {T}}$
, the latter being a cover of the former, and in Corollary 5.19 that
$\Sigma _{\mathcal {T}}$
, the latter being a cover of the former, and in Corollary 5.19 that 
 $\Lambda _{\mathcal {T}}$
 embeds in its fundamental groupoid—Proposition 3.13 then shows that
$\Lambda _{\mathcal {T}}$
 embeds in its fundamental groupoid—Proposition 3.13 then shows that 
 $\Sigma _{\mathcal {T}}$
 embeds as well. We also prove that
$\Sigma _{\mathcal {T}}$
 embeds as well. We also prove that 
 $\Sigma _{\mathcal {T}}$
 is singly connected and deduce that its
$\Sigma _{\mathcal {T}}$
 is singly connected and deduce that its 
 $C^*$
-algebra is type I
$C^*$
-algebra is type I
 $_0$
. The construction of
$_0$
. The construction of 
 $\Lambda _{\mathcal {T}}$
 is related to a number of existing constructions. It is directly inspired by [Reference Robertson and Steger38, pages 135–136]. As discussed in [Reference Cartwright, Mantero, Steger and Zappa8, Reference Robertson and Steger38], a thick
$\Lambda _{\mathcal {T}}$
 is related to a number of existing constructions. It is directly inspired by [Reference Robertson and Steger38, pages 135–136]. As discussed in [Reference Cartwright, Mantero, Steger and Zappa8, Reference Robertson and Steger38], a thick 
 $\tilde {A_2}$
-building
$\tilde {A_2}$
-building 
 $\mathscr {B}$
 carrying a vertex-transitive action of an
$\mathscr {B}$
 carrying a vertex-transitive action of an 
 $\tilde {A_2}$
-group
$\tilde {A_2}$
-group 
 $\Gamma _{\mathcal {T}}$
 arises from a finite projective plane
$\Gamma _{\mathcal {T}}$
 arises from a finite projective plane 
 $(P, L)$
, a bijection between P and L, and a compatible triangle presentation
$(P, L)$
, a bijection between P and L, and a compatible triangle presentation 
 $\mathcal {T}$
 on P, the points of the projective plane, arising from the local structure of the building (see [Reference Cartwright, Mantero, Steger and Zappa8, Section 3]). The
$\mathcal {T}$
 on P, the points of the projective plane, arising from the local structure of the building (see [Reference Cartwright, Mantero, Steger and Zappa8, Section 3]). The 
 $\tilde {A_2}$
-group
$\tilde {A_2}$
-group 
 $\Gamma _{\mathcal {T}}$
 is generated by a set indexed by P subject to the relations encoded in
$\Gamma _{\mathcal {T}}$
 is generated by a set indexed by P subject to the relations encoded in 
 $\mathcal {T}$
. The
$\mathcal {T}$
. The 
 $\tilde {A_2}$
-building
$\tilde {A_2}$
-building 
 $\mathscr {B}$
 is constructed as an augmented Cayley graph of
$\mathscr {B}$
 is constructed as an augmented Cayley graph of 
 $\Gamma _{\mathcal {T}}$
 with 2-simplices given by
$\Gamma _{\mathcal {T}}$
 with 2-simplices given by 
 $\mathcal {T}$
. Our
$\mathcal {T}$
. Our 
 $\Lambda _{\mathcal {T}}$
 is isomorphic to the
$\Lambda _{\mathcal {T}}$
 is isomorphic to the 
 $2$
-graph obtained from [Reference Kumjian and Pask26, Example 1.7(iv)] from the
$2$
-graph obtained from [Reference Kumjian and Pask26, Example 1.7(iv)] from the 
 $0$
–
$0$
–
 $1$
 matrices
$1$
 matrices 
 $M_i$
 of [Reference Robertson and Steger38, page 135] (see Remark 5.18). Geometric considerations suggest both that
$M_i$
 of [Reference Robertson and Steger38, page 135] (see Remark 5.18). Geometric considerations suggest both that 
 $\Sigma _{\mathcal {T}}$
 should be simply connected, and therefore equal to the universal cover of
$\Sigma _{\mathcal {T}}$
 should be simply connected, and therefore equal to the universal cover of 
 $\Lambda _{\mathcal {T}}$
, and that its topological realisation should coincide with that of
$\Lambda _{\mathcal {T}}$
, and that its topological realisation should coincide with that of 
 $\mathscr {B}$
, so it should have Hausdorff boundary; we leave this for future work. Our construction is also related to the construction of k-graphs from groups in [Reference Mutter, Radu and Vdovina31], but cannot be recovered from it: the covering
$\mathscr {B}$
, so it should have Hausdorff boundary; we leave this for future work. Our construction is also related to the construction of k-graphs from groups in [Reference Mutter, Radu and Vdovina31], but cannot be recovered from it: the covering 
 $2$
-graphs in [Reference Mutter, Radu and Vdovina31] are products of trees rather than
$2$
-graphs in [Reference Mutter, Radu and Vdovina31] are products of trees rather than 
 $\tilde {A_2}$
-buildings.
$\tilde {A_2}$
-buildings.
2 Background and preliminary results
2.1 Higher-rank graphs
 We write 
 $\mathbb {N}$
 for the additive monoid
$\mathbb {N}$
 for the additive monoid 
 $\{ 0, 1 ,\ldots \}$
. We denote the standard generators of
$\{ 0, 1 ,\ldots \}$
. We denote the standard generators of 
 $\mathbb {N}^k \subset \mathbb {Z}^k$
 by
$\mathbb {N}^k \subset \mathbb {Z}^k$
 by 
 $\varepsilon _1, \ldots ,\varepsilon _k$
, and we write
$\varepsilon _1, \ldots ,\varepsilon _k$
, and we write 
 $n_i$
 for the ith coordinate of
$n_i$
 for the ith coordinate of 
 $n \in \mathbb {N}^k$
. We write
$n \in \mathbb {N}^k$
. We write 
 $\mathbf {1}_k$
 or just
$\mathbf {1}_k$
 or just 
 $\mathbf {1}$
 for
$\mathbf {1}$
 for 
 $(1, \ldots , 1) \in \mathbb {N}^k$
.
$(1, \ldots , 1) \in \mathbb {N}^k$
.
 A k-graph is a small category 
 $\Lambda $
 equipped with a functor
$\Lambda $
 equipped with a functor 
 $d :\Lambda \to \mathbb {N}^k$
 satisfying the factorisation property: whenever
$d :\Lambda \to \mathbb {N}^k$
 satisfying the factorisation property: whenever 
 $d(\lambda ) = m+n$
, there exist unique
$d(\lambda ) = m+n$
, there exist unique 
 $\mu ,\nu \in \Lambda $
 such that
$\mu ,\nu \in \Lambda $
 such that 
 $d(\mu )=m$
,
$d(\mu )=m$
, 
 $d(\nu )=n$
 and
$d(\nu )=n$
 and 
 $\lambda =\mu \nu $
. This implies that
$\lambda =\mu \nu $
. This implies that 
 $\Lambda $
 is cancellative. We write
$\Lambda $
 is cancellative. We write 
 ${\Lambda ^n := d^{-1} (n)}$
 for
${\Lambda ^n := d^{-1} (n)}$
 for 
 $n \in \mathbb {N}^k$
. When
$n \in \mathbb {N}^k$
. When 
 $d(\lambda )=n$
, we say
$d(\lambda )=n$
, we say 
 $\lambda $
 has degree n. The factorisation property implies that
$\lambda $
 has degree n. The factorisation property implies that 
 $\Lambda ^0$
 is the set of identity morphisms, which we call vertices. Elements of
$\Lambda ^0$
 is the set of identity morphisms, which we call vertices. Elements of 
 $\bigcup _i \Lambda ^{\varepsilon _i}$
 are called edges. For
$\bigcup _i \Lambda ^{\varepsilon _i}$
 are called edges. For 
 $u,v\in \Lambda ^0$
, we write
$u,v\in \Lambda ^0$
, we write 
 $u\Lambda := r^{-1}(u)$
,
$u\Lambda := r^{-1}(u)$
, 
 $\Lambda v:=s^{-1}(v)$
 and
$\Lambda v:=s^{-1}(v)$
 and 
 ${u\Lambda v:=u\Lambda \cap \Lambda v}$
.
${u\Lambda v:=u\Lambda \cap \Lambda v}$
.
Notation 2.1. For 
 $\lambda \in \Lambda $
 and
$\lambda \in \Lambda $
 and 
 $0 \le m \le n \le d(\lambda )$
, we write
$0 \le m \le n \le d(\lambda )$
, we write 
 $\lambda (m,n)$
 for the unique element of
$\lambda (m,n)$
 for the unique element of 
 $\Lambda $
 such that
$\Lambda $
 such that 
 $\lambda \in \Lambda ^m \lambda (m,n)\Lambda ^{d(\lambda ) -n}$
. We define
$\lambda \in \Lambda ^m \lambda (m,n)\Lambda ^{d(\lambda ) -n}$
. We define 
 $\lambda (n) := \lambda (n,n) = s(\lambda (0,n))$
.
$\lambda (n) := \lambda (n,n) = s(\lambda (0,n))$
.
Definition 2.2. The k-graph 
 $\Lambda $
 is connected if the equivalence relation
$\Lambda $
 is connected if the equivalence relation 
 $\sim $
 on
$\sim $
 on 
 $\Lambda ^0$
 generated by
$\Lambda ^0$
 generated by 
 $\{(u,v)\mid u\Lambda v\ne \emptyset \}$
 is
$\{(u,v)\mid u\Lambda v\ne \emptyset \}$
 is 
 $\Lambda ^0\times \Lambda ^0$
. A k-graph is strongly connected if
$\Lambda ^0\times \Lambda ^0$
. A k-graph is strongly connected if 
 $u \Lambda v \neq \emptyset $
 for all
$u \Lambda v \neq \emptyset $
 for all 
 $u,v \in \Lambda ^0$
.
$u,v \in \Lambda ^0$
.
 A morphism 
 $\phi : \Omega \to \Lambda $
 between k-graphs is a functor such that
$\phi : \Omega \to \Lambda $
 between k-graphs is a functor such that 
 $d_\Lambda ( \phi ( \lambda ) ) = d_\Omega ( \lambda )$
 for all
$d_\Lambda ( \phi ( \lambda ) ) = d_\Omega ( \lambda )$
 for all 
 $\lambda \in \Omega $
. A quasi-morphism from a k-graph
$\lambda \in \Omega $
. A quasi-morphism from a k-graph 
 $( \Omega , d_\Omega )$
 to an
$( \Omega , d_\Omega )$
 to an 
 $\ell $
-graph
$\ell $
-graph 
 $( \Lambda , d_\Lambda )$
 is a pair
$( \Lambda , d_\Lambda )$
 is a pair 
 $( \phi , f)$
 consisting of a functor
$( \phi , f)$
 consisting of a functor 
 $\phi : \Omega \to \Lambda $
 and a homomorphism
$\phi : \Omega \to \Lambda $
 and a homomorphism 
 $f: \mathbb {N}^k \to \mathbb {N}^\ell $
 such that
$f: \mathbb {N}^k \to \mathbb {N}^\ell $
 such that 
 $d_\Lambda \circ \phi = f \circ d_\Omega $
. If
$d_\Lambda \circ \phi = f \circ d_\Omega $
. If 
 $\Lambda $
 is a k-graph, then
$\Lambda $
 is a k-graph, then 
 $\Lambda ^{\mathbb {N}\mathbf {1}} := \{\lambda \in \Lambda : d(\lambda ) \in \mathbb {N}\mathbf { 1}\}$
 is a
$\Lambda ^{\mathbb {N}\mathbf {1}} := \{\lambda \in \Lambda : d(\lambda ) \in \mathbb {N}\mathbf { 1}\}$
 is a 
 $1$
-graph and the natural inclusion
$1$
-graph and the natural inclusion 
 $\Lambda ^{\mathbb {N}\mathbf {1}} \hookrightarrow \Lambda $
 together with the map
$\Lambda ^{\mathbb {N}\mathbf {1}} \hookrightarrow \Lambda $
 together with the map 
 $f: \mathbb {N} \to \mathbb {N}^k$
 given by
$f: \mathbb {N} \to \mathbb {N}^k$
 given by 
 $f(n) := n\mathbf {1}$
 is a quasimorphism.
$f(n) := n\mathbf {1}$
 is a quasimorphism.
Examples 2.3.
- 
(i) Let  $B_n$
 be the directed graph with $B_n$
 be the directed graph with $B_n^{0} = \{u\}$
 and $B_n^{0} = \{u\}$
 and $B^1_n = \{f_1 , \ldots , f_n\}$
. Its path category $B^1_n = \{f_1 , \ldots , f_n\}$
. Its path category $B_n^*$
 is a $B_n^*$
 is a $1$
-graph and coincides with the free semigroup $1$
-graph and coincides with the free semigroup $\mathbb {F}_n^+$
 on n generators. $\mathbb {F}_n^+$
 on n generators.
- 
(ii) Let  $\Delta _k = \{ (m,n) \in \mathbb {Z}^k \times \mathbb {Z}^k : m \le n \}$
. Define $\Delta _k = \{ (m,n) \in \mathbb {Z}^k \times \mathbb {Z}^k : m \le n \}$
. Define $r,s : \Delta _k \to \operatorname {Obj} \Delta _k$
 by $r,s : \Delta _k \to \operatorname {Obj} \Delta _k$
 by $r (m,n) = m$
, $r (m,n) = m$
, $s (m,n) = n$
, and for $s (m,n) = n$
, and for $m \le m \le p \in \mathbb {Z}^k$
, define $m \le m \le p \in \mathbb {Z}^k$
, define $(m,n)(n,p)=(m,p)$
 and $(m,n)(n,p)=(m,p)$
 and $d (m,n) = n-m$
. Then $d (m,n) = n-m$
. Then $( \Delta _k , d )$
 is a k-graph where $( \Delta _k , d )$
 is a k-graph where $\operatorname {Obj} \Delta _k$
 is identified with $\operatorname {Obj} \Delta _k$
 is identified with $\{ (m,m) : m \in \mathbb {Z}^k \} \subset \operatorname {Mor} \Delta _k$
. $\{ (m,m) : m \in \mathbb {Z}^k \} \subset \operatorname {Mor} \Delta _k$
.
- 
(iii) Similarly,  $\Omega _k = \{(m,n) \in \mathbb {N}^k \times \mathbb {N}^k : m \le n\}$
 is a sub-k-graph of $\Omega _k = \{(m,n) \in \mathbb {N}^k \times \mathbb {N}^k : m \le n\}$
 is a sub-k-graph of $\Delta _k$
. $\Delta _k$
.
Example 2.4 (Skew-product graphs).
 Let 
 $\Lambda $
 be a k-graph, G a group and
$\Lambda $
 be a k-graph, G a group and 
 $c: \Lambda \to G$
 a
$c: \Lambda \to G$
 a 
 $1$
-cocycle (functor). Then the set
$1$
-cocycle (functor). Then the set 
 $G \times _c \Lambda := \{ (g, \lambda ) : g \in G, \lambda \in \Lambda \}$
, under the structure maps
$G \times _c \Lambda := \{ (g, \lambda ) : g \in G, \lambda \in \Lambda \}$
, under the structure maps 
 $$ \begin{align*} s (g, \lambda ) &= ( g c ( \lambda ), s ( \lambda ) ), \quad r (g, \lambda ) = (g, r(\lambda )), \nonumber\\ (g, \lambda ) \cdot (g c (\lambda), \mu) &= (g, \lambda \mu ), \qquad\quad\kern0.8pt d (g , \lambda ) = d ( \lambda ) \end{align*} $$
$$ \begin{align*} s (g, \lambda ) &= ( g c ( \lambda ), s ( \lambda ) ), \quad r (g, \lambda ) = (g, r(\lambda )), \nonumber\\ (g, \lambda ) \cdot (g c (\lambda), \mu) &= (g, \lambda \mu ), \qquad\quad\kern0.8pt d (g , \lambda ) = d ( \lambda ) \end{align*} $$
is a k-graph called the skew-product graph [Reference Kumjian and Pask26, Definition 5.1]. Left translation by G on the first coordinate of 
 $G \times _c \Lambda $
 is an action of G by k-graph automorphisms.
$G \times _c \Lambda $
 is an action of G by k-graph automorphisms.
There are two equivalent conventions for skew-product graphs in the literature: the other is [Reference Pask, Raeburn and Quigg33, Definition 6.3] (see also [Reference Bédos, Kaliszewski and Quigg5, Definition 3.5]). In [Reference Pask, Raeburn and Quigg33, Definition 6.3],
 $$ \begin{align*}\Lambda \times _c G := \{ (\lambda , g) : \lambda \in \Lambda , g \in G \}\end{align*} $$
$$ \begin{align*}\Lambda \times _c G := \{ (\lambda , g) : \lambda \in \Lambda , g \in G \}\end{align*} $$
with structure maps
 $$ \begin{align*} s ( \lambda , g ) &= ( s ( \lambda ) , g ), \quad r ( \lambda , g ) = ( r(\lambda ) , c( \lambda)g ), \\ ( \lambda , c( \lambda)g ) \cdot ( \mu , g ) &= ( \lambda \mu , g ), \quad\kern1pt\ d ( \lambda , g ) = d ( \lambda ). \end{align*} $$
$$ \begin{align*} s ( \lambda , g ) &= ( s ( \lambda ) , g ), \quad r ( \lambda , g ) = ( r(\lambda ) , c( \lambda)g ), \\ ( \lambda , c( \lambda)g ) \cdot ( \mu , g ) &= ( \lambda \mu , g ), \quad\kern1pt\ d ( \lambda , g ) = d ( \lambda ). \end{align*} $$
It is simple to check that 
 $\phi (g, \lambda ) = (\lambda , c( \lambda )^{-1}g^{-1})$
 yields an isomorphism
$\phi (g, \lambda ) = (\lambda , c( \lambda )^{-1}g^{-1})$
 yields an isomorphism 
 ${\phi : G \times _c \Lambda \to \Lambda \times _c G}$
.
${\phi : G \times _c \Lambda \to \Lambda \times _c G}$
.
Example 2.5 (Monoidal 
 $2$
-graphs).
$2$
-graphs).
 The following class of 2-graphs was introduced in [Reference Kumjian and Pask26, Section 6] and later studied extensively by Yang et al. [Reference Davidson, Power and Yang14, Reference Yang46, Reference Yang47]. Fix 
 ${n_1 , n_2 \ge 1}$
. Let
${n_1 , n_2 \ge 1}$
. Let 
 $[n_i ]= \{ 1 , \ldots , n_i \}$
 for
$[n_i ]= \{ 1 , \ldots , n_i \}$
 for 
 $i=1,2$
. Let
$i=1,2$
. Let 
 $\theta : [n_1 ]\times [n_2] \to [n_2] \times [n_1]$
 be a bijection. The monoidal
$\theta : [n_1 ]\times [n_2] \to [n_2] \times [n_1]$
 be a bijection. The monoidal 
 $2$
-graph
$2$
-graph 
 $\mathbb {F}_\theta ^+$
 is the unique
$\mathbb {F}_\theta ^+$
 is the unique 
 $2$
-graph such that
$2$
-graph such that 
 $(\mathbb {F}_\theta ^+)^0 = \{v\}$
,
$(\mathbb {F}_\theta ^+)^0 = \{v\}$
, 
 $(\mathbb {F}_\theta ^+)^{\varepsilon _1} = \{ e_{1}, \ldots , e_{n_2} \}$
,
$(\mathbb {F}_\theta ^+)^{\varepsilon _1} = \{ e_{1}, \ldots , e_{n_2} \}$
, 
 $(\mathbb {F}_\theta ^+)^{\varepsilon _2} = \{ f_{1}, \ldots , f_{n_2} \}$
 and
$(\mathbb {F}_\theta ^+)^{\varepsilon _2} = \{ f_{1}, \ldots , f_{n_2} \}$
 and 
 $$ \begin{align*} e_i f_j = f_{j'} e_{i'} \quad\text{whenever } \theta (i,j) = (j',i'). \end{align*} $$
$$ \begin{align*} e_i f_j = f_{j'} e_{i'} \quad\text{whenever } \theta (i,j) = (j',i'). \end{align*} $$
Remark 2.6. In their early papers, Yang et al. define 
 $\mathbb {F}_\theta ^+$
 in terms of a bijection
$\mathbb {F}_\theta ^+$
 in terms of a bijection 
 ${\theta : [n_1 ]\times [n_2] \to [n_1] \times [n_2]}$
 rather than
${\theta : [n_1 ]\times [n_2] \to [n_1] \times [n_2]}$
 rather than 
 $[n_1 ]\times [n_2] \to [n_2] \times [n_1]$
.
$[n_1 ]\times [n_2] \to [n_2] \times [n_1]$
.
 An affine map 
 $f : \mathbb {N}^\ell \to \mathbb {N}^k$
 is a map of the form
$f : \mathbb {N}^\ell \to \mathbb {N}^k$
 is a map of the form 
 $f(n) = An+p$
 for
$f(n) = An+p$
 for 
 $A \in M_{\ell ,k} ( \mathbb {N} )$
 and
$A \in M_{\ell ,k} ( \mathbb {N} )$
 and 
 $p \in \mathbb {N}^\ell $
. The next proposition unifies the pullback construction of [Reference Kumjian and Pask26, Definition 1.9] (case
$p \in \mathbb {N}^\ell $
. The next proposition unifies the pullback construction of [Reference Kumjian and Pask26, Definition 1.9] (case 
 $p=0$
) and the p-dual graph of [Reference Allen, Pask and Sims1, Definition 3.2] (case
$p=0$
) and the p-dual graph of [Reference Allen, Pask and Sims1, Definition 3.2] (case 
 $A=I$
).
$A=I$
).
Proposition 2.7 (Affine pullbacks).
 Let 
 $(\Lambda ,d)$
 be a k-graph and let
$(\Lambda ,d)$
 be a k-graph and let 
 $f : \mathbb {N}^\ell \to \mathbb {N}^k$
 be an affine map with
$f : \mathbb {N}^\ell \to \mathbb {N}^k$
 be an affine map with 
 $f(0)=p \in \mathbb {N}^k$
. Set
$f(0)=p \in \mathbb {N}^k$
. Set 
 $f^* (\Lambda ) = \{ ( \lambda , n ) : d ( \lambda ) = f(n) \} \subseteq \Lambda \times \mathbb {N}^\ell $
. Then
$f^* (\Lambda ) = \{ ( \lambda , n ) : d ( \lambda ) = f(n) \} \subseteq \Lambda \times \mathbb {N}^\ell $
. Then 
 $f^*(\Lambda )$
 is an
$f^*(\Lambda )$
 is an 
 $\ell $
-graph, with
$\ell $
-graph, with 
 $r (\lambda , n ) = [ \lambda (0,p) , 0]$
,
$r (\lambda , n ) = [ \lambda (0,p) , 0]$
, 
 $s ( \lambda , n ) = [\lambda ( d(\lambda ) -p , d(\lambda )),0]$
,
$s ( \lambda , n ) = [\lambda ( d(\lambda ) -p , d(\lambda )),0]$
, 
 $$ \begin{align*} (\lambda , m ) \circ (\mu , n ) = ( \lambda ( 0 , d(\lambda)-p) \mu , m+n) \text{ if }s (\lambda , m ) = r ( \mu , n ), \end{align*} $$
$$ \begin{align*} (\lambda , m ) \circ (\mu , n ) = ( \lambda ( 0 , d(\lambda)-p) \mu , m+n) \text{ if }s (\lambda , m ) = r ( \mu , n ), \end{align*} $$
and 
 $d_{f^*(\Lambda )} (\lambda ,n) = n$
. We have
$d_{f^*(\Lambda )} (\lambda ,n) = n$
. We have 
 $f^*(\Lambda )^0 = \{ ( \lambda , 0 ) : \lambda \in \Lambda ^p \}$
.
$f^*(\Lambda )^0 = \{ ( \lambda , 0 ) : \lambda \in \Lambda ^p \}$
.
Proof. As in [Reference Kumjian and Pask26, Definition 1.9], the pullback 
 $A^*(\Lambda )$
 of
$A^*(\Lambda )$
 of 
 $\Lambda $
 by the homomorphism
$\Lambda $
 by the homomorphism 
 $A : \mathbb {N}^\ell \to \mathbb {N}^k$
 is an
$A : \mathbb {N}^\ell \to \mathbb {N}^k$
 is an 
 $\ell $
-graph. By [Reference Allen, Pask and Sims1, Proposition 3.2], its dual
$\ell $
-graph. By [Reference Allen, Pask and Sims1, Proposition 3.2], its dual 
 $p(A^*(\Lambda ))$
 is also an
$p(A^*(\Lambda ))$
 is also an 
 $\ell $
-graph. As sets,
$\ell $
-graph. As sets, 

Direct calculations show that this identification intertwines the structure maps above with those of 
 $p(A^*(\Lambda ))$
.
$p(A^*(\Lambda ))$
.
Example 2.8 (Crossed-product graph).
 Let 
 $\alpha : \mathbb {Z}^\ell \to \operatorname {Aut} \Lambda $
 be an action of
$\alpha : \mathbb {Z}^\ell \to \operatorname {Aut} \Lambda $
 be an action of 
 $\mathbb {Z}^\ell $
 on a k-graph
$\mathbb {Z}^\ell $
 on a k-graph 
 $\Lambda $
. Then the set
$\Lambda $
. Then the set 
 $\Lambda \times \mathbb {N}^\ell $
 with the structure maps
$\Lambda \times \mathbb {N}^\ell $
 with the structure maps 
 $$\begin{align*}\begin{array}{lr@{\ }lr@{\ }l} &r ( \lambda , m ) &= ( r ( \lambda ) , 0 ) , &s ( \lambda , m ) &= ( \alpha^{-m} (s (\lambda ) ) , 0 ) , \\[5pt] &( \lambda , m )( \mu , n )&= ( \lambda \alpha^m ( \mu ) , m+n ), & d ( \lambda , m ) &= ( d ( \lambda) , m ) \end{array} \end{align*}$$
$$\begin{align*}\begin{array}{lr@{\ }lr@{\ }l} &r ( \lambda , m ) &= ( r ( \lambda ) , 0 ) , &s ( \lambda , m ) &= ( \alpha^{-m} (s (\lambda ) ) , 0 ) , \\[5pt] &( \lambda , m )( \mu , n )&= ( \lambda \alpha^m ( \mu ) , m+n ), & d ( \lambda , m ) &= ( d ( \lambda) , m ) \end{array} \end{align*}$$
is a 
 $(k + \ell )$
-graph, called the crossed-product graph
$(k + \ell )$
-graph, called the crossed-product graph 
 $\Lambda \times _\alpha \mathbb {N}^\ell $
 (see [Reference Farthing, Pask and Sims17]).
$\Lambda \times _\alpha \mathbb {N}^\ell $
 (see [Reference Farthing, Pask and Sims17]).
2.2 Fundamental groupoids, fundamental groups and universal covers
 Every k-graph 
 $\Lambda $
 has a fundamental groupoid, defined as follows (see [Reference Schubert42, Section 19.1] or [Reference Pask, Raeburn and Quigg32, Section 3]).
$\Lambda $
 has a fundamental groupoid, defined as follows (see [Reference Schubert42, Section 19.1] or [Reference Pask, Raeburn and Quigg32, Section 3]).
Definition 2.9. Let 
 $\Lambda $
 be a k-graph. There exists a groupoid
$\Lambda $
 be a k-graph. There exists a groupoid 
 $\Pi (\Lambda )$
 and a functor
$\Pi (\Lambda )$
 and a functor 
 $i : \Lambda \to \Pi (\Lambda )$
 such that
$i : \Lambda \to \Pi (\Lambda )$
 such that 
 $i(\Lambda ^0)=\Pi (\Lambda )^0$
, with the following universal property: for every functor F from
$i(\Lambda ^0)=\Pi (\Lambda )^0$
, with the following universal property: for every functor F from 
 $\Lambda $
 into a groupoid
$\Lambda $
 into a groupoid 
 $\mathcal {G}$
, there exists a unique groupoid homomorphism
$\mathcal {G}$
, there exists a unique groupoid homomorphism 
 $\tilde {F} : \Pi (\Lambda ) \to \mathcal {G}$
 such that
$\tilde {F} : \Pi (\Lambda ) \to \mathcal {G}$
 such that 
 $\tilde {F} \circ i = F$
. The pair
$\tilde {F} \circ i = F$
. The pair 
 $(\Pi (\Lambda ), i)$
 is unique up to canonical isomorphism, so we refer to any such groupoid
$(\Pi (\Lambda ), i)$
 is unique up to canonical isomorphism, so we refer to any such groupoid 
 $\Pi (\Lambda )$
 as the fundamental groupoid of
$\Pi (\Lambda )$
 as the fundamental groupoid of 
 $\Lambda $
.
$\Lambda $
.
Remark 2.10. The assignment 
 $\Lambda \mapsto \Pi (\Lambda )$
 is a functor from k-graphs to groupoids. The restriction of
$\Lambda \mapsto \Pi (\Lambda )$
 is a functor from k-graphs to groupoids. The restriction of 
 $i : \Lambda \to \Pi (\Lambda )$
 to
$i : \Lambda \to \Pi (\Lambda )$
 to 
 $\Lambda ^0$
 is injective with range
$\Lambda ^0$
 is injective with range 
 $\Pi (\Lambda )^0$
 and thus we identify
$\Pi (\Lambda )^0$
 and thus we identify 
 $\Lambda ^0$
 with
$\Lambda ^0$
 with 
 $\Pi (\Lambda )^0$
. Note that
$\Pi (\Lambda )^0$
. Note that 
 $\Pi (\Lambda )$
 is denoted
$\Pi (\Lambda )$
 is denoted 
 $\mathcal {G} (\Lambda )$
 in [Reference Pask, Raeburn and Quigg32], but this clashes with the notation for path groupoids in Section 2.4 and [Reference Kumjian and Pask26].
$\mathcal {G} (\Lambda )$
 in [Reference Pask, Raeburn and Quigg32], but this clashes with the notation for path groupoids in Section 2.4 and [Reference Kumjian and Pask26].
Each component of a k-graph also has a fundamental group.
Definition 2.11. Let 
 $\Lambda $
 be a k-graph. The fundamental group
$\Lambda $
 be a k-graph. The fundamental group 
 $\pi _1(\Lambda , v)$
 of
$\pi _1(\Lambda , v)$
 of 
 $\Lambda $
 at
$\Lambda $
 at 
 $v \in \Lambda ^0$
 is the isotropy group
$v \in \Lambda ^0$
 is the isotropy group 
 $\pi _1 (\Lambda , v) := v \Pi ( \Lambda ) v$
 of
$\pi _1 (\Lambda , v) := v \Pi ( \Lambda ) v$
 of 
 $\Pi (\Lambda )$
 at v.
$\Pi (\Lambda )$
 at v.
Definition 2.12. For 
 $X \not = \emptyset $
, the pair groupoid of X is
$X \not = \emptyset $
, the pair groupoid of X is 
 $T(X) := X \times X$
, the simple transitive groupoid with unit space
$T(X) := X \times X$
, the simple transitive groupoid with unit space 
 $\{(x,x) : x \in X\}$
 identified with X; it has structure maps
$\{(x,x) : x \in X\}$
 identified with X; it has structure maps 
 $$ \begin{align*} r(x, y) := x, \quad s(x, y) := y, \quad (x, y)(y, z) := (x, z), \quad (x, y)^{-1} := (y, x). \end{align*} $$
$$ \begin{align*} r(x, y) := x, \quad s(x, y) := y, \quad (x, y)(y, z) := (x, z), \quad (x, y)^{-1} := (y, x). \end{align*} $$
Remark 2.13. Suppose that 
 $\Lambda $
 is connected. Then for every
$\Lambda $
 is connected. Then for every 
 $u, v \in \Lambda ^0$
,
$u, v \in \Lambda ^0$
, 
 $\pi _1 (\Lambda , u) \cong \pi _1 (\Lambda , v)$
, but the isomorphism
$\pi _1 (\Lambda , u) \cong \pi _1 (\Lambda , v)$
, but the isomorphism 
 $\pi _1(\Lambda , u) \to \pi _1(\Lambda , v)$
 is noncanonical.
$\pi _1(\Lambda , u) \to \pi _1(\Lambda , v)$
 is noncanonical.
 Let 
 $v \in \Lambda ^0$
. Then there exists a function
$v \in \Lambda ^0$
. Then there exists a function 
 $w \mapsto \gamma _w$
 from
$w \mapsto \gamma _w$
 from 
 $\Lambda ^0$
 to
$\Lambda ^0$
 to 
 $\Pi (\Lambda )v$
 such that
$\Pi (\Lambda )v$
 such that 
 $\gamma _v = v$
 and
$\gamma _v = v$
 and 
 $r(\gamma _w) = w$
 for all w. Any such function
$r(\gamma _w) = w$
 for all w. Any such function 
 $\gamma $
 determines a
$\gamma $
 determines a 
 $1$
-cocycle
$1$
-cocycle 
 $\kappa = \kappa _\gamma : \Lambda \to \pi _1 (\Lambda , v)$
, given by
$\kappa = \kappa _\gamma : \Lambda \to \pi _1 (\Lambda , v)$
, given by 
 $$ \begin{align*} \kappa_\gamma(\lambda) := \gamma_{r(\lambda)}^{-1} i(\lambda)\gamma_{s(\lambda)} \quad \text{for } \lambda \in \Lambda, \end{align*} $$
$$ \begin{align*} \kappa_\gamma(\lambda) := \gamma_{r(\lambda)}^{-1} i(\lambda)\gamma_{s(\lambda)} \quad \text{for } \lambda \in \Lambda, \end{align*} $$
and an isomorphism 
 $\phi _\gamma : \Pi (\Lambda ) \to \pi _1 (\Lambda , v) \times T(\Lambda ^0)$
 (see [Reference Pask, Raeburn and Quigg33, Corollary 6.5]) given for
$\phi _\gamma : \Pi (\Lambda ) \to \pi _1 (\Lambda , v) \times T(\Lambda ^0)$
 (see [Reference Pask, Raeburn and Quigg33, Corollary 6.5]) given for 
 $g \in \Pi (\Lambda )$
 by
$g \in \Pi (\Lambda )$
 by 
 $$ \begin{align*} \phi_\gamma(g) := (\gamma_{r(g)}^{-1} g\gamma_{s(g)}, (r(g), s(g))). \end{align*} $$
$$ \begin{align*} \phi_\gamma(g) := (\gamma_{r(g)}^{-1} g\gamma_{s(g)}, (r(g), s(g))). \end{align*} $$
Thus, we have 
 $(\phi _\gamma \circ i)(\lambda ) = (\kappa _\gamma (\lambda ), (r(\lambda ), s(\lambda )))$
 for all
$(\phi _\gamma \circ i)(\lambda ) = (\kappa _\gamma (\lambda ), (r(\lambda ), s(\lambda )))$
 for all 
 $\lambda \in \Lambda $
.
$\lambda \in \Lambda $
.
The following definitions appear in [Reference Pask, Raeburn and Quigg33]. We include them for completeness.
Definition 2.14. Let 
 $\Lambda , \Sigma , \Gamma $
 be k-graphs.
$\Lambda , \Sigma , \Gamma $
 be k-graphs. 
- 
(i) A surjective k-graph morphism  $p : \Sigma \to \Lambda $
 is a covering if for all $p : \Sigma \to \Lambda $
 is a covering if for all $v \in \Sigma ^0$
, p restricts to bijections $v \in \Sigma ^0$
, p restricts to bijections $\Sigma v \to \Lambda p(v)$
 and $\Sigma v \to \Lambda p(v)$
 and $v \Sigma \to p(v) \Lambda $
. $v \Sigma \to p(v) \Lambda $
.
- 
(ii) A covering  $p:\Sigma \to \Lambda $
 is said to be connected if $p:\Sigma \to \Lambda $
 is said to be connected if $\Sigma $
 (and hence $\Sigma $
 (and hence $\Lambda $
) is connected. $\Lambda $
) is connected.
- 
(iii) If  $p: \Sigma \to \Lambda $
 and $p: \Sigma \to \Lambda $
 and $q : \Gamma \to \Lambda $
 are coverings, a morphism from $q : \Gamma \to \Lambda $
 are coverings, a morphism from $(\Sigma ,p)$
 to $(\Sigma ,p)$
 to $(\Gamma , q)$
 is a k-graph morphism $(\Gamma , q)$
 is a k-graph morphism $\phi : \Sigma \to \Gamma $
 such that $\phi : \Sigma \to \Gamma $
 such that $q \circ \phi = p$
. $q \circ \phi = p$
.
- 
(iv) A covering  $p : \Sigma \to \Lambda $
 is universal if it is connected in the sense of part (ii), and for every connected covering $p : \Sigma \to \Lambda $
 is universal if it is connected in the sense of part (ii), and for every connected covering $q : \Gamma \to \Lambda $
, there is a unique morphism $q : \Gamma \to \Lambda $
, there is a unique morphism ${\phi : (\Sigma ,p)\to (\Gamma ,q)}$
 in the sense of part (iii). ${\phi : (\Sigma ,p)\to (\Gamma ,q)}$
 in the sense of part (iii).
Example 2.15. Let 
 $\Lambda $
 be a k-graph, G a group,
$\Lambda $
 be a k-graph, G a group, 
 $c: \Lambda \to G$
 a
$c: \Lambda \to G$
 a 
 $1$
-cocycle and
$1$
-cocycle and 
 $G \times _c \Lambda $
 the skew product. There is a covering
$G \times _c \Lambda $
 the skew product. There is a covering 
 $p : G \times _c \Lambda \to \Lambda $
 given by
$p : G \times _c \Lambda \to \Lambda $
 given by 
 $p(g, \lambda ) = \lambda $
 [Reference Pask, Raeburn and Quigg33, Proposition 6.3]. The quotient
$p(g, \lambda ) = \lambda $
 [Reference Pask, Raeburn and Quigg33, Proposition 6.3]. The quotient 
 $G \backslash (G \times _c \Lambda )$
 by translation in G is a k-graph, and p descends to an isomorphism
$G \backslash (G \times _c \Lambda )$
 by translation in G is a k-graph, and p descends to an isomorphism 
 $\tilde {p} : G \backslash (G \times _c \Lambda ) \to \Lambda $
.
$\tilde {p} : G \backslash (G \times _c \Lambda ) \to \Lambda $
.
Theorem 2.16 [Reference Bridson and Haefliger6, Proposition A.19], [Reference Pask, Raeburn and Quigg33, Theorem 2.7].
 Every connected k-graph 
 $\Lambda $
 has a universal covering. A connected covering
$\Lambda $
 has a universal covering. A connected covering 
 $p :\Sigma \to \Lambda $
 is universal if and only if the induced homomorphism
$p :\Sigma \to \Lambda $
 is universal if and only if the induced homomorphism 
 $p_*: \pi _1(\Sigma ,v) \to \pi _1 (\Lambda , p(w))$
 given by
$p_*: \pi _1(\Sigma ,v) \to \pi _1 (\Lambda , p(w))$
 given by 
 $p_* ( [\gamma ] ) = [p(\gamma )]$
 is the trivial homomorphism for some, and hence every,
$p_* ( [\gamma ] ) = [p(\gamma )]$
 is the trivial homomorphism for some, and hence every, 
 $v\in \Sigma ^0$
.
$v\in \Sigma ^0$
.
2.3 Simply connected k-graphs
Definition 2.17. A k-graph 
 $\Lambda $
 is simply connected if
$\Lambda $
 is simply connected if 
 $\pi _1(\Lambda , v)$
 is trivial for every
$\pi _1(\Lambda , v)$
 is trivial for every 
 ${v \in \Lambda ^0}$
.
${v \in \Lambda ^0}$
.
Theorem 2.18 [Reference Pask, Raeburn and Quigg33, Corollaries 5.5 and 6.5].
 Let 
 $\Lambda $
 be a connected k-graph.
$\Lambda $
 be a connected k-graph. 
- 
(i) A connected covering  $p : \Sigma \to \Lambda $
 is universal if and only if $p : \Sigma \to \Lambda $
 is universal if and only if $\,\Sigma $
 is simply connected. $\,\Sigma $
 is simply connected.
- 
(ii) Given  $v \in \Lambda ^0$
, there exists a cocycle $v \in \Lambda ^0$
, there exists a cocycle $\eta : \Lambda \to \pi _1 (\Lambda , v)$
 for which the skew-product covering $\eta : \Lambda \to \pi _1 (\Lambda , v)$
 for which the skew-product covering $p : \pi _1(\Lambda , v) \times _\eta \Lambda \to \Lambda $
 of Example 2.15 is a universal covering. $p : \pi _1(\Lambda , v) \times _\eta \Lambda \to \Lambda $
 of Example 2.15 is a universal covering.
We can characterise simply connected k-graphs using either fundamental groupoids or 
 $1$
-cocycles.
$1$
-cocycles.
Lemma 2.19. Let 
 $\Lambda $
 be a connected k-graph. Then the following are equivalent:
$\Lambda $
 be a connected k-graph. Then the following are equivalent: 
- 
(i)  $\Lambda $
 is simply connected; $\Lambda $
 is simply connected;
- 
(ii)  $\gamma \mapsto (r(\gamma ), s(\gamma ))$
 is an isomorphism $\gamma \mapsto (r(\gamma ), s(\gamma ))$
 is an isomorphism $\Pi (\Lambda ) \cong T(\Lambda ^0)$
; and $\Pi (\Lambda ) \cong T(\Lambda ^0)$
; and
- 
(iii) for every group G, every  $1$
-cocycle $1$
-cocycle $c : \Lambda \to G$
 is a coboundary in the sense that there is a function $c : \Lambda \to G$
 is a coboundary in the sense that there is a function $b : \Lambda ^0 \to G$
 such that $b : \Lambda ^0 \to G$
 such that $b(r(\lambda )) c(\lambda ) = b(s(\lambda ))$
. $b(r(\lambda )) c(\lambda ) = b(s(\lambda ))$
.
Proof. (i)
 $\,\Rightarrow \,$
(ii). If
$\,\Rightarrow \,$
(ii). If 
 $\Lambda $
 is simply connected, then by definition,
$\Lambda $
 is simply connected, then by definition, 
 $\pi _1(\Lambda , v)$
 is trivial for all v, so Remark 2.13 gives item (ii).
$\pi _1(\Lambda , v)$
 is trivial for all v, so Remark 2.13 gives item (ii).
 (ii)
 $\,\Rightarrow \,$
(iii). Suppose that
$\,\Rightarrow \,$
(iii). Suppose that 
 $\Pi (\Lambda ) = T(\Lambda ^0)$
 and fix a
$\Pi (\Lambda ) = T(\Lambda ^0)$
 and fix a 
 $1$
-cocycle
$1$
-cocycle 
 $c : \Lambda \to G$
. By the universal property of
$c : \Lambda \to G$
. By the universal property of 
 $\Pi (\Lambda )$
, there is a homomorphism
$\Pi (\Lambda )$
, there is a homomorphism 
 $\tilde {c} : T(\Lambda ^0) \to G$
 that extends c (that is,
$\tilde {c} : T(\Lambda ^0) \to G$
 that extends c (that is, 
 $c = \tilde {c}\circ {i}$
). Fix
$c = \tilde {c}\circ {i}$
). Fix 
 $v \in \Lambda ^0$
. Define
$v \in \Lambda ^0$
. Define 
 $b : \Lambda ^0 \to G$
 by
$b : \Lambda ^0 \to G$
 by 
 $b(w) = \tilde {c}(v,w)$
. For each
$b(w) = \tilde {c}(v,w)$
. For each 
 $\lambda \in \Lambda $
,
$\lambda \in \Lambda $
, 
 $$ \begin{align*} c(\lambda) = \tilde{c}(r(\lambda), s(\lambda)) = \tilde{c}((r(\lambda), v) (v, s(\lambda))) = b(r(\lambda))^{-1} b(s(\lambda)), \end{align*} $$
$$ \begin{align*} c(\lambda) = \tilde{c}(r(\lambda), s(\lambda)) = \tilde{c}((r(\lambda), v) (v, s(\lambda))) = b(r(\lambda))^{-1} b(s(\lambda)), \end{align*} $$
giving 
 $b(r(\lambda )) c(\lambda ) = b(s(\lambda ))$
.
$b(r(\lambda )) c(\lambda ) = b(s(\lambda ))$
.
 (iii)
 $\,\Rightarrow \,$
(i). Suppose that every
$\,\Rightarrow \,$
(i). Suppose that every 
 $1$
-cocycle on
$1$
-cocycle on 
 $\Lambda $
 is a coboundary. Fix
$\Lambda $
 is a coboundary. Fix 
 $v \in \Lambda ^0$
. As in Remark 2.13, for each
$v \in \Lambda ^0$
. As in Remark 2.13, for each 
 $w \in \Lambda ^0 \setminus \{v\}$
, fix
$w \in \Lambda ^0 \setminus \{v\}$
, fix 
 $\gamma _w \in \Pi (\Lambda )^w_v$
, put
$\gamma _w \in \Pi (\Lambda )^w_v$
, put 
 $\gamma _v = v$
 and define
$\gamma _v = v$
 and define 
 $\kappa : \Lambda \to \pi _1(\Lambda , v)$
 by
$\kappa : \Lambda \to \pi _1(\Lambda , v)$
 by 
 $\kappa (\lambda ) = \gamma _{r(\lambda )}^{-1} i(\lambda )\gamma _{s(\lambda )}$
. Then
$\kappa (\lambda ) = \gamma _{r(\lambda )}^{-1} i(\lambda )\gamma _{s(\lambda )}$
. Then 
 $\kappa $
 is a
$\kappa $
 is a 
 $1$
-cocycle so there is a map
$1$
-cocycle so there is a map 
 ${b : \Lambda ^0 \to \pi (\Lambda , v)}$
 such that
${b : \Lambda ^0 \to \pi (\Lambda , v)}$
 such that 
 $\kappa (\lambda ) = b(r(\lambda ))^{-1}b(s(\lambda ))$
 for all
$\kappa (\lambda ) = b(r(\lambda ))^{-1}b(s(\lambda ))$
 for all 
 $\lambda $
. By the universal property of the fundamental groupoid,
$\lambda $
. By the universal property of the fundamental groupoid, 
 $\kappa $
 extends uniquely to a
$\kappa $
 extends uniquely to a 
 $1$
-cocycle
$1$
-cocycle 
 $\tilde {\kappa } : \Pi (\Lambda ) \to \pi _1(\Lambda , v)$
 (that is,
$\tilde {\kappa } : \Pi (\Lambda ) \to \pi _1(\Lambda , v)$
 (that is, 
 $\kappa = \tilde {\kappa }\circ {i}$
). By uniqueness, it follows that for all
$\kappa = \tilde {\kappa }\circ {i}$
). By uniqueness, it follows that for all 
 $\gamma \in \Pi (\Lambda )$
, we have
$\gamma \in \Pi (\Lambda )$
, we have 
 $$ \begin{align*} \gamma_{r(\gamma)}^{-1} \gamma\gamma_{s(\gamma)} = \tilde{\kappa}(\gamma) = b(r(\gamma))^{-1}b(s(\gamma)). \end{align*} $$
$$ \begin{align*} \gamma_{r(\gamma)}^{-1} \gamma\gamma_{s(\gamma)} = \tilde{\kappa}(\gamma) = b(r(\gamma))^{-1}b(s(\gamma)). \end{align*} $$
The first equation implies that the restriction of 
 $\tilde {\kappa }$
 to
$\tilde {\kappa }$
 to 
 $ \pi _1(\Lambda , v)$
 is the identity map and by the second equation, the restriction is trivial. Hence,
$ \pi _1(\Lambda , v)$
 is the identity map and by the second equation, the restriction is trivial. Hence, 
 $ \pi _1(\Lambda , v)$
 is trivial and so
$ \pi _1(\Lambda , v)$
 is trivial and so 
 $\Lambda $
 is simply connected.
$\Lambda $
 is simply connected.
2.4 The path groupoid 
 $\mathcal {G}_\Lambda $
 and the
$\mathcal {G}_\Lambda $
 and the 
 $C^*$
-algebra
$C^*$
-algebra 
 $C^*(\Lambda )$
$C^*(\Lambda )$
 Let 
 $\Lambda $
 be a row-finite source-free k-graph. The infinite path space
$\Lambda $
 be a row-finite source-free k-graph. The infinite path space 
 $\Lambda ^\infty $
 of
$\Lambda ^\infty $
 of 
 $\Lambda $
 is the space of k-graph morphisms
$\Lambda $
 is the space of k-graph morphisms 
 $x : \Omega _k \to \Lambda $
 under the locally compact Hausdorff topology with basic compact open sets
$x : \Omega _k \to \Lambda $
 under the locally compact Hausdorff topology with basic compact open sets 
 $Z(\lambda ) := \{ x \in \Lambda ^\infty : \lambda = x(0, d(\lambda )) \}$
, indexed by
$Z(\lambda ) := \{ x \in \Lambda ^\infty : \lambda = x(0, d(\lambda )) \}$
, indexed by 
 $\lambda \in \Lambda $
. For
$\lambda \in \Lambda $
. For 
 $p \in \mathbb {N}^k$
, the shift map
$p \in \mathbb {N}^k$
, the shift map 
 $\sigma ^p: \Lambda ^\infty \to \Lambda ^\infty $
 is defined by
$\sigma ^p: \Lambda ^\infty \to \Lambda ^\infty $
 is defined by 
 $\sigma ^px(m, n) = x(m+p, n+p)$
 for
$\sigma ^px(m, n) = x(m+p, n+p)$
 for 
 $x \in \Lambda ^\infty $
 and
$x \in \Lambda ^\infty $
 and 
 $(m, n) \in \Omega _k$
; and
$(m, n) \in \Omega _k$
; and 
 $p \mapsto \sigma ^p$
 is an action of
$p \mapsto \sigma ^p$
 is an action of 
 $\mathbb {N}^k$
 by local homeomorphisms.
$\mathbb {N}^k$
 by local homeomorphisms.
 Elements 
 $x, y \kern1.3pt{\in}\kern1.3pt \Lambda ^\infty $
 are shift equivalent, written
$x, y \kern1.3pt{\in}\kern1.3pt \Lambda ^\infty $
 are shift equivalent, written 
 $x \kern1.4pt{\simeq}\kern1.4pt y$
, if
$x \kern1.4pt{\simeq}\kern1.4pt y$
, if 
 $\sigma ^px \kern1.3pt{=}\kern1.3pt \sigma ^qy$
 for some
$\sigma ^px \kern1.3pt{=}\kern1.3pt \sigma ^qy$
 for some 
 ${p, q \kern1.3pt{\in}\kern1.3pt \mathbb {N}^k}$
. The path groupoid
${p, q \kern1.3pt{\in}\kern1.3pt \mathbb {N}^k}$
. The path groupoid 
 $\mathcal {G}_{\Lambda} $
 is the Deaconu–Renault groupoid of the action
$\mathcal {G}_{\Lambda} $
 is the Deaconu–Renault groupoid of the action 
 $p \mapsto \sigma ^p$
.
$p \mapsto \sigma ^p$
.
Definition 2.20 [Reference Kumjian and Pask26, Definition 2.7].
The path groupoid is
 $$ \begin{align*} \mathcal{G}_\Lambda := \{ (x, n, y) \in \Lambda^\infty \times \mathbb{Z} \times \Lambda^\infty : \sigma^\ell x = \sigma^my, n = \ell -m \}, \end{align*} $$
$$ \begin{align*} \mathcal{G}_\Lambda := \{ (x, n, y) \in \Lambda^\infty \times \mathbb{Z} \times \Lambda^\infty : \sigma^\ell x = \sigma^my, n = \ell -m \}, \end{align*} $$
with unit space 
 $\mathcal {G}_\Lambda ^0 = \{(x, 0, x) : x \in \Lambda ^\infty \}$
 identified with
$\mathcal {G}_\Lambda ^0 = \{(x, 0, x) : x \in \Lambda ^\infty \}$
 identified with 
 $\Lambda ^\infty $
, with structure maps
$\Lambda ^\infty $
, with structure maps 
 $$ \begin{align*} r(x, n, y) = x, \quad s(x, n, y) = y, \quad (x, n, y)(y, \ell, z) = (x, n+\ell, z), \quad (x, n, y)^{-1} = (y, -n, x), \end{align*} $$
$$ \begin{align*} r(x, n, y) = x, \quad s(x, n, y) = y, \quad (x, n, y)(y, \ell, z) = (x, n+\ell, z), \quad (x, n, y)^{-1} = (y, -n, x), \end{align*} $$
and under the topology with basic open sets
 $$ \begin{align*} Z(\mu ,\nu ) = \{(\mu x, d(\mu ) - d(\nu ), \nu x) : x \in Z(s(\mu ))\} \end{align*} $$
$$ \begin{align*} Z(\mu ,\nu ) = \{(\mu x, d(\mu ) - d(\nu ), \nu x) : x \in Z(s(\mu ))\} \end{align*} $$
indexed by pairs 
 $(\mu ,\nu ) \in \Lambda \times \Lambda $
 such that
$(\mu ,\nu ) \in \Lambda \times \Lambda $
 such that 
 $s(\mu ) = s(\nu )$
.
$s(\mu ) = s(\nu )$
.
 The 
 $C^*$
-algebra of
$C^*$
-algebra of 
 $\Lambda $
 is defined via generators and relations.
$\Lambda $
 is defined via generators and relations.
Definition 2.21 [Reference Kumjian and Pask26, Definition 1.5].
 A family of partial isometries 
 $\{ s_\lambda : \lambda \in \Lambda \}$
 is a Cuntz–Krieger
$\{ s_\lambda : \lambda \in \Lambda \}$
 is a Cuntz–Krieger 
 $\Lambda $
-family if:
$\Lambda $
-family if: 
- 
(CK1)  $\{ s_v : v \in \Lambda ^0\}$
 is a collection of mutually orthogonal projections; $\{ s_v : v \in \Lambda ^0\}$
 is a collection of mutually orthogonal projections;
- 
(CK2)  $s_{\lambda \mu } = s_{\lambda }s_\mu $
 for all $s_{\lambda \mu } = s_{\lambda }s_\mu $
 for all $\lambda , \mu \in \Lambda $
 such that $\lambda , \mu \in \Lambda $
 such that $s(\lambda ) = r(\mu )$
; $s(\lambda ) = r(\mu )$
;
- 
(CK3)  $s_{\lambda }^*s_{\lambda } = s_{s(\lambda )}$
 for all $s_{\lambda }^*s_{\lambda } = s_{s(\lambda )}$
 for all $\lambda \in \Lambda $
; and $\lambda \in \Lambda $
; and
- 
(CK4) for all  $v \in \Lambda ^0$
 and $v \in \Lambda ^0$
 and $n \in \mathbb {N}^k$
, we have $n \in \mathbb {N}^k$
, we have $s_v = \sum _{\lambda \in v\Lambda ^n} s_{\lambda }s_{\lambda }^*$
. $s_v = \sum _{\lambda \in v\Lambda ^n} s_{\lambda }s_{\lambda }^*$
.
We write 
 $C^*(\Lambda )$
 for the universal
$C^*(\Lambda )$
 for the universal 
 $C^*$
-algebra generated by a Cuntz–Krieger
$C^*$
-algebra generated by a Cuntz–Krieger 
 $\Lambda $
-family
$\Lambda $
-family 
 $\{ s_\lambda : \lambda \in \Lambda \}$
.
$\{ s_\lambda : \lambda \in \Lambda \}$
.
 The groupoid 
 $\mathcal {G}_\Lambda $
 is étale [Reference Kumjian and Pask26, Proposition 2.8], and [Reference Kumjian and Pask26, Corollary 3.5(i)] says that
$\mathcal {G}_\Lambda $
 is étale [Reference Kumjian and Pask26, Proposition 2.8], and [Reference Kumjian and Pask26, Corollary 3.5(i)] says that 
 $C^*(\Lambda) \cong C^*(\mathcal{G}_\Lambda)$
.
$C^*(\Lambda) \cong C^*(\mathcal{G}_\Lambda)$
.
3 Embedding results for higher-rank graphs
 In this section, we develop tools for determining when a k-graph 
 $\Lambda $
 embeds in
$\Lambda $
 embeds in 
 $\Pi (\Lambda )$
, and describe classes of examples that do embed; we also present three examples—one from [Reference Pask, Raeburn and Quigg32], one due to Ben Steinberg and one that is new—that do not embed.
$\Pi (\Lambda )$
, and describe classes of examples that do embed; we also present three examples—one from [Reference Pask, Raeburn and Quigg32], one due to Ben Steinberg and one that is new—that do not embed.
3.1 Nonembeddings
 Even a fairly elementary monoidal 
 $2$
-graph
$2$
-graph 
 $\Lambda $
 need not embed in
$\Lambda $
 need not embed in 
 $\Pi (\Lambda )$
.
$\Pi (\Lambda )$
.
Example 3.1 [Reference Pask, Raeburn and Quigg32, Example 7.1].
 Let 
 $\Lambda $
 be the 1-vertex
$\Lambda $
 be the 1-vertex 
 $2$
-graph with
$2$
-graph with 
 $\Lambda ^{\varepsilon _1} = \{ d, e \}$
 and
$\Lambda ^{\varepsilon _1} = \{ d, e \}$
 and 
 $\Lambda ^{\varepsilon _2} = \{ a,b,c \}$
 such that
$\Lambda ^{\varepsilon _2} = \{ a,b,c \}$
 such that 
 $$ \begin{align} da = ad,\quad db = be,\quad dc = ae,\quad ea = cd,\quad eb = ce,\quad ec = bd. \end{align} $$
$$ \begin{align} da = ad,\quad db = be,\quad dc = ae,\quad ea = cd,\quad eb = ce,\quad ec = bd. \end{align} $$
Using the first four relations from (3-1) and that the map 
 $i : \Lambda \to \Pi (\Lambda )$
 is a morphism, we obtain
$i : \Lambda \to \Pi (\Lambda )$
 is a morphism, we obtain 
 $$ \begin{align*} i(a) = i(d) i(a) i(d)^{-1} &= i(d)i(e)^{-1}i(c) = i(d)i(b)i(e)^{-1} = i(b), \end{align*} $$
$$ \begin{align*} i(a) = i(d) i(a) i(d)^{-1} &= i(d)i(e)^{-1}i(c) = i(d)i(b)i(e)^{-1} = i(b), \end{align*} $$
so 
 $i(a)=i(b)$
 in
$i(a)=i(b)$
 in 
 $\Pi ( \Lambda )$
. The fifth equation in (3-1) gives
$\Pi ( \Lambda )$
. The fifth equation in (3-1) gives 
 $i(d)=i(e)$
, so equations two and five give
$i(d)=i(e)$
, so equations two and five give 
 $i(b)=i(c)$
. Hence,
$i(b)=i(c)$
. Hence, 
 $i(a)=i(b) = i(c)$
 and
$i(a)=i(b) = i(c)$
 and 
 $i(d) = i(e)$
. The degree map descends to an isomorphism
$i(d) = i(e)$
. The degree map descends to an isomorphism 
 $\tilde {d} : \Pi ( \Lambda ) \to \mathbb {Z}^2$
; so the universal cover of
$\tilde {d} : \Pi ( \Lambda ) \to \mathbb {Z}^2$
; so the universal cover of 
 $\Lambda $
 is isomorphic to
$\Lambda $
 is isomorphic to 
 ${\mathbb {Z}^2 \times _d \Lambda }$
.
${\mathbb {Z}^2 \times _d \Lambda }$
.
 The next example, shown to us by Ben Steinberg, who attributes the idea to Mal’cev [Reference Mal’cev30, §2] (see also [Reference Lawson and Vdovina29, Example 11.13]), is a monoidal 
 $2$
-graph that does not embed even though its edge-set does.
$2$
-graph that does not embed even though its edge-set does.
Example 3.2 (Steinberg, private communication).
 Let 
 $\Lambda $
 be the unique
$\Lambda $
 be the unique 
 $1$
-vertex
$1$
-vertex 
 $2$
-graph with
$2$
-graph with 
 $\Lambda ^{\varepsilon _1} = \{ e_1, e_2, e_3, e_4 \}$
 and
$\Lambda ^{\varepsilon _1} = \{ e_1, e_2, e_3, e_4 \}$
 and 
 $\Lambda ^{\varepsilon _2} = \{ f_1, f_2, f_3, f_4 \}$
, and such that
$\Lambda ^{\varepsilon _2} = \{ f_1, f_2, f_3, f_4 \}$
, and such that 
 $$ \begin{align} e_af_b := \begin{cases} f_be_a & \text{if } (a, b) = (1, 4), (4, 1); \\ f_ae_b & \text{otherwise.} \end{cases} \end{align} $$
$$ \begin{align} e_af_b := \begin{cases} f_be_a & \text{if } (a, b) = (1, 4), (4, 1); \\ f_ae_b & \text{otherwise.} \end{cases} \end{align} $$
Since 
 $i : \Lambda \to \Pi (\Lambda )$
 is a functor,
$i : \Lambda \to \Pi (\Lambda )$
 is a functor, 
 $i(e_a)^{-1}i(f_a) = i(f_b)i(e_b)^{-1}$
 for
$i(e_a)^{-1}i(f_a) = i(f_b)i(e_b)^{-1}$
 for 
 $(a, b) = (1,2), (2,3), (3,4)$
, so
$(a, b) = (1,2), (2,3), (3,4)$
, so 
 $$ \begin{align*} i( e_1 )^{-1} i ( f_1) = i( f_2 ) i ( e_2 )^{-1} = i( e_3 )^{-1} i ( f_3) = i ( f_4 ) i (e_4 )^{-1}, \end{align*} $$
$$ \begin{align*} i( e_1 )^{-1} i ( f_1) = i( f_2 ) i ( e_2 )^{-1} = i( e_3 )^{-1} i ( f_3) = i ( f_4 ) i (e_4 )^{-1}, \end{align*} $$
and then rearranging the outer terms gives
 $$ \begin{align*} i(f_1e_4) = i(f_1) i(e_4) = i(f_4) i (e_1) = i(f_4e_1). \end{align*} $$
$$ \begin{align*} i(f_1e_4) = i(f_1) i(e_4) = i(f_4) i (e_1) = i(f_4e_1). \end{align*} $$
Uniqueness of factorisations in 
 $\Lambda $
 shows that
$\Lambda $
 shows that 
 $f_1e_4 \not = f_4e_1$
, so i is not injective.
$f_1e_4 \not = f_4e_1$
, so i is not injective.
 We show that i is injective on 
 $\Lambda ^{\varepsilon _1} \cup \Lambda ^{\varepsilon _2}$
. For this, define
$\Lambda ^{\varepsilon _1} \cup \Lambda ^{\varepsilon _2}$
. For this, define 
 $c : \Lambda ^{\varepsilon _1} \cup \Lambda ^{\varepsilon _2} \to \mathbb {Z}$
 by
$c : \Lambda ^{\varepsilon _1} \cup \Lambda ^{\varepsilon _2} \to \mathbb {Z}$
 by 
 $c(e_j) = c(f_j) = j$
 for
$c(e_j) = c(f_j) = j$
 for 
 $j=1, \ldots , 4$
. Since c respects (3-2), it extends to a functor
$j=1, \ldots , 4$
. Since c respects (3-2), it extends to a functor 
 ${c : \Lambda \to \mathbb {Z}}$
. By Definition 2.9, there is a functor
${c : \Lambda \to \mathbb {Z}}$
. By Definition 2.9, there is a functor 
 $\tilde {c} : \Pi (\Lambda ) \to \mathbb {Z}$
 such that
$\tilde {c} : \Pi (\Lambda ) \to \mathbb {Z}$
 such that 
 $\tilde {c} \circ i = c$
. In particular,
$\tilde {c} \circ i = c$
. In particular, 
 $\tilde {c}(i(e_j)) = j = \tilde {c}(i(f_j))$
 for all j. Hence,
$\tilde {c}(i(e_j)) = j = \tilde {c}(i(f_j))$
 for all j. Hence, 
 $(\tilde {c} \times \tilde {d}) \circ i : (\Lambda ^{\varepsilon _1} \cup \Lambda ^{\varepsilon _2}) \to \mathbb {Z}^2$
 is injective. Thus, i is injective on
$(\tilde {c} \times \tilde {d}) \circ i : (\Lambda ^{\varepsilon _1} \cup \Lambda ^{\varepsilon _2}) \to \mathbb {Z}^2$
 is injective. Thus, i is injective on 
 $\Lambda ^{\varepsilon _1} \cup \Lambda ^{\varepsilon _2}$
.
$\Lambda ^{\varepsilon _1} \cup \Lambda ^{\varepsilon _2}$
.
Example 3.3. For readers looking at this paper in monochrome, in the following example we refer to solid edges as blue, dashed edges as red, and dot-dashed edges as green. By [Reference Hazlewood, Raeburn, Sims and Webster19, Theorems 4.4 and 4.5], there is a unique 
 $3$
-graph
$3$
-graph 
 $\Gamma $
 with the skeleton and factorisation rules below (there are no 3-coloured paths, so the associativity condition is vacuous).
$\Gamma $
 with the skeleton and factorisation rules below (there are no 3-coloured paths, so the associativity condition is vacuous). 

By Proposition 3.12(ii) below, the 2-coloured sub-
 $2$
-graphs of
$2$
-graphs of 
 $\Gamma $
 are all embeddable: the
$\Gamma $
 are all embeddable: the 
 $\mathbb {Z}$
-valued cocycle on the blue–red graph carrying
$\mathbb {Z}$
-valued cocycle on the blue–red graph carrying 
 $\{f_i : i \le 4\}$
 to
$\{f_i : i \le 4\}$
 to 
 $1$
 and all other edges to
$1$
 and all other edges to 
 $0$
 is essential (see Definition 3.10); the
$0$
 is essential (see Definition 3.10); the 
 $\mathbb {Z}$
-valued cocycle on the red–green graph carrying
$\mathbb {Z}$
-valued cocycle on the red–green graph carrying 
 $\{f_1\}\cup \{f^{\prime }_i : i \ge 2\}$
 to
$\{f_1\}\cup \{f^{\prime }_i : i \ge 2\}$
 to 
 $1$
 and all other edges to
$1$
 and all other edges to 
 $0$
 is essential; and the trivial cocycle on the blue–green graph is essential.
$0$
 is essential; and the trivial cocycle on the blue–green graph is essential.
 However, 
 $\Gamma $
 does not embed in
$\Gamma $
 does not embed in 
 $\Pi (\Gamma )$
: writing
$\Pi (\Gamma )$
: writing 
 $[x]$
 for
$[x]$
 for 
 $i(x) \in \Pi (\Lambda )$
, we calculate:
$i(x) \in \Pi (\Lambda )$
, we calculate: 
 $$ \begin{align*}[f_1'] [g_1]^{-1} &= [g_3]^{-1}[f_3] = [f_2] [g_2]^{-1} = [f_2] [e_2]^{-1} [e_2] [g_2]^{-1} = [e_3]^{-1}[f_4] [g_4]^{-1}[e_4] \\ &= [e_3]^{-1}[f_4][e_1][e_1]^{-1} [g_4]^{-1}[e_4]\\ &= [e_3]^{-1}[e_3][f_1][g_1]^{-1} [e_4]^{-1}[e_4] = [f_1] [g_1]^{-1}. \end{align*} $$
$$ \begin{align*}[f_1'] [g_1]^{-1} &= [g_3]^{-1}[f_3] = [f_2] [g_2]^{-1} = [f_2] [e_2]^{-1} [e_2] [g_2]^{-1} = [e_3]^{-1}[f_4] [g_4]^{-1}[e_4] \\ &= [e_3]^{-1}[f_4][e_1][e_1]^{-1} [g_4]^{-1}[e_4]\\ &= [e_3]^{-1}[e_3][f_1][g_1]^{-1} [e_4]^{-1}[e_4] = [f_1] [g_1]^{-1}. \end{align*} $$
So cancellation gives 
 $[f_1'] = [f_1]$
. We then have
$[f_1'] = [f_1]$
. We then have 
 $[f^{\prime }_3] = [g_3][f_1][g_1]^{-1} = [g_3][f^{\prime }_1] [g_1]^{-1} = [f_3]$
 and
$[f^{\prime }_3] = [g_3][f_1][g_1]^{-1} = [g_3][f^{\prime }_1] [g_1]^{-1} = [f_3]$
 and 
 $[f^{\prime }_4] = [e_3][f^{\prime }_1][e_1]^{-1} = [e_3][f_1][e_1]^{-1} = [f_4]$
, and then also
$[f^{\prime }_4] = [e_3][f^{\prime }_1][e_1]^{-1} = [e_3][f_1][e_1]^{-1} = [f_4]$
, and then also 
 ${[f^{\prime }_2] = [e_3]^{-1} [f^{\prime }_4][e_2] = [e_3]^{-1} [f_4][e_2] = [f_2]}$
.
${[f^{\prime }_2] = [e_3]^{-1} [f^{\prime }_4][e_2] = [e_3]^{-1} [f_4][e_2] = [f_2]}$
.
 Motivated by these examples, we seek conditions under which 
 $i : \Lambda \to \Pi (\Lambda )$
 is injective.
$i : \Lambda \to \Pi (\Lambda )$
 is injective.
3.2 Embedding singly connected higher-rank graphs
Definition 3.4. A k-graph 
 $\Lambda $
 is singly connected if there is at most one path between any two vertices; that is, for all
$\Lambda $
 is singly connected if there is at most one path between any two vertices; that is, for all 
 $u,v \in \Lambda ^0$
, we have
$u,v \in \Lambda ^0$
, we have 
 $| u {\Lambda }v | \le 1$
.
$| u {\Lambda }v | \le 1$
.
Singly connected k-graphs need not be connected. The vertex set of a singly connected k-graph is partially ordered by the relation 
 $\le $
 given by
$\le $
 given by 
 $u \le v$
 if and only if
$u \le v$
 if and only if 
 $u \Lambda v \neq \emptyset $
.
$u \Lambda v \neq \emptyset $
.
Example 3.5. Write 
 $\{ t_i : i=1 , \ldots , n\}$
 for the generators of the free group
$\{ t_i : i=1 , \ldots , n\}$
 for the generators of the free group 
 $\mathbb {F}_n$
. Let
$\mathbb {F}_n$
. Let 
 $c :B_n \to \mathbb {F}_n$
 be the
$c :B_n \to \mathbb {F}_n$
 be the 
 $1$
-cocycle such that
$1$
-cocycle such that 
 $c(f_i) = t_i$
 for all i. Then
$c(f_i) = t_i$
 for all i. Then 
 $\mathbb {F}_n \times _c B_n$
 is singly connected.
$\mathbb {F}_n \times _c B_n$
 is singly connected.
There is a relationship between singly connected k-graphs and the simply connected k-graphs of Section 2.3, though neither condition implies the other.
Proposition 3.6. Let 
 $\Lambda $
 be a connected k-graph and suppose that
$\Lambda $
 be a connected k-graph and suppose that 
 $i : \Lambda \to \Pi (\Lambda )$
 is injective. If
$i : \Lambda \to \Pi (\Lambda )$
 is injective. If 
 $\Lambda $
 is simply connected, then it is singly connected.
$\Lambda $
 is simply connected, then it is singly connected.
Proof. Suppose that 
 $\Lambda $
 is not singly connected. Then there exist distinct elements
$\Lambda $
 is not singly connected. Then there exist distinct elements 
 $\lambda , \mu \in \Lambda $
 such that
$\lambda , \mu \in \Lambda $
 such that 
 $s(\lambda ) = s(\mu )$
 and
$s(\lambda ) = s(\mu )$
 and 
 $r(\lambda ) = r(\mu )$
. Since
$r(\lambda ) = r(\mu )$
. Since 
 $i : \Lambda \to \Pi (\Lambda )$
 is injective,
$i : \Lambda \to \Pi (\Lambda )$
 is injective, 
 ${i(\lambda ) \ne i(\mu )}$
 and thus
${i(\lambda ) \ne i(\mu )}$
 and thus 
 $i(\lambda )^{-1}i(\mu ) \in \pi _1 (\Lambda , s(\lambda )) \backslash \{ s(\lambda )\}$
. Hence,
$i(\lambda )^{-1}i(\mu ) \in \pi _1 (\Lambda , s(\lambda )) \backslash \{ s(\lambda )\}$
. Hence, 
 $\Lambda $
 is not simply connected.
$\Lambda $
 is not simply connected.
The reverse implication fails, as the following example illustrates.
Example 3.7. Let E be the directed graph with 
 $E^0=\{u, v, w, x\}$
 and
$E^0=\{u, v, w, x\}$
 and 
 $E^1= \{ e, f, g, h \}$
 such that
$E^1= \{ e, f, g, h \}$
 such that 
 $s(e) = u = s(f)$
,
$s(e) = u = s(f)$
, 
 $s(g) = w = s(h)$
,
$s(g) = w = s(h)$
, 
 $r(e) = v = r(h)$
 and
$r(e) = v = r(h)$
 and 
 $r(f) = x = r(g)$
. Then the
$r(f) = x = r(g)$
. Then the 
 $1$
-graph
$1$
-graph 
 $E^*$
 is a singly connected
$E^*$
 is a singly connected 
 $1$
-graph that is not simply connected since
$1$
-graph that is not simply connected since 
 $\pi _1(E^*, u) \cong \mathbb {Z}$
. Adding tails at both u and w as in [Reference Bates, Pask, Raeburn and Szymański4, Lemma 1.2] yields a source-free
$\pi _1(E^*, u) \cong \mathbb {Z}$
. Adding tails at both u and w as in [Reference Bates, Pask, Raeburn and Szymański4, Lemma 1.2] yields a source-free 
 $1$
-graph with the same property.
$1$
-graph with the same property.
We use the next theorem, which exploits the universal property of the fundamental groupoid from Section 2.2, to show that singly connected k-graphs embed in their fundamental groupoids.
Theorem 3.8. Let 
 $\Lambda $
 be a k-graph and let
$\Lambda $
 be a k-graph and let 
 $\mathcal {G}$
 be a groupoid. If there is an injective functor
$\mathcal {G}$
 be a groupoid. If there is an injective functor 
 $F : \Lambda \to \mathcal {G}$
, then
$F : \Lambda \to \mathcal {G}$
, then 
 $i : \Lambda \to \Pi (\Lambda )$
 is injective.
$i : \Lambda \to \Pi (\Lambda )$
 is injective.
Proof. The universal property of the fundamental groupoid yields a homomorphism 
 $\tilde {F} : \Pi (\Lambda ) \to \mathcal {G}$
 such that
$\tilde {F} : \Pi (\Lambda ) \to \mathcal {G}$
 such that 
 $F = \tilde {F} \circ i$
. Hence, if F is injective, then i is injective.
$F = \tilde {F} \circ i$
. Hence, if F is injective, then i is injective.
Proposition 3.9. Let 
 $\Lambda $
 be a connected k-graph. Then:
$\Lambda $
 be a connected k-graph. Then: 
- 
(i) the canonical map  $\iota : \Lambda \to T(\Lambda ^0)$
 is injective if and only if $\iota : \Lambda \to T(\Lambda ^0)$
 is injective if and only if $\Lambda $
 is singly connected; $\Lambda $
 is singly connected;
- 
(ii) if  $\Lambda $
 is singly connected, then $\Lambda $
 is singly connected, then $i : \Lambda \to \Pi (\Lambda )$
 is injective. $i : \Lambda \to \Pi (\Lambda )$
 is injective.
Proof. The first assertion follows by definition and the second follows from Theorem 3.8.
 Theorem 3.8 also allows us to deduce embeddability from the existence of a suitable 
 $1$
-cocycle.
$1$
-cocycle.
Definition 3.10. Let 
 $\Lambda $
 be a k-graph, G a countable group and
$\Lambda $
 be a k-graph, G a countable group and 
 $c : \Lambda \to G$
 a 1-cocycle. We say that c is essential if the restriction of c to
$c : \Lambda \to G$
 a 1-cocycle. We say that c is essential if the restriction of c to 
 $u{\Lambda }v$
 is injective for all
$u{\Lambda }v$
 is injective for all 
 $u, v \in \Lambda ^0$
.
$u, v \in \Lambda ^0$
.
Example 3.11. The 
 $1$
-cocycle
$1$
-cocycle 
 $c : B_n \to \mathbb {F}_n$
 described in Example 3.5 is essential.
$c : B_n \to \mathbb {F}_n$
 described in Example 3.5 is essential.
Proposition 3.12. Let 
 $\Lambda $
 be a connected k-graph and let
$\Lambda $
 be a connected k-graph and let 
 $v \in \Lambda ^0$
. Then the following are equivalent:
$v \in \Lambda ^0$
. Then the following are equivalent: 
- 
(i) the  $1$
-cocycle $1$
-cocycle $\kappa : \Lambda \to \pi _1(\Lambda , v)$
 given in Remark 2.13 is essential; $\kappa : \Lambda \to \pi _1(\Lambda , v)$
 given in Remark 2.13 is essential;
- 
(ii)  $\Lambda $
 admits an essential cocycle $\Lambda $
 admits an essential cocycle $c : \Lambda \to G$
 to a group G; and $c : \Lambda \to G$
 to a group G; and
- 
(iii)  $i : \Lambda \to \Pi (\Lambda )$
 is injective. $i : \Lambda \to \Pi (\Lambda )$
 is injective.
For any essential cocycle 
 $c : \Lambda \to G$
 as in part (ii),
$c : \Lambda \to G$
 as in part (ii), 
 $G \times _c \Lambda $
 is singly connected.
$G \times _c \Lambda $
 is singly connected.
Proof. The implication (i) 
 $\implies $
 (ii) is obvious.
$\implies $
 (ii) is obvious.
 For (ii) 
 $\implies $
 (iii), suppose that
$\implies $
 (iii), suppose that 
 $c : \Lambda \to G$
 is an essential cocycle into a group. Note that
$c : \Lambda \to G$
 is an essential cocycle into a group. Note that 
 $G \times T(\Lambda ^0)$
 is a groupoid. Define
$G \times T(\Lambda ^0)$
 is a groupoid. Define 
 $j : \Lambda \to G \times T(\Lambda ^0)$
 by
$j : \Lambda \to G \times T(\Lambda ^0)$
 by 
 $j(\lambda ) := (c(\lambda ), (r(\lambda ), s(\lambda )))$
; then j is a functor. Since c is essential, j is injective, so
$j(\lambda ) := (c(\lambda ), (r(\lambda ), s(\lambda )))$
; then j is a functor. Since c is essential, j is injective, so 
 $i : \Lambda \to \Pi (\Lambda )$
 is injective by Theorem 3.8.
$i : \Lambda \to \Pi (\Lambda )$
 is injective by Theorem 3.8.
 For (iii) 
 $\implies $
 (i), suppose that
$\implies $
 (i), suppose that 
 $i : \Lambda \to \Pi (\Lambda )$
 is injective. Recall that by Remark 2.13,
$i : \Lambda \to \Pi (\Lambda )$
 is injective. Recall that by Remark 2.13, 
 $(\kappa (\lambda ), (r(\lambda ), s(\lambda ))) = (\phi _\gamma \circ {i})(\lambda )$
 for all
$(\kappa (\lambda ), (r(\lambda ), s(\lambda ))) = (\phi _\gamma \circ {i})(\lambda )$
 for all 
 $\lambda \in \Lambda $
. Hence,
$\lambda \in \Lambda $
. Hence, 
 $\kappa $
 is essential, since
$\kappa $
 is essential, since 
 $\phi _\gamma \circ i$
 is injective.
$\phi _\gamma \circ i$
 is injective.
 For the final statement, suppose that 
 $c : \Lambda \to G$
 is essential, and that
$c : \Lambda \to G$
 is essential, and that 
 ${r(g, \lambda ) = r(h,\mu )}$
 and
${r(g, \lambda ) = r(h,\mu )}$
 and 
 $s(g,\lambda ) = s(h,\mu )$
 in
$s(g,\lambda ) = s(h,\mu )$
 in 
 $G \times _c \Lambda $
. Then
$G \times _c \Lambda $
. Then 
 $$ \begin{align*} (g, r(\lambda)) &= r(g,\lambda) = r(h, \mu) = (h, r(\mu)) \quad \text{and} \\ (c(\lambda) g, s(\lambda)) &= s(g,\lambda) = s(h,\mu) = (c(\mu) h, s(\mu)). \end{align*} $$
$$ \begin{align*} (g, r(\lambda)) &= r(g,\lambda) = r(h, \mu) = (h, r(\mu)) \quad \text{and} \\ (c(\lambda) g, s(\lambda)) &= s(g,\lambda) = s(h,\mu) = (c(\mu) h, s(\mu)). \end{align*} $$
So 
 $r(\lambda ) = r(\mu )$
,
$r(\lambda ) = r(\mu )$
, 
 $s(\lambda ) = s(\mu )$
,
$s(\lambda ) = s(\mu )$
, 
 $g = h$
 and
$g = h$
 and 
 $c(\lambda )g = c(\mu )h$
. These last two equalities give
$c(\lambda )g = c(\mu )h$
. These last two equalities give 
 $c(\lambda ) = c(\mu )$
. Thus,
$c(\lambda ) = c(\mu )$
. Thus, 
 $j(\lambda ) = j(\mu )$
 and hence
$j(\lambda ) = j(\mu )$
 and hence 
 $\lambda = \mu $
. Therefore,
$\lambda = \mu $
. Therefore, 
 $(g, \lambda ) = (h,\mu )$
 and so
$(g, \lambda ) = (h,\mu )$
 and so 
 $G \times _c \Lambda $
 is singly connected.
$G \times _c \Lambda $
 is singly connected.
3.3 More general embedding results
In this section, we investigate embeddability of k-graphs that are not singly connected. We start with one of the most useful results in our toolkit, which relies on the universal property of the fundamental groupoid given in Definition 2.9.
Proposition 3.13 (Lifting embeddability).
 Let 
 $\Lambda , \Sigma $
 be connected k-graphs and let
$\Lambda , \Sigma $
 be connected k-graphs and let 
 $p : \Sigma \to \Lambda $
 be a covering. Then
$p : \Sigma \to \Lambda $
 be a covering. Then 
 $i_\Lambda : \Lambda \to \Pi ( \Lambda )$
 is injective if and only if
$i_\Lambda : \Lambda \to \Pi ( \Lambda )$
 is injective if and only if 
 $i_\Sigma : \Sigma \to \Pi (\Sigma )$
 is injective.
$i_\Sigma : \Sigma \to \Pi (\Sigma )$
 is injective.
Proof. Suppose that 
 $i_\Lambda : \Lambda \to \Pi (\Lambda )$
 is injective and that
$i_\Lambda : \Lambda \to \Pi (\Lambda )$
 is injective and that 
 $\sigma , \sigma ' \in \Sigma $
 satisfy
$\sigma , \sigma ' \in \Sigma $
 satisfy 
 $ {i_\Sigma (\sigma ) = i_\Sigma ( \sigma ' )}$
. In particular,
$ {i_\Sigma (\sigma ) = i_\Sigma ( \sigma ' )}$
. In particular, 
 $s(\sigma ) = s(\sigma ')$
; let
$s(\sigma ) = s(\sigma ')$
; let 
 $u := s(\sigma )$
. By universality of
$u := s(\sigma )$
. By universality of 
 $\Pi (\Sigma )$
, there is a unique groupoid morphism
$\Pi (\Sigma )$
, there is a unique groupoid morphism 
 $\tilde {p} : \Pi (\Sigma ) \to \Pi (\Lambda )$
 such that
$\tilde {p} : \Pi (\Sigma ) \to \Pi (\Lambda )$
 such that 
 $\tilde {p} \circ i_\Sigma = i_\Lambda \circ p$
. Hence,
$\tilde {p} \circ i_\Sigma = i_\Lambda \circ p$
. Hence, 
 $$ \begin{align*} i_\Lambda(p(\sigma)) = \tilde{p} ( i_\Sigma( \sigma)) = \tilde{p} ( i_\Sigma( \sigma')) = i_\Lambda(p(\sigma')). \end{align*} $$
$$ \begin{align*} i_\Lambda(p(\sigma)) = \tilde{p} ( i_\Sigma( \sigma)) = \tilde{p} ( i_\Sigma( \sigma')) = i_\Lambda(p(\sigma')). \end{align*} $$
Injectivity of 
 $i_\Lambda $
 forces
$i_\Lambda $
 forces 
 $p(\sigma ) = p(\sigma ')$
. Since p is a covering, it is injective on
$p(\sigma ) = p(\sigma ')$
. Since p is a covering, it is injective on 
 $s^{-1}(u)$
. So
$s^{-1}(u)$
. So 
 $\sigma = \sigma '$
, and hence
$\sigma = \sigma '$
, and hence 
 $i_\Sigma : \Sigma \to \Pi (\Sigma )$
 is injective.
$i_\Sigma : \Sigma \to \Pi (\Sigma )$
 is injective.
 For the reverse implication, suppose that 
 $i_\Lambda : \Lambda \to \Pi ( \Lambda )$
 is not injective. Then there are distinct
$i_\Lambda : \Lambda \to \Pi ( \Lambda )$
 is not injective. Then there are distinct 
 $\lambda , \lambda ' \in \Lambda $
 such that
$\lambda , \lambda ' \in \Lambda $
 such that 
 $i_\Lambda ( \lambda ) = i_\Lambda ( \lambda ' )$
. We may assume without loss of generality that
$i_\Lambda ( \lambda ) = i_\Lambda ( \lambda ' )$
. We may assume without loss of generality that 
 $\Sigma $
 is the universal covering of
$\Sigma $
 is the universal covering of 
 $\Lambda $
 so that
$\Lambda $
 so that 
 $\Sigma $
 is simply connected. Since
$\Sigma $
 is simply connected. Since 
 $\Sigma $
 is connected,
$\Sigma $
 is connected, 
 $r \times s : \Pi ( \Sigma ) \to \Sigma ^0 \times \Sigma ^0$
 is an isomorphism, so
$r \times s : \Pi ( \Sigma ) \to \Sigma ^0 \times \Sigma ^0$
 is an isomorphism, so 
 $\Pi ( \Sigma ) \cong T( \Sigma ^0 )$
. By Theorem 2.18(ii), given
$\Pi ( \Sigma ) \cong T( \Sigma ^0 )$
. By Theorem 2.18(ii), given 
 $u \in \Lambda ^0$
, there is a cocycle
$u \in \Lambda ^0$
, there is a cocycle 
 $\eta : \Lambda \to \pi _1(\Lambda , u)$
 such that
$\eta : \Lambda \to \pi _1(\Lambda , u)$
 such that 
 $\Sigma \cong \pi _1(\Lambda , u) \times _\eta \Lambda $
 and p is given by projection onto the second factor. It follows that
$\Sigma \cong \pi _1(\Lambda , u) \times _\eta \Lambda $
 and p is given by projection onto the second factor. It follows that 
 $s( \lambda ) = s( \lambda ' )$
,
$s( \lambda ) = s( \lambda ' )$
, 
 ${r( \lambda ) = r( \lambda ' )}$
 and
${r( \lambda ) = r( \lambda ' )}$
 and 
 $\eta ( \lambda ) = \eta ( \lambda ' )$
 (since
$\eta ( \lambda ) = \eta ( \lambda ' )$
 (since 
 $\eta $
 factors through
$\eta $
 factors through 
 $i_\Lambda $
 and
$i_\Lambda $
 and 
 $i_\Lambda ( \lambda ) = i_\Lambda ( \lambda ' )$
). Identifying
$i_\Lambda ( \lambda ) = i_\Lambda ( \lambda ' )$
). Identifying 
 $\Sigma $
 with the skew-product as above, set
$\Sigma $
 with the skew-product as above, set 
 $\sigma = (1, \lambda ), \sigma ' = (1, \lambda ') \in \Sigma $
, so
$\sigma = (1, \lambda ), \sigma ' = (1, \lambda ') \in \Sigma $
, so 
 $\sigma , \sigma '$
 are distinct. We have
$\sigma , \sigma '$
 are distinct. We have 
 $$ \begin{align*} s(\sigma) = s(1, \lambda) = (\eta(\lambda), s(\lambda)) = (\eta(\lambda'), s(\lambda')) = s(1, \lambda') = s(\sigma') \end{align*} $$
$$ \begin{align*} s(\sigma) = s(1, \lambda) = (\eta(\lambda), s(\lambda)) = (\eta(\lambda'), s(\lambda')) = s(1, \lambda') = s(\sigma') \end{align*} $$
and similarly, 
 $r(\sigma ) = r(\sigma ')$
. So
$r(\sigma ) = r(\sigma ')$
. So 
 $(r \times s)(i_\Sigma (\sigma )) = (r \times s)(i_\Sigma (\sigma '))$
. Since
$(r \times s)(i_\Sigma (\sigma )) = (r \times s)(i_\Sigma (\sigma '))$
. Since 
 $r \times s$
 is injective on
$r \times s$
 is injective on 
 $i_\Sigma $
, we deduce that
$i_\Sigma $
, we deduce that 
 $i_\Sigma : \Sigma \to \Pi (\Sigma )$
 is not injective.
$i_\Sigma : \Sigma \to \Pi (\Sigma )$
 is not injective.
 Our later results say that embeddability is preserved by various constructions of new k-graphs from old ones. So we need to know that some basic classes of k-graphs, like 
 $1$
-graphs, embed.
$1$
-graphs, embed.
Theorem 3.14. Let 
 $\Lambda $
 be a
$\Lambda $
 be a 
 $1$
-graph. Then
$1$
-graph. Then 
 $i_\Lambda : \Lambda \to \Pi ( \Lambda )$
 is injective.
$i_\Lambda : \Lambda \to \Pi ( \Lambda )$
 is injective.
Proof. Write 
 $\Lambda = \bigsqcup _{i=1}^n \Lambda _i $
 as a disjoint union of connected graphs. For
$\Lambda = \bigsqcup _{i=1}^n \Lambda _i $
 as a disjoint union of connected graphs. For 
 $i=1 , \ldots , n$
, let
$i=1 , \ldots , n$
, let 
 $\Sigma _i$
 be the universal cover of
$\Sigma _i$
 be the universal cover of 
 $\Lambda _i$
. Since
$\Lambda _i$
. Since 
 $\Sigma = \bigsqcup _{i=1}^n \Sigma _i$
 is (the path category of) a disjoint union of trees, there is at most one undirected path connecting any two distinct vertices. It follows that
$\Sigma = \bigsqcup _{i=1}^n \Sigma _i$
 is (the path category of) a disjoint union of trees, there is at most one undirected path connecting any two distinct vertices. It follows that 
 $\Sigma $
 is singly connected and therefore embeddable by Proposition 3.9(ii). Hence,
$\Sigma $
 is singly connected and therefore embeddable by Proposition 3.9(ii). Hence, 
 $i_\Lambda : \Lambda \to \Pi ( \Lambda )$
 is injective.
$i_\Lambda : \Lambda \to \Pi ( \Lambda )$
 is injective.
Corollary 3.15. Let 
 $\Lambda $
 be a k-graph and suppose that
$\Lambda $
 be a k-graph and suppose that 
 $i_\Lambda : \Lambda \to \Pi (\Lambda )$
 is injective.
$i_\Lambda : \Lambda \to \Pi (\Lambda )$
 is injective. 
- 
(i) Let  $f : \mathbb {N}^\ell \to \mathbb {N}^k$
 be an affine map. Then $f : \mathbb {N}^\ell \to \mathbb {N}^k$
 be an affine map. Then $i : f^* ( \Lambda ) \to \Pi (f^* ( \Lambda ) )$
 is injective. $i : f^* ( \Lambda ) \to \Pi (f^* ( \Lambda ) )$
 is injective.
- 
(ii) If  $\Gamma $
 is an $\Gamma $
 is an $\ell $
-graph and $\ell $
-graph and $i_\Gamma : \Gamma \to \Pi (\Gamma )$
 is injective, then $i_\Gamma : \Gamma \to \Pi (\Gamma )$
 is injective, then $i_{\Lambda \times \Gamma } : \Lambda \times \Gamma \to \Pi (\Lambda \times \Gamma )$
 is injective. $i_{\Lambda \times \Gamma } : \Lambda \times \Gamma \to \Pi (\Lambda \times \Gamma )$
 is injective.
- 
(iii) If  $c : \Lambda \to G$
 is a $c : \Lambda \to G$
 is a $1$
-cocycle into a group, then $1$
-cocycle into a group, then $i_{G\times \Lambda } : G \times _c \Lambda \to \Pi ( G \times _c \Lambda )$
 is injective. $i_{G\times \Lambda } : G \times _c \Lambda \to \Pi ( G \times _c \Lambda )$
 is injective.
- 
(iv) If  $\alpha : \mathbb {N}^\ell \to \operatorname {Aut} (\Lambda )$
 is an action, then there is an action $\alpha : \mathbb {N}^\ell \to \operatorname {Aut} (\Lambda )$
 is an action, then there is an action $\tilde {\alpha } : \mathbb {Z}^\ell \to \operatorname {Aut}(\Pi (\Lambda ))$
 such that $\tilde {\alpha } : \mathbb {Z}^\ell \to \operatorname {Aut}(\Pi (\Lambda ))$
 such that $\tilde {\alpha _n} \circ i_\Lambda = i_{\Lambda } \circ \alpha _n$
 for $\tilde {\alpha _n} \circ i_\Lambda = i_{\Lambda } \circ \alpha _n$
 for $n \in \mathbb {N}^\ell $
. Both are injective. Moreover, $n \in \mathbb {N}^\ell $
. Both are injective. Moreover, $$ \begin{align*} i_\Lambda \times i_{\mathbb{N}^\ell} : \Lambda \times_\alpha \mathbb{N}^\ell \to \Pi ( \Lambda) \times_\alpha \mathbb{Z}^\ell \quad\text{and}\quad i_{\Lambda \times_\alpha \mathbb{N}^\ell} : \Lambda \times_\alpha \mathbb{N}^\ell \to \Pi(\Lambda \times_\alpha \mathbb{N}^\ell) \end{align*} $$ $$ \begin{align*} i_\Lambda \times i_{\mathbb{N}^\ell} : \Lambda \times_\alpha \mathbb{N}^\ell \to \Pi ( \Lambda) \times_\alpha \mathbb{Z}^\ell \quad\text{and}\quad i_{\Lambda \times_\alpha \mathbb{N}^\ell} : \Lambda \times_\alpha \mathbb{N}^\ell \to \Pi(\Lambda \times_\alpha \mathbb{N}^\ell) \end{align*} $$ $i_\Lambda \times i_{\mathbb {N}^\ell }$
 induces an isomorphism $i_\Lambda \times i_{\mathbb {N}^\ell }$
 induces an isomorphism $\Pi ( \Lambda \times _\alpha \mathbb {N}^\ell ) \cong \Pi ( \Lambda ) \times _\alpha \mathbb {Z}^\ell $
. $\Pi ( \Lambda \times _\alpha \mathbb {N}^\ell ) \cong \Pi ( \Lambda ) \times _\alpha \mathbb {Z}^\ell $
.
Proof. (i) Define 
 $i \times \operatorname {id} : f^*( \Lambda ) \to \Pi (\Lambda ) \times \mathbb {Z}^\ell $
 by
$i \times \operatorname {id} : f^*( \Lambda ) \to \Pi (\Lambda ) \times \mathbb {Z}^\ell $
 by 
 $(i \times \operatorname {id})(\lambda , n) = (i(\lambda ), n)$
. Then
$(i \times \operatorname {id})(\lambda , n) = (i(\lambda ), n)$
. Then 
 $i \times \operatorname {id}$
 is an injective functor into a groupoid, so the result follows from Theorem 3.8.
$i \times \operatorname {id}$
 is an injective functor into a groupoid, so the result follows from Theorem 3.8.
 (ii) The map 
 $i_\Lambda \times i_\Gamma : \Lambda \times \Gamma \to \Pi (\Lambda ) \times \Pi (\Gamma )$
 is an injective functor into a groupoid, so the result follows from Theorem 3.8.
$i_\Lambda \times i_\Gamma : \Lambda \times \Gamma \to \Pi (\Lambda ) \times \Pi (\Gamma )$
 is an injective functor into a groupoid, so the result follows from Theorem 3.8.
 (iii) By universality of 
 $\Pi (\Lambda )$
, there is a cocycle
$\Pi (\Lambda )$
, there is a cocycle 
 $\tilde {c} : \Pi (\Lambda ) \to G$
 such that
$\tilde {c} : \Pi (\Lambda ) \to G$
 such that 
 $\tilde {c} \circ i_\Lambda = c$
. The skew-product groupoid
$\tilde {c} \circ i_\Lambda = c$
. The skew-product groupoid 
 $G \times _{\tilde {c}} \Pi (\Lambda )$
 is equal as a set to
$G \times _{\tilde {c}} \Pi (\Lambda )$
 is equal as a set to 
 $G \times \Pi (\Lambda )$
, and
$G \times \Pi (\Lambda )$
, and 
 $\operatorname {id}_G \times i_\Lambda : G \times _c \Lambda \to G \times _{\tilde {c}} \Pi (\Lambda )$
 is a functor. Since
$\operatorname {id}_G \times i_\Lambda : G \times _c \Lambda \to G \times _{\tilde {c}} \Pi (\Lambda )$
 is a functor. Since 
 $i_\Lambda $
 is injective, so is
$i_\Lambda $
 is injective, so is 
 $\operatorname {id}_G \times i_\Lambda $
, so the result follows from Theorem 3.8.
$\operatorname {id}_G \times i_\Lambda $
, so the result follows from Theorem 3.8.
 (iv) Since the action 
 $\alpha $
 of
$\alpha $
 of 
 $\mathbb {N}^\ell $
 on
$\mathbb {N}^\ell $
 on 
 $\Lambda $
 is determined by
$\Lambda $
 is determined by 
 $\ell $
 commuting automorphisms, it extends to an action (also called
$\ell $
 commuting automorphisms, it extends to an action (also called 
 $\alpha $
) of
$\alpha $
) of 
 $\mathbb {Z}^\ell $
 on
$\mathbb {Z}^\ell $
 on 
 $\Lambda $
. By functoriality, this extends to an action
$\Lambda $
. By functoriality, this extends to an action 
 $\tilde {\alpha } : \mathbb {Z}^\ell \to \operatorname {Aut}(\Pi (\Lambda ))$
 such that
$\tilde {\alpha } : \mathbb {Z}^\ell \to \operatorname {Aut}(\Pi (\Lambda ))$
 such that 
 $\tilde {\alpha _n} \circ i_\Lambda = i_{\Lambda } \circ \alpha _n$
 for
$\tilde {\alpha _n} \circ i_\Lambda = i_{\Lambda } \circ \alpha _n$
 for 
 $n \in \mathbb {N}^\ell $
. It is routine to check that
$n \in \mathbb {N}^\ell $
. It is routine to check that 
 $i_\Lambda \times i_{\mathbb {N}^\ell }$
 is a functor; it is injective because
$i_\Lambda \times i_{\mathbb {N}^\ell }$
 is a functor; it is injective because 
 $i_\Lambda $
 and
$i_\Lambda $
 and 
 $i_{\mathbb {N}^\ell }$
 are injective. So Theorem 3.8 implies that
$i_{\mathbb {N}^\ell }$
 are injective. So Theorem 3.8 implies that 
 $i_{\Lambda \times _\alpha \mathbb {N}^\ell }$
 is injective.
$i_{\Lambda \times _\alpha \mathbb {N}^\ell }$
 is injective.
 To see that 
 $i_\Lambda \times i_{\mathbb {N}^\ell }$
 induces an isomorphism
$i_\Lambda \times i_{\mathbb {N}^\ell }$
 induces an isomorphism 
 $\Pi ( \Lambda \times _\alpha \mathbb {N}^\ell ) \cong \Pi ( \Lambda ) \times _\alpha \mathbb {Z}^\ell $
, note that the universal property of
$\Pi ( \Lambda \times _\alpha \mathbb {N}^\ell ) \cong \Pi ( \Lambda ) \times _\alpha \mathbb {Z}^\ell $
, note that the universal property of 
 $\Pi ( \Lambda \times _\alpha \mathbb {N}^\ell )$
 implies that
$\Pi ( \Lambda \times _\alpha \mathbb {N}^\ell )$
 implies that 
 $i_\Lambda \times i_{\mathbb {N}^\ell }$
 induces a homomorphism
$i_\Lambda \times i_{\mathbb {N}^\ell }$
 induces a homomorphism 
 $\tilde {i} : \Pi ( \Lambda \times _\alpha \mathbb {N}^\ell ) \to \Pi ( \Lambda ) \times _\alpha \mathbb {Z}^\ell $
 such that
$\tilde {i} : \Pi ( \Lambda \times _\alpha \mathbb {N}^\ell ) \to \Pi ( \Lambda ) \times _\alpha \mathbb {Z}^\ell $
 such that 
 $\tilde {i} \circ i_{\Lambda \times _\alpha \mathbb {N}^\ell } = i_\Lambda \times i_{\mathbb {N}^\ell }$
. We construct an inverse. The restriction
$\tilde {i} \circ i_{\Lambda \times _\alpha \mathbb {N}^\ell } = i_\Lambda \times i_{\mathbb {N}^\ell }$
. We construct an inverse. The restriction 
 $c_1 := i_{\Lambda \times _\alpha \mathbb {N}^\ell }|_{\Lambda \times \{0\}} : \Lambda \to \Pi (\Lambda \times _\alpha \mathbb {N}^\ell )$
 is a functor, as is
$c_1 := i_{\Lambda \times _\alpha \mathbb {N}^\ell }|_{\Lambda \times \{0\}} : \Lambda \to \Pi (\Lambda \times _\alpha \mathbb {N}^\ell )$
 is a functor, as is 
 ${c_2 := i_{\Lambda \times _\alpha \mathbb {N}^\ell }|_{\Lambda ^0 \times \mathbb {N}^\ell }}$
. The universal property of
${c_2 := i_{\Lambda \times _\alpha \mathbb {N}^\ell }|_{\Lambda ^0 \times \mathbb {N}^\ell }}$
. The universal property of 
 $\Pi (\Lambda )$
 implies that
$\Pi (\Lambda )$
 implies that 
 $i_{\Lambda \times _\alpha \mathbb {N}^\ell }|_{\Lambda \times \{0\}}$
 induces a homomorphism
$i_{\Lambda \times _\alpha \mathbb {N}^\ell }|_{\Lambda \times \{0\}}$
 induces a homomorphism 
 $\tilde {c}_1 : \Pi (\Lambda ) \to \Pi ( \Lambda \times _\alpha \mathbb {N}^\ell )$
; and
$\tilde {c}_1 : \Pi (\Lambda ) \to \Pi ( \Lambda \times _\alpha \mathbb {N}^\ell )$
; and 
 $i_{\Lambda \times _\alpha \mathbb {N}^\ell }|_{\Lambda ^0 \times \mathbb {N}^\ell }$
 extends to a homomorphism
$i_{\Lambda \times _\alpha \mathbb {N}^\ell }|_{\Lambda ^0 \times \mathbb {N}^\ell }$
 extends to a homomorphism 
 $\tilde {c}_2 : \Lambda ^0 \times \mathbb {Z}^\ell \to \Pi ( \Lambda \times _\alpha \mathbb {N}^\ell )$
. Routine calculations show that
$\tilde {c}_2 : \Lambda ^0 \times \mathbb {Z}^\ell \to \Pi ( \Lambda \times _\alpha \mathbb {N}^\ell )$
. Routine calculations show that 
 $\tilde {c}_1 \times \tilde {c}_2 : \Pi (\Lambda ) \times _{\tilde {\alpha }} \mathbb {Z}^\ell \to \Pi (\Lambda \times _\alpha \mathbb {N}^\ell )$
 is a homomorphism inverse to
$\tilde {c}_1 \times \tilde {c}_2 : \Pi (\Lambda ) \times _{\tilde {\alpha }} \mathbb {Z}^\ell \to \Pi (\Lambda \times _\alpha \mathbb {N}^\ell )$
 is a homomorphism inverse to 
 $\tilde {i}$
.
$\tilde {i}$
.
Remark 3.16. Combining Theorem 3.14 and Corollary 3.15(iv), we see that crossed-product graphs of 
 $1$
-graphs always embed in their fundamental groupoids.
$1$
-graphs always embed in their fundamental groupoids.
Examples 3.17. We present two examples of Corollary 3.15(i).
- 
(i) Define  $f : \mathbb {N}^2 \to \mathbb {N}$
 by $f : \mathbb {N}^2 \to \mathbb {N}$
 by $f(a,b)=a+b$
. Let $f(a,b)=a+b$
. Let $\Lambda = f^* (B_n)$
. Corollary 3.15 implies that $\Lambda = f^* (B_n)$
. Corollary 3.15 implies that $f^* (\Lambda )$
 embeds in its fundamental group since Theorem 3.14 impies that the 1-graph $f^* (\Lambda )$
 embeds in its fundamental group since Theorem 3.14 impies that the 1-graph $B_n$
 does. Indeed, for $B_n$
 does. Indeed, for $\theta : [n] \times [n] \to [n] \times [n]$
 given by $\theta : [n] \times [n] \to [n] \times [n]$
 given by $\theta (i,j)=(i, j)$
, we have $\theta (i,j)=(i, j)$
, we have $\Lambda \cong \mathbb {F}_\theta ^+$
. $\Lambda \cong \mathbb {F}_\theta ^+$
.
- 
(ii) Let  $\Lambda $
 be a $\Lambda $
 be a $2$
-graph and define $2$
-graph and define $f : \mathbb {N}^2 \to \mathbb {N}^2$
 by $f : \mathbb {N}^2 \to \mathbb {N}^2$
 by $f(a,b)=(a,b)+\mathbf {1}$
. Then $f(a,b)=(a,b)+\mathbf {1}$
. Then $f^*(\Lambda )$
 is the dual graph $f^*(\Lambda )$
 is the dual graph $\mathbf {1} \Lambda $
 described in [Reference Allen, Pask and Sims1, Definition 3.1]. So for the $\mathbf {1} \Lambda $
 described in [Reference Allen, Pask and Sims1, Definition 3.1]. So for the $2$
-graph $2$
-graph $\Lambda = \mathbb {F}_\theta ^+$
 from example (i) above, $\Lambda = \mathbb {F}_\theta ^+$
 from example (i) above, $f^* ( \mathbb {F}_\theta ^+ )$
 embeds in its fundamental group by Corollary 3.15(i). $f^* ( \mathbb {F}_\theta ^+ )$
 embeds in its fundamental group by Corollary 3.15(i).
Corollary 3.18 (Action graphs).
 Let 
 $\Lambda $
 be a k-graph. Let
$\Lambda $
 be a k-graph. Let 
 $B_n$
 be the
$B_n$
 be the 
 $1$
-graph described in Example 2.3(i). Let
$1$
-graph described in Example 2.3(i). Let 
 $\mu \mapsto \alpha _\mu $
 be a functor from
$\mu \mapsto \alpha _\mu $
 be a functor from 
 $B_n$
 to
$B_n$
 to 
 $\operatorname {Aut}(\Lambda )$
. Let
$\operatorname {Aut}(\Lambda )$
. Let 
 ${\Gamma = B_n \times \Lambda }$
; define
${\Gamma = B_n \times \Lambda }$
; define 
 $d : \Gamma \to \mathbb {N}^{k+1}$
 by
$d : \Gamma \to \mathbb {N}^{k+1}$
 by 
 $d(\mu , \lambda ) = (|\mu |, d(\lambda ))$
; define
$d(\mu , \lambda ) = (|\mu |, d(\lambda ))$
; define 
 $r, s : \Gamma \to \Gamma ^0$
 by
$r, s : \Gamma \to \Gamma ^0$
 by 
 ${r(\mu , \lambda ) = (u, \alpha _\mu (r(\lambda )))}$
 and
${r(\mu , \lambda ) = (u, \alpha _\mu (r(\lambda )))}$
 and 
 $s(\mu , \lambda ) = (u, s(\lambda ))$
; and define composition in
$s(\mu , \lambda ) = (u, s(\lambda ))$
; and define composition in 
 $\Gamma $
 by
$\Gamma $
 by 
 $$ \begin{align} (\mu,\alpha_\nu(\lambda))(\nu,\xi) = (\mu\nu, \lambda\xi). \end{align} $$
$$ \begin{align} (\mu,\alpha_\nu(\lambda))(\nu,\xi) = (\mu\nu, \lambda\xi). \end{align} $$
Then 
 $(\Gamma ,d)$
 is a
$(\Gamma ,d)$
 is a 
 $(k+1)$
-graph. If
$(k+1)$
-graph. If 
 $i_\Lambda : \Lambda \to \Pi ( \Lambda )$
 is injective, then
$i_\Lambda : \Lambda \to \Pi ( \Lambda )$
 is injective, then 
 $i_\Gamma : \Gamma \to \Pi ( \Gamma )$
 is injective.
$i_\Gamma : \Gamma \to \Pi ( \Gamma )$
 is injective.
Proof. It is routine to check that (3-3) determines an associative composition. The map d is clearly a functor and if 
 $d(\mu ,\lambda ) = (a+b, m+n)$
, then factorising
$d(\mu ,\lambda ) = (a+b, m+n)$
, then factorising 
 $\mu = \mu _a \mu _b$
 and
$\mu = \mu _a \mu _b$
 and 
 $\lambda = \lambda _m \lambda _n$
 with the appropriate degrees, the factorisation
$\lambda = \lambda _m \lambda _n$
 with the appropriate degrees, the factorisation 
 $(\mu ,\lambda ) = (\mu _a, \alpha _{\mu _b}(\lambda _m))(\mu _b,\lambda _n)$
 is the unique factorisation of
$(\mu ,\lambda ) = (\mu _a, \alpha _{\mu _b}(\lambda _m))(\mu _b,\lambda _n)$
 is the unique factorisation of 
 $(\mu ,\lambda )$
 into morphisms of degrees
$(\mu ,\lambda )$
 into morphisms of degrees 
 $(a,m)$
 and
$(a,m)$
 and 
 $(b,n)$
. So
$(b,n)$
. So 
 $\Gamma $
 is a
$\Gamma $
 is a 
 $(k+1)$
-graph.
$(k+1)$
-graph.
 Universality of 
 $\Pi ( \Lambda )$
 implies that each
$\Pi ( \Lambda )$
 implies that each 
 $\alpha _\mu $
 extends to an automorphism of
$\alpha _\mu $
 extends to an automorphism of 
 $\Pi ( \Lambda )$
. So
$\Pi ( \Lambda )$
. So 
 $\alpha $
 extends to an action of
$\alpha $
 extends to an action of 
 $\Pi (B_n) \cong \mathbb {F}_n$
 on
$\Pi (B_n) \cong \mathbb {F}_n$
 on 
 $\Pi ( \Lambda )$
, with semidirect product groupoid
$\Pi ( \Lambda )$
, with semidirect product groupoid 
 $\Pi (B_n) \ltimes _{\tilde {\alpha }} \Pi ( \Lambda )$
. Then
$\Pi (B_n) \ltimes _{\tilde {\alpha }} \Pi ( \Lambda )$
. Then 
 $i_{B_n} \times i_\Lambda $
 is an embedding of
$i_{B_n} \times i_\Lambda $
 is an embedding of 
 $\Gamma $
 in
$\Gamma $
 in 
 $\Pi (B_n) \ltimes _{\tilde {\alpha }} \Pi ( \Lambda )$
. The result now follows by Theorem 3.8.
$\Pi (B_n) \ltimes _{\tilde {\alpha }} \Pi ( \Lambda )$
. The result now follows by Theorem 3.8.
Examples 3.19.
- 
(i) Fix  $m,n \ge 2$
. Let $m,n \ge 2$
. Let $\Lambda = B_m$
 be the $\Lambda = B_m$
 be the $1$
-graph described in Example 2.3(i). For each $1$
-graph described in Example 2.3(i). For each $f \in B_n^1$
, let $f \in B_n^1$
, let $\alpha _f$
 be a permutation of $\alpha _f$
 be a permutation of $B_m^1$
 and extend this to a $B_m^1$
 and extend this to a $1$
-cocycle $1$
-cocycle $B_n \to \operatorname {Aut}(\Lambda )$
 in the only possible way. By Theorem 3.18, these data give rise to a $B_n \to \operatorname {Aut}(\Lambda )$
 in the only possible way. By Theorem 3.18, these data give rise to a $2$
-graph $2$
-graph $\Gamma $
 that embeds in its fundamental group. Define $\Gamma $
 that embeds in its fundamental group. Define $\theta : [n] \times [m] \to [m] \times [n]$
 by $\theta : [n] \times [m] \to [m] \times [n]$
 by $\theta (i,j) = (j' , i)$
 if and only if $\theta (i,j) = (j' , i)$
 if and only if $\alpha _{f_i}(f_j) = f_{j'}$
. Then $\alpha _{f_i}(f_j) = f_{j'}$
. Then $\Gamma $
 is isomorphic to the $\Gamma $
 is isomorphic to the $2$
-graph $2$
-graph $\mathbb {F}_\theta ^+$
 of Example 2.5. In particular, $\mathbb {F}_\theta ^+$
 of Example 2.5. In particular, $\mathbb {F}_\theta ^+$
 embeds in its fundamental group. $\mathbb {F}_\theta ^+$
 embeds in its fundamental group.
Example 3.20. Fix 
 $n \ge 2$
 and a permutation
$n \ge 2$
 and a permutation 
 $\sigma \in \operatorname {Bij} ( [n] )$
, the group of all bijections of the set
$\sigma \in \operatorname {Bij} ( [n] )$
, the group of all bijections of the set 
 $[n]$
. Define
$[n]$
. Define 
 $\theta : [n] \times [n] \to [n] \times [n]$
 by
$\theta : [n] \times [n] \to [n] \times [n]$
 by 
 $\theta (i,j) = (\sigma (i) ,j )$
. This fits into the situation of Example 3.19, so
$\theta (i,j) = (\sigma (i) ,j )$
. This fits into the situation of Example 3.19, so 
 $\mathbb {F}_\theta ^+$
 embeds in its fundamental group.
$\mathbb {F}_\theta ^+$
 embeds in its fundamental group.
Definition 3.21. Let X be a nonempty set. A map 
 $R : X^2 \to X^2$
 is a (set-theoretic) Yang–Baxter solution if
$R : X^2 \to X^2$
 is a (set-theoretic) Yang–Baxter solution if 
 $$ \begin{align*} (R \times \text{id}_X)(\text{id}_X \times R)(R \times \text{id}_X) = (\text{id}_X \times R)(R \times \text{id}_X) (\text{id}_X \times R) \end{align*} $$
$$ \begin{align*} (R \times \text{id}_X)(\text{id}_X \times R)(R \times \text{id}_X) = (\text{id}_X \times R)(R \times \text{id}_X) (\text{id}_X \times R) \end{align*} $$
as maps on 
 $X^3$
. For every permutation
$X^3$
. For every permutation 
 $\sigma $
 of X, there is a Yang–Baxter solution R given by
$\sigma $
 of X, there is a Yang–Baxter solution R given by 
 $R(e, f) = (\sigma (f), e)$
; such solutions are called permutation-type Yang–Baxter solutions.
$R(e, f) = (\sigma (f), e)$
; such solutions are called permutation-type Yang–Baxter solutions.
For the interplay between the Yang–Baxter equation and k-graphs, see [Reference Yang47].
Lemma 3.22. Fix a finite set X and a Yang–Baxter solution 
 $R : X^2 \to X^2$
 on X. Fix
$R : X^2 \to X^2$
 on X. Fix 
 $k \ge 2$
. Let
$k \ge 2$
. Let 
 $\Lambda _{k, R}^0 = \{v\}$
. For
$\Lambda _{k, R}^0 = \{v\}$
. For 
 $i \le k$
, let
$i \le k$
, let 
 $\Lambda _{k, R}^{\varepsilon _i}=\{i\} \times X$
. For
$\Lambda _{k, R}^{\varepsilon _i}=\{i\} \times X$
. For 
 $(i, e) \in \Lambda _{k, R}^{\varepsilon _i}$
 and
$(i, e) \in \Lambda _{k, R}^{\varepsilon _i}$
 and 
 $(j, f) \in \Lambda _{k, R}^{\varepsilon _j}$
 with
$(j, f) \in \Lambda _{k, R}^{\varepsilon _j}$
 with 
 $i < j$
, set
$i < j$
, set 
 $$ \begin{align*} (i,e)(j,f) = (j, f')(i, e') \quad\text{if } R(e,f) = ( f',e'). \end{align*} $$
$$ \begin{align*} (i,e)(j,f) = (j, f')(i, e') \quad\text{if } R(e,f) = ( f',e'). \end{align*} $$
There is a unique k-graph 
 $\Lambda _{k, R}$
 with these edges and factorisation rules. If R is a permutation-type Yang–Baxter solution, then
$\Lambda _{k, R}$
 with these edges and factorisation rules. If R is a permutation-type Yang–Baxter solution, then 
 $i : \Lambda _{k, R} \to \Pi ( \Lambda _{k, R} )$
 is injective.
$i : \Lambda _{k, R} \to \Pi ( \Lambda _{k, R} )$
 is injective.
Proof. The first statement follows from [Reference Yang47, Section 4.1]. For the second statement, we proceed by induction. For 
 $k=2$
, this follows from [Reference Yang47, Section 4.1]. Now suppose inductively that
$k=2$
, this follows from [Reference Yang47, Section 4.1]. Now suppose inductively that 
 $\Lambda _{k-1, R}$
 embeds in its fundamental groupoid. There is an automorphism
$\Lambda _{k-1, R}$
 embeds in its fundamental groupoid. There is an automorphism 
 $\alpha $
 of
$\alpha $
 of 
 $\Lambda _{k-1, R}$
 such that
$\Lambda _{k-1, R}$
 such that 
 $\alpha (i, e) = (i, \sigma (e))$
 for all
$\alpha (i, e) = (i, \sigma (e))$
 for all 
 $i \le k-1$
 and
$i \le k-1$
 and 
 $e \in X$
. For
$e \in X$
. For 
 $e \in B^1_{|X|}$
, let
$e \in B^1_{|X|}$
, let 
 ${\alpha _{e} := \alpha \in \operatorname {Aut}(\Lambda _{k-1, R})}$
. Corollary 3.18 yields a k-graph
${\alpha _{e} := \alpha \in \operatorname {Aut}(\Lambda _{k-1, R})}$
. Corollary 3.18 yields a k-graph 
 $\Gamma = B_{|X|} \times _\alpha \Lambda _{k-1, R}$
. Choose a bijection
$\Gamma = B_{|X|} \times _\alpha \Lambda _{k-1, R}$
. Choose a bijection 
 $\phi : B_{|X|}^1 \to \Lambda _{k, R}^{\varepsilon _1}$
. Then there is an isomorphism
$\phi : B_{|X|}^1 \to \Lambda _{k, R}^{\varepsilon _1}$
. Then there is an isomorphism 
 $\Gamma \to \Lambda _{k, R}$
 that agrees with
$\Gamma \to \Lambda _{k, R}$
 that agrees with 
 $\phi $
 on
$\phi $
 on 
 ${B^1_{|X|} \subseteq \Gamma }$
 and takes each
${B^1_{|X|} \subseteq \Gamma }$
 and takes each 
 $(i, e) \in \Lambda ^{\varepsilon _i}_{k-1, R} \subseteq \Gamma $
 to
$(i, e) \in \Lambda ^{\varepsilon _i}_{k-1, R} \subseteq \Gamma $
 to 
 $(i+1, e) \in \Lambda ^{\varepsilon _{i+1}}_{k, R}$
. Corollary 3.18 implies that
$(i+1, e) \in \Lambda ^{\varepsilon _{i+1}}_{k, R}$
. Corollary 3.18 implies that 
 $\Gamma $
 embeds in its fundamental groupoid, so
$\Gamma $
 embeds in its fundamental groupoid, so 
 $\Lambda _{k, R}$
 does too.
$\Lambda _{k, R}$
 does too.
Remark 3.23. For a long time, the literature on k-graphs lacked concrete examples with 
 $k \ge 3$
 not obtained from lower-rank graphs via the constructions of Corollary 3.15. Yang’s important insight [Reference Yang47] remedied this situation: every Yang–Baxter solution yields k-graphs for arbitrary k, typically not of the forms from Corollary 3.15. In particular, Lemma 3.22 uses Yang’s construction to see that every finite permutation
$k \ge 3$
 not obtained from lower-rank graphs via the constructions of Corollary 3.15. Yang’s important insight [Reference Yang47] remedied this situation: every Yang–Baxter solution yields k-graphs for arbitrary k, typically not of the forms from Corollary 3.15. In particular, Lemma 3.22 uses Yang’s construction to see that every finite permutation 
 $\sigma $
 yields a k-graph that embeds in its fundamental groupoid for each
$\sigma $
 yields a k-graph that embeds in its fundamental groupoid for each 
 $k \ge 1$
. Taking
$k \ge 1$
. Taking 
 $\sigma = \operatorname {id}$
 yields Cartesian-product k-graphs, but most other choices of
$\sigma = \operatorname {id}$
 yields Cartesian-product k-graphs, but most other choices of 
 $\sigma $
 yield k-graphs that do not arise from the constructions of Corollary 3.15.
$\sigma $
 yield k-graphs that do not arise from the constructions of Corollary 3.15.
Remark 3.24. Work of Lawson and Vdovina also yields many embeddable k-graphs. A monoidal k-graph is rigid [Reference Lawson and Vdovina29, page 37] if whenever e and f are edges of different degrees, there are unique edges 
 $e', e", f', f"$
 such that
$e', e", f', f"$
 such that 
 $e'f = f'e$
 and
$e'f = f'e$
 and 
 $ef" = fe"$
. Theorem 3.8 and [Reference Lawson and Vdovina29, Theorem 11.14] combined imply that every rigid monoidal k-graph
$ef" = fe"$
. Theorem 3.8 and [Reference Lawson and Vdovina29, Theorem 11.14] combined imply that every rigid monoidal k-graph 
 $\Lambda $
 embeds in
$\Lambda $
 embeds in 
 $\Pi (\Lambda )$
.
$\Pi (\Lambda )$
.
 We finish the section by showing that a strongly connected k-graph 
 $\Lambda $
 embeds in
$\Lambda $
 embeds in 
 $\Pi (\Lambda )$
 whenever the submonoid of endomorphisms at any vertex embeds in a group.
$\Pi (\Lambda )$
 whenever the submonoid of endomorphisms at any vertex embeds in a group.
Proposition 3.25. Let 
 $\Lambda $
 be a strongly connected k-graph and H a group. Fix
$\Lambda $
 be a strongly connected k-graph and H a group. Fix 
 $v \in \Lambda ^0$
. If there exists an injective monoid homomorphism
$v \in \Lambda ^0$
. If there exists an injective monoid homomorphism 
 $c : v\Lambda v \to H$
, then
$c : v\Lambda v \to H$
, then 
 $i : \Lambda \to \Pi (\Lambda )$
 is injective.
$i : \Lambda \to \Pi (\Lambda )$
 is injective.
Proof. The universal property of 
 $\Pi (\Lambda )$
 given in Definition 2.9 implies that there is a homomorphism
$\Pi (\Lambda )$
 given in Definition 2.9 implies that there is a homomorphism 
 $\tilde {c} : i(v)\Pi (\Lambda )i(v) \to H$
 such that
$\tilde {c} : i(v)\Pi (\Lambda )i(v) \to H$
 such that 
 $\tilde {c} \circ i = c$
. Since
$\tilde {c} \circ i = c$
. Since 
 $\Lambda $
 is strongly connected and since
$\Lambda $
 is strongly connected and since 
 $\Pi (\Lambda )$
 is a discrete groupoid,
$\Pi (\Lambda )$
 is a discrete groupoid, 
 $\Pi (\Lambda )$
 is isomorphic to
$\Pi (\Lambda )$
 is isomorphic to 
 $T(\Lambda ^0) \times i(v)\Pi (\Lambda )i(v)$
. Post-composing this isomorphism with
$T(\Lambda ^0) \times i(v)\Pi (\Lambda )i(v)$
. Post-composing this isomorphism with 
 $\operatorname {id}_{T(\Lambda ^0)} \times \tilde {c}$
 yields a groupoid homomorphism
$\operatorname {id}_{T(\Lambda ^0)} \times \tilde {c}$
 yields a groupoid homomorphism 
 $q : \Pi (\Lambda ) \to T(\Lambda ^0) \times H$
. Suppose that
$q : \Pi (\Lambda ) \to T(\Lambda ^0) \times H$
. Suppose that 
 $q(i(\mu )) = q(i(\nu ))$
. Fix
$q(i(\mu )) = q(i(\nu ))$
. Fix 
 $\lambda \in v\Lambda r(\mu )$
 and
$\lambda \in v\Lambda r(\mu )$
 and 
 $\tau \in s(\mu )\Lambda v$
. We have
$\tau \in s(\mu )\Lambda v$
. We have 
 $$ \begin{align*} ((v,v), c(\lambda\mu\tau)) &= ((v,v), \tilde{c}(i(\lambda\mu\tau))) = q(i(\lambda\mu\tau))\\ &= q(i(\lambda\nu\tau)) = ((v,v), \tilde{c}(i(\lambda\nu\tau))) ((v,v), c(\lambda\nu\tau)). \end{align*} $$
$$ \begin{align*} ((v,v), c(\lambda\mu\tau)) &= ((v,v), \tilde{c}(i(\lambda\mu\tau))) = q(i(\lambda\mu\tau))\\ &= q(i(\lambda\nu\tau)) = ((v,v), \tilde{c}(i(\lambda\nu\tau))) ((v,v), c(\lambda\nu\tau)). \end{align*} $$
Since c is injective, 
 $\lambda \mu \tau = \lambda \nu \tau $
 and so
$\lambda \mu \tau = \lambda \nu \tau $
 and so 
 $\mu = \nu $
. Thus,
$\mu = \nu $
. Thus, 
 $q \circ i$
, and therefore i, is injective.
$q \circ i$
, and therefore i, is injective.
Example 3.26. Consider the 
 $2$
-graph
$2$
-graph 
 $\Lambda $
 below with relations
$\Lambda $
 below with relations 
 $a_0e=fa_1, \ a_1e=fa_0 , bf=eb$
.
$a_0e=fa_1, \ a_1e=fa_0 , bf=eb$
. 

Then 
 $\Lambda $
 is strongly connected. None of our results before Proposition 3.25 apply to show that
$\Lambda $
 is strongly connected. None of our results before Proposition 3.25 apply to show that 
 $\Lambda $
 embeds in
$\Lambda $
 embeds in 
 $\Pi (\Lambda )$
. Since
$\Pi (\Lambda )$
. Since 
 $e b a_i = b f a_i = ba_{1-i} e$
 for each i, the monoid
$e b a_i = b f a_i = ba_{1-i} e$
 for each i, the monoid 
 ${u\Lambda u \subseteq \Lambda }$
 has presentation
${u\Lambda u \subseteq \Lambda }$
 has presentation 
 $$ \begin{align*} u \Lambda u = \langle e, b a_0 , b a_1 : eba_i = ba_{1-i} e, i=0,1 \rangle, \end{align*} $$
$$ \begin{align*} u \Lambda u = \langle e, b a_0 , b a_1 : eba_i = ba_{1-i} e, i=0,1 \rangle, \end{align*} $$
so is isomorphic to the semidirect product 
 $\mathbb {F}^+_2 \times _\alpha \mathbb {N}$
 for the action
$\mathbb {F}^+_2 \times _\alpha \mathbb {N}$
 for the action 
 $\alpha $
 that interchanges
$\alpha $
 that interchanges 
 $\{ b a_0 , b a_1 \}$
, the generators of
$\{ b a_0 , b a_1 \}$
, the generators of 
 $\mathbb {F}^+_2$
. The action
$\mathbb {F}^+_2$
. The action 
 $\alpha $
 extends uniquely to an action
$\alpha $
 extends uniquely to an action 
 $\tilde {\alpha }$
 of
$\tilde {\alpha }$
 of 
 $\mathbb {Z}$
 on
$\mathbb {Z}$
 on 
 $\mathbb {F}_2$
, and
$\mathbb {F}_2$
, and 
 $u \Lambda u \cong \mathbb {F}^+_2 \times _\alpha \mathbb {N}$
 embeds in
$u \Lambda u \cong \mathbb {F}^+_2 \times _\alpha \mathbb {N}$
 embeds in 
 $\mathbb {F}_2 \times _{\tilde {\alpha }} \mathbb {Z}$
. So Proposition 3.25 implies that
$\mathbb {F}_2 \times _{\tilde {\alpha }} \mathbb {Z}$
. So Proposition 3.25 implies that 
 ${i : \Lambda \to \Pi (\Lambda )}$
 is injective.
${i : \Lambda \to \Pi (\Lambda )}$
 is injective.
4 
 $C^*$
-algebraic results
$C^*$
-algebraic results
 Here, we generalise [Reference Kumjian and Pask25, Corollary 4.14], which says that the 
 $C^*$
-algebra of a connected row-finite
$C^*$
-algebra of a connected row-finite 
 $1$
-graph is Rieffel–Morita equivalent to a crossed product of a commutative
$1$
-graph is Rieffel–Morita equivalent to a crossed product of a commutative 
 $C^*$
-algebra by the fundamental group of the graph. The situation is much more complicated in higher dimensions.
$C^*$
-algebra by the fundamental group of the graph. The situation is much more complicated in higher dimensions.
 Let 
 $\Lambda $
 be a connected row-finite source-free k-graph. Fix
$\Lambda $
 be a connected row-finite source-free k-graph. Fix 
 $v\in \Lambda ^0$
. By Theorem 2.18 (see [Reference Pask, Raeburn and Quigg33, Corollary 6.5]), there is a cocycle
$v\in \Lambda ^0$
. By Theorem 2.18 (see [Reference Pask, Raeburn and Quigg33, Corollary 6.5]), there is a cocycle 
 $\eta : \Lambda \to \pi _1 (\Lambda , v)$
 such that the skew-product
$\eta : \Lambda \to \pi _1 (\Lambda , v)$
 such that the skew-product 
 $ \pi _1 ( \Lambda , v ) \times _\eta \Lambda $
 is isomorphic to the universal cover
$ \pi _1 ( \Lambda , v ) \times _\eta \Lambda $
 is isomorphic to the universal cover 
 $\Sigma $
 of
$\Sigma $
 of 
 $\Lambda $
. It then follows from [Reference Kumjian and Pask26, Theorem 5.7] that
$\Lambda $
. It then follows from [Reference Kumjian and Pask26, Theorem 5.7] that 
 $C^*(\Lambda )$
 is Rieffel–Morita equivalent to
$C^*(\Lambda )$
 is Rieffel–Morita equivalent to 
 $C^*(\Sigma )\rtimes \pi _1(\Lambda ,v)$
. Our main theorem describes the coefficient algebra
$C^*(\Sigma )\rtimes \pi _1(\Lambda ,v)$
. Our main theorem describes the coefficient algebra 
 $C^*(\Sigma )$
 of this crossed product.
$C^*(\Sigma )$
 of this crossed product.
Theorem 4.1. Let 
 $\Lambda $
 be a connected row-finite source-free k-graph and let
$\Lambda $
 be a connected row-finite source-free k-graph and let 
 ${\Sigma = \pi _1(\Lambda , v) \times _\eta \Lambda }$
 be as above so that
${\Sigma = \pi _1(\Lambda , v) \times _\eta \Lambda }$
 be as above so that 
 $C^*(\Lambda )$
 is Rieffel–Morita equivalent to
$C^*(\Lambda )$
 is Rieffel–Morita equivalent to 
 $C^*(\Sigma ) \rtimes \pi _1(\Lambda , v)$
.
$C^*(\Sigma ) \rtimes \pi _1(\Lambda , v)$
. 
- 
(i) The  $C^*$
-algebra $C^*$
-algebra $C^*(\Sigma )$
 is AF. $C^*(\Sigma )$
 is AF.
- 
(ii) If  $\Lambda $
 embeds in its fundamental groupoid $\Lambda $
 embeds in its fundamental groupoid $\Pi (\Lambda )$
, then $\Pi (\Lambda )$
, then $C^*(\Sigma )$
 is type I $C^*(\Sigma )$
 is type I $_0$
 and its spectrum has a cover by zero-dimensional compact open Hausdorff subsets. $_0$
 and its spectrum has a cover by zero-dimensional compact open Hausdorff subsets.
- 
(iii) If  $\Lambda $
 embeds in its fundamental groupoid $\Lambda $
 embeds in its fundamental groupoid $\Pi (\Lambda )$
 and $\Pi (\Lambda )$
 and $\Sigma ^{\mathbb {N}\mathbf {1}}$
 is simply connected, then $\Sigma ^{\mathbb {N}\mathbf {1}}$
 is simply connected, then $C^*(\Sigma )$
 is Rieffel–Morita equivalent to a commutative $C^*(\Sigma )$
 is Rieffel–Morita equivalent to a commutative $C^*$
-algebra. $C^*$
-algebra.
We use the next two results to prove parts (i) and (ii) of Theorem 4.1.
Proposition 4.2. Let 
 $\Gamma $
 be a row-finite source-free k-graph. If
$\Gamma $
 be a row-finite source-free k-graph. If 
 $\Gamma $
 is simply connected, then there is a map
$\Gamma $
 is simply connected, then there is a map 
 $f: \Gamma ^0 \to \mathbb {Z}^k$
 such that
$f: \Gamma ^0 \to \mathbb {Z}^k$
 such that 
 $d(\lambda ) = f(s(\lambda )) - f(r(\lambda ))$
 for all
$d(\lambda ) = f(s(\lambda )) - f(r(\lambda ))$
 for all 
 $\lambda \in \Gamma $
. Moreover,
$\lambda \in \Gamma $
. Moreover, 
 $C^*(\Gamma )$
 is AF.
$C^*(\Gamma )$
 is AF.
Proof. Since 
 $d : \Gamma \to \mathbb {Z}^k$
 is a cocycle, Lemma 2.19 ensures the existence of f. Now, [Reference Kumjian and Pask26, Lemma 5.4] implies that
$d : \Gamma \to \mathbb {Z}^k$
 is a cocycle, Lemma 2.19 ensures the existence of f. Now, [Reference Kumjian and Pask26, Lemma 5.4] implies that 
 $C^*(\Gamma )$
 is AF.
$C^*(\Gamma )$
 is AF.
Example 4.3. Let 
 $\Lambda $
 be the
$\Lambda $
 be the 
 $2$
-graph of Example 3.1 (see [Reference Pask, Raeburn and Quigg32, Example 7.1]). Recall that
$2$
-graph of Example 3.1 (see [Reference Pask, Raeburn and Quigg32, Example 7.1]). Recall that 
 $\Lambda $
 does not embed in its fundamental groupoid and the universal cover
$\Lambda $
 does not embed in its fundamental groupoid and the universal cover 
 ${\Sigma = \mathbb {Z}^2 \times _d \Lambda }$
 is simply connected. We claim that
${\Sigma = \mathbb {Z}^2 \times _d \Lambda }$
 is simply connected. We claim that 
 $C^*(\Sigma )$
 is Rieffel–Morita equivalent to the UHF algebra
$C^*(\Sigma )$
 is Rieffel–Morita equivalent to the UHF algebra 
 $M_{6^{\infty }}$
 (in fact,
$M_{6^{\infty }}$
 (in fact, 
 $C^*(\Sigma ) \cong M_{6^{\infty }} \otimes \mathcal {K}$
). For each
$C^*(\Sigma ) \cong M_{6^{\infty }} \otimes \mathcal {K}$
). For each 
 $n \in \mathbb {N}$
, set
$n \in \mathbb {N}$
, set 
 $v_n := n\mathbf {1}$
 and observe that as in the proof of [Reference Kumjian and Pask26, Lemma 5.4],
$v_n := n\mathbf {1}$
 and observe that as in the proof of [Reference Kumjian and Pask26, Lemma 5.4], 
 $A_n := C^*(\{ s_\lambda : s(\lambda ) = v_n \}) \cong \mathcal {K}(\ell ^2(s^{-1}(v_n)))$
. Moreover, for all n,
$A_n := C^*(\{ s_\lambda : s(\lambda ) = v_n \}) \cong \mathcal {K}(\ell ^2(s^{-1}(v_n)))$
. Moreover, for all n, 
 $A_n \subset A_{n+1}$
 and the multiplicity of the embedding is 6 (since
$A_n \subset A_{n+1}$
 and the multiplicity of the embedding is 6 (since 
 $|v_n\Lambda v_{n+1}| = 6$
). Since the sequence
$|v_n\Lambda v_{n+1}| = 6$
). Since the sequence 
 $(v_n)^\infty_{n=1}$
 is cofinal in
$(v_n)^\infty_{n=1}$
 is cofinal in 
 $\mathbb {Z}^2$
,
$\mathbb {Z}^2$
, 
 $$ \begin{align*} C^*(\Sigma) \cong \varinjlim A_n \cong \varinjlim \mathcal{K}(\ell^2(s^{-1}(v_n))). \end{align*} $$
$$ \begin{align*} C^*(\Sigma) \cong \varinjlim A_n \cong \varinjlim \mathcal{K}(\ell^2(s^{-1}(v_n))). \end{align*} $$
Hence, 
 $C^*(\Sigma )$
 is Rieffel–Morita equivalent to the UHF algebra
$C^*(\Sigma )$
 is Rieffel–Morita equivalent to the UHF algebra 
 $M_{6^{\infty }}$
 as claimed.
$M_{6^{\infty }}$
 as claimed.
Proposition 4.4. Let 
 $\Gamma $
 be a row-finite source-free k-graph. If
$\Gamma $
 be a row-finite source-free k-graph. If 
 $\Gamma $
 is singly connected, then, for each
$\Gamma $
 is singly connected, then, for each 
 $v \in \Gamma ^0$
, the corner
$v \in \Gamma ^0$
, the corner 
 $s_vC^*(\Gamma )s_v$
 is an abelian
$s_vC^*(\Gamma )s_v$
 is an abelian 
 $C^*$
-algebra isomorphic to
$C^*$
-algebra isomorphic to 
 $C(Z(v))$
. Moreover,
$C(Z(v))$
. Moreover, 
 $C^*(\Gamma )$
 is type I
$C^*(\Gamma )$
 is type I
 $_0$
 and
$_0$
 and 
 $\operatorname {Prim} C^*(\Gamma )$
 admits a cover by zero-dimensional compact open Hausdorff sets.
$\operatorname {Prim} C^*(\Gamma )$
 admits a cover by zero-dimensional compact open Hausdorff sets.
Proof. Fix 
 $x, y \in \Gamma ^\infty $
 such that
$x, y \in \Gamma ^\infty $
 such that 
 $x(0) = y(0)$
 and
$x(0) = y(0)$
 and 
 $p,q\in \mathbb {N}^k$
. We claim that if
$p,q\in \mathbb {N}^k$
. We claim that if 
 $\sigma ^p(x) = \sigma ^q(y)$
, then
$\sigma ^p(x) = \sigma ^q(y)$
, then 
 $p =q$
 and
$p =q$
 and 
 $x = y$
. To see this, suppose that
$x = y$
. To see this, suppose that 
 $\sigma ^p(x) = \sigma ^q(y)$
. Then
$\sigma ^p(x) = \sigma ^q(y)$
. Then 
 $\sigma ^p(x)(0) = \sigma ^q(y)(0)$
. Let
$\sigma ^p(x)(0) = \sigma ^q(y)(0)$
. Let 
 $u := x(0) = y(0)$
 and
$u := x(0) = y(0)$
 and 
 $v := \sigma ^p(x)(0) = \sigma ^q(y)(0)$
. Then
$v := \sigma ^p(x)(0) = \sigma ^q(y)(0)$
. Then 
 $x(0, p), y(0, q) \in u{\Gamma }v$
. Since
$x(0, p), y(0, q) \in u{\Gamma }v$
. Since 
 $\Gamma $
 is singly connected,
$\Gamma $
 is singly connected, 
 $x(0, p) = y(0, q)$
. Hence,
$x(0, p) = y(0, q)$
. Hence, 
 ${x = x(0, p)\sigma ^p(x) = y(0, q)\sigma ^q(y)(0) = y}$
, and the claim holds.
${x = x(0, p)\sigma ^p(x) = y(0, q)\sigma ^q(y)(0) = y}$
, and the claim holds.
 Now, recall from [Reference Kumjian and Pask26] that 
 $\Gamma ^\infty = \mathcal {G}_\Gamma ^0$
 and that for
$\Gamma ^\infty = \mathcal {G}_\Gamma ^0$
 and that for 
 $v \in \Gamma ^0$
,
$v \in \Gamma ^0$
, 
 $$ \begin{align*} \mathcal{G}_\Gamma|_{Z(v)} := \{ \gamma \in \mathcal{G}_\Gamma : s(\gamma), r(\gamma) \in Z(v) \}, \end{align*} $$
$$ \begin{align*} \mathcal{G}_\Gamma|_{Z(v)} := \{ \gamma \in \mathcal{G}_\Gamma : s(\gamma), r(\gamma) \in Z(v) \}, \end{align*} $$
 $s_v = \chi _{Z(v)} \subset C_0(\mathcal {G}_\Gamma ^0)$
 and
$s_v = \chi _{Z(v)} \subset C_0(\mathcal {G}_\Gamma ^0)$
 and 
 $s_vC^*(\Gamma )s_v \cong C^*( \mathcal {G}_\Gamma |_{Z(v)})$
. By the first paragraph,
$s_vC^*(\Gamma )s_v \cong C^*( \mathcal {G}_\Gamma |_{Z(v)})$
. By the first paragraph, 
 ${\mathcal {G}_\Gamma |_{Z(v)}^0 \cong Z(v)}$
. Hence,
${\mathcal {G}_\Gamma |_{Z(v)}^0 \cong Z(v)}$
. Hence, 
 $C^*( \mathcal {G}_\Gamma |_{Z(v)}) \cong C(Z(v))$
. So for each
$C^*( \mathcal {G}_\Gamma |_{Z(v)}) \cong C(Z(v))$
. So for each 
 $v \in \Gamma ^0$
, the ideal
$v \in \Gamma ^0$
, the ideal 
 $I_v$
 generated by
$I_v$
 generated by 
 $s_v$
 is Rieffel–Morita equivalent to the abelian
$s_v$
 is Rieffel–Morita equivalent to the abelian 
 $C^*$
-algebra
$C^*$
-algebra 
 $C(Z(v))$
. Since
$C(Z(v))$
. Since 
 $C^*(\Gamma )$
 is generated by the ideals
$C^*(\Gamma )$
 is generated by the ideals 
 $I_v$
,
$I_v$
, 
 $C^*(\Gamma )$
 is type I
$C^*(\Gamma )$
 is type I
 $_0$
.
$_0$
.
 By definition of the hull-kernel topology, the ideals 
 $I_v$
 yield a cover of
$I_v$
 yield a cover of 
 $\operatorname {Prim}(C^*(\Gamma ))$
 by open sets
$\operatorname {Prim}(C^*(\Gamma ))$
 by open sets 
 $\widehat {I}_v \cong \operatorname {Prim}(I_v)$
. Since each
$\widehat {I}_v \cong \operatorname {Prim}(I_v)$
. Since each 
 $I_v$
 is Rieffel–Morita equivalent to
$I_v$
 is Rieffel–Morita equivalent to 
 $C(Z(v))$
, each
$C(Z(v))$
, each 
 $\operatorname {Prim}(I_v) \cong Z(v)$
 is a zero-dimensional compact open Hausdorff subspace of
$\operatorname {Prim}(I_v) \cong Z(v)$
 is a zero-dimensional compact open Hausdorff subspace of 
 $\operatorname {Prim}(C^*(\Gamma ))$
.
$\operatorname {Prim}(C^*(\Gamma ))$
.
Proof of Theorem 4.1(i) and (ii).
 Proposition 4.2 for 
 $\Gamma =\Sigma $
 gives part (i). If
$\Gamma =\Sigma $
 gives part (i). If 
 $\Lambda \to \Pi (\Lambda )$
 is injective, then so is
$\Lambda \to \Pi (\Lambda )$
 is injective, then so is 
 $\Sigma \to \Pi (\Sigma )$
 by Proposition 3.13. Since
$\Sigma \to \Pi (\Sigma )$
 by Proposition 3.13. Since 
 $\Sigma $
 is simply connected, Proposition 3.6 implies that
$\Sigma $
 is simply connected, Proposition 3.6 implies that 
 $\Sigma $
 is singly connected; so Proposition 4.4 for
$\Sigma $
 is singly connected; so Proposition 4.4 for 
 $\Gamma =\Sigma $
 gives part (ii).
$\Gamma =\Sigma $
 gives part (ii).
 To prove Theorem 4.1(iii), we argue that the spectrum 
 $C^*(\Sigma )^{\wedge }$
 is Hausdorff: then Theorem 4.1(ii) shows that
$C^*(\Sigma )^{\wedge }$
 is Hausdorff: then Theorem 4.1(ii) shows that 
 $C^*(\Sigma )$
 is Rieffel–Morita equivalent to a continuous-trace
$C^*(\Sigma )$
 is Rieffel–Morita equivalent to a continuous-trace 
 $C^*$
-algebra with totally disconnected spectrum, and the Dixmier–Douady theorem shows that
$C^*$
-algebra with totally disconnected spectrum, and the Dixmier–Douady theorem shows that 
 $C^*(\Sigma )$
 is Rieffel–Morita equivalent to
$C^*(\Sigma )$
 is Rieffel–Morita equivalent to 
 $C_0(C^*(\Sigma )^{\wedge })$
. We argue that
$C_0(C^*(\Sigma )^{\wedge })$
. We argue that 
 $C_0(C^*(\Sigma )^{\wedge }) \cong \Sigma ^{\mathbb {N}\mathbf {1}}/\mathcal {G}_{\Sigma ^{\mathbb {N}\mathbf {1}}}$
 and use the additional hypothesis that
$C_0(C^*(\Sigma )^{\wedge }) \cong \Sigma ^{\mathbb {N}\mathbf {1}}/\mathcal {G}_{\Sigma ^{\mathbb {N}\mathbf {1}}}$
 and use the additional hypothesis that 
 $\Sigma ^{\mathbb {N}\mathbf {1}}$
 is simply connected to prove Theorem 4.1(iii). We do not know whether this additional hypothesis is automatic; certainly, even for
$\Sigma ^{\mathbb {N}\mathbf {1}}$
 is simply connected to prove Theorem 4.1(iii). We do not know whether this additional hypothesis is automatic; certainly, even for 
 $1$
-graphs, being singly connected does not guarantee that the associated
$1$
-graphs, being singly connected does not guarantee that the associated 
 $C^*$
-algebra has Hausdorff spectrum.
$C^*$
-algebra has Hausdorff spectrum.
Example 4.5. Let E be the directed graph (pictured below) such that:
- 
•  $E^0 = \{u_n, v_n : n \in \mathbb {Z}\} \cup \{w_{n, i} : n \in \mathbb {Z} \text { and }i \ge 0\}$
; and $E^0 = \{u_n, v_n : n \in \mathbb {Z}\} \cup \{w_{n, i} : n \in \mathbb {Z} \text { and }i \ge 0\}$
; and
- 
•  $E^1 = \{e_n, f_n, g_n, h_n : n \in \mathbb {Z}\} \cup \{k_{n, i} : n \in \mathbb {Z}\text { and }i \ge 0\}$
, $E^1 = \{e_n, f_n, g_n, h_n : n \in \mathbb {Z}\} \cup \{k_{n, i} : n \in \mathbb {Z}\text { and }i \ge 0\}$
,
and such that for 
 $n \in \mathbb {Z}$
 and
$n \in \mathbb {Z}$
 and 
 $i \ge 0$
,
$i \ge 0$
, 
 $$ \begin{align*} r(e_n) &= s(e_{n-1}) = r(g_n) = u_n,\quad r(f_n) = s(f_{n-1}) = r(h_n) = v_n,\\ s(g_n) &= s(h_n) = r(k_{n,0}) = w_{n,0}, \quad s(k_{n,i}) = r(k_{n, i+1}) = w_{n, i+1}. \end{align*} $$
$$ \begin{align*} r(e_n) &= s(e_{n-1}) = r(g_n) = u_n,\quad r(f_n) = s(f_{n-1}) = r(h_n) = v_n,\\ s(g_n) &= s(h_n) = r(k_{n,0}) = w_{n,0}, \quad s(k_{n,i}) = r(k_{n, i+1}) = w_{n, i+1}. \end{align*} $$

 This graph E is singly connected. Define 
 $x,y \in E^\infty $
 by
$x,y \in E^\infty $
 by 
 $x = e_0 e_1 e_2 \cdots $
 and
$x = e_0 e_1 e_2 \cdots $
 and 
 ${y = f_0 f_1 f_2\cdots }$
. Then
${y = f_0 f_1 f_2\cdots }$
. Then 
 $[x] \not = [y]$
 in
$[x] \not = [y]$
 in 
 $\mathcal {G}_E^{(0)}/\mathcal {G}_E$
. We claim that they cannot be separated by disjoint open sets. To see this, for
$\mathcal {G}_E^{(0)}/\mathcal {G}_E$
. We claim that they cannot be separated by disjoint open sets. To see this, for 
 $n \in \mathbb {Z}$
, let
$n \in \mathbb {Z}$
, let 
 $z_n = k_{n,0} k_{n, 1} k_{n, 2} \cdots $
. We show that
$z_n = k_{n,0} k_{n, 1} k_{n, 2} \cdots $
. We show that 
 $[z_n] \to [x]$
 and
$[z_n] \to [x]$
 and 
 $z_n \to [y]$
 as
$z_n \to [y]$
 as 
 $n \to \infty $
. By symmetry, we just have to show that
$n \to \infty $
. By symmetry, we just have to show that 
 $[z_n] \to [x]$
. For this, just note that
$[z_n] \to [x]$
. For this, just note that 
 $[z_n] = [e_0 e_1 \cdots e_{n-1} g_n z_n]$
 and we have
$[z_n] = [e_0 e_1 \cdots e_{n-1} g_n z_n]$
 and we have 
 $\lim _{n \to \infty } e_0 e_1 \cdots e_{n-1} g_n z_n = e_0 e_1 e_2 \cdots = x$
.
$\lim _{n \to \infty } e_0 e_1 \cdots e_{n-1} g_n z_n = e_0 e_1 e_2 \cdots = x$
.
 We have 
 $C^*(E) \cong C^*(\mathcal {G}_E)$
 by [Reference Kumjian, Pask, Raeburn and Renault27, Proposition 4.1]. Since
$C^*(E) \cong C^*(\mathcal {G}_E)$
 by [Reference Kumjian, Pask, Raeburn and Renault27, Proposition 4.1]. Since 
 $C^*(E)$
 is type I
$C^*(E)$
 is type I
 $_0$
, its spectrum is homeomorphic, by [Reference Clark11, Corollary 4.2], to the orbit space
$_0$
, its spectrum is homeomorphic, by [Reference Clark11, Corollary 4.2], to the orbit space 
 $\mathcal {G}_E^{(0)}/\mathcal {G}_E$
 of
$\mathcal {G}_E^{(0)}/\mathcal {G}_E$
 of 
 $\mathcal {G}_E$
, which we just saw is not Hausdorff. Note that E is not simply connected (for example,
$\mathcal {G}_E$
, which we just saw is not Hausdorff. Note that E is not simply connected (for example, 
 $e_0g_1h_1^{-1}f_0^{-1}h_0g_0^{-1} \in \Pi (E^*)^{u_0}_{u_0} \setminus \{u_0\}$
).
$e_0g_1h_1^{-1}f_0^{-1}h_0g_0^{-1} \in \Pi (E^*)^{u_0}_{u_0} \setminus \{u_0\}$
).
 Example 4.5 suggests a Hausdorffness criterion (Lemma 4.7). As this criterion is not easy to check, in Theorem 4.8, we specialise to singly connected k-graphs and recast it in terms of the following relation on vertices, which permeates analyses of ideals of k-graph 
 $C^*$
-algebras [Reference Raeburn, Sims and Yeend36].
$C^*$
-algebras [Reference Raeburn, Sims and Yeend36].
Notation 4.6. For 
 $\Gamma $
 a k-graph, we define a relation
$\Gamma $
 a k-graph, we define a relation 
 $\le $
 on
$\le $
 on 
 $\Gamma ^0$
 by
$\Gamma ^0$
 by 
 $v \le w$
 if and only if
$v \le w$
 if and only if 
 $v \Gamma w \not = \emptyset $
.
$v \Gamma w \not = \emptyset $
.
Lemma 4.7. Let 
 $\Gamma $
 be a row-finite source-free k-graph and let
$\Gamma $
 be a row-finite source-free k-graph and let 
 $\mathcal {G}_\Gamma $
 be its k-graph groupoid. The orbit space
$\mathcal {G}_\Gamma $
 be its k-graph groupoid. The orbit space 
 $\Gamma ^\infty /\mathcal {G}_\Gamma $
 is Hausdorff if and only if for every pair of infinite paths
$\Gamma ^\infty /\mathcal {G}_\Gamma $
 is Hausdorff if and only if for every pair of infinite paths 
 $x,y \in \Gamma ^\infty $
 such that
$x,y \in \Gamma ^\infty $
 such that 
 $[x]\not =[y]$
, there exists
$[x]\not =[y]$
, there exists 
 $N \in \mathbb {N}^k$
 such that the vertices
$N \in \mathbb {N}^k$
 such that the vertices 
 $x(N)$
 on x and
$x(N)$
 on x and 
 $y(N)$
 on y have no common upper bound with respect to
$y(N)$
 on y have no common upper bound with respect to 
 $\le $
, in the sense that
$\le $
, in the sense that 
 $s(\mu ) \not = s(\nu )$
 for all
$s(\mu ) \not = s(\nu )$
 for all 
 $\mu \in x(N)\Gamma $
 and
$\mu \in x(N)\Gamma $
 and 
 $\nu \in y(N)\Gamma $
.
$\nu \in y(N)\Gamma $
.
Proof. We have 
 $[x] = [y]$
 if and only if
$[x] = [y]$
 if and only if 
 $\sigma ^m(x) = \sigma ^n(y)$
 for some
$\sigma ^m(x) = \sigma ^n(y)$
 for some 
 $m,n$
. So it suffices to fix
$m,n$
. So it suffices to fix 
 $x,y$
 such that
$x,y$
 such that 
 $\sigma ^m(x) \not = \sigma ^n(y)$
 for all
$\sigma ^m(x) \not = \sigma ^n(y)$
 for all 
 $m,n$
, and show that
$m,n$
, and show that 
 $[x]$
 and
$[x]$
 and 
 $[y]$
 can be separated if and only if there exists N as in the statement. Suppose that there is no such N. For each
$[y]$
 can be separated if and only if there exists N as in the statement. Suppose that there is no such N. For each 
 $N \in \mathbb {N}^k$
, choose
$N \in \mathbb {N}^k$
, choose 
 $\mu _N \in x(N)\Gamma $
 and
$\mu _N \in x(N)\Gamma $
 and 
 $\nu _N \in y(N)\Gamma $
 with
$\nu _N \in y(N)\Gamma $
 with 
 $s(\mu _N) = s(\nu _N)$
, and
$s(\mu _N) = s(\nu _N)$
, and 
 ${z_N \in s(\mu _N)\Gamma ^\infty }$
. Then
${z_N \in s(\mu _N)\Gamma ^\infty }$
. Then 
 $x(0,N)\mu _Nz_N \to x$
 and
$x(0,N)\mu _Nz_N \to x$
 and 
 $y(0, N)\nu _N z_N \to y$
. Since each
$y(0, N)\nu _N z_N \to y$
. Since each 
 $[x(0,N)\mu _Nz_N] = [z_N] = [y(0,N)\nu _Nz_N]$
, this forces
$[x(0,N)\mu _Nz_N] = [z_N] = [y(0,N)\nu _Nz_N]$
, this forces 
 $[z_N] \to [x]$
 and
$[z_N] \to [x]$
 and 
 $[z_N] \to [y]$
. Now suppose that there exists N as in the statement. Then
$[z_N] \to [y]$
. Now suppose that there exists N as in the statement. Then 
 $q(Z(x(0, N)))$
 and
$q(Z(x(0, N)))$
 and 
 $q(Z(y(0,N)))$
 are disjoint open neighbourhoods of
$q(Z(y(0,N)))$
 are disjoint open neighbourhoods of 
 $[x]$
 and
$[x]$
 and 
 $[y]$
 in
$[y]$
 in 
 $\Gamma ^\infty /\mathcal {G}_\Gamma $
.
$\Gamma ^\infty /\mathcal {G}_\Gamma $
.
 Recall that a filter for a partially ordered set 
 $(X, \preceq )$
 is a nonempty subset
$(X, \preceq )$
 is a nonempty subset 
 $F \subseteq X$
 such that:
$F \subseteq X$
 such that: 
- 
(a) for all  $u,v \in F$
, there exists $u,v \in F$
, there exists $w \in F$
 such that $w \in F$
 such that $u,v \preceq w$
; $u,v \preceq w$
;
- 
(b) if  $v \in F$
 and $v \in F$
 and $u \preceq v$
, then $u \preceq v$
, then $u \in F$
. $u \in F$
.
A filter F for 
 $\preceq $
 is called an ultrafilter if:
$\preceq $
 is called an ultrafilter if: 
- 
(c) F is not properly contained in any other filter  $F'$
 for $F'$
 for $(X, \preceq )$
. $(X, \preceq )$
.
 If 
 $\Gamma $
 is singly connected, then
$\Gamma $
 is singly connected, then 
 $\le $
 is a partial order on
$\le $
 is a partial order on 
 $\Gamma ^0$
. We show that elements of
$\Gamma ^0$
. We show that elements of 
 $\Gamma ^\infty /\mathcal {G}_\Gamma $
 correspond with ultrafilters for
$\Gamma ^\infty /\mathcal {G}_\Gamma $
 correspond with ultrafilters for 
 $(\Gamma ^0, \le )$
 and use this to characterise Hausdorffness of
$(\Gamma ^0, \le )$
 and use this to characterise Hausdorffness of 
 $\Gamma ^\infty /\mathcal {G}_\Gamma $
.
$\Gamma ^\infty /\mathcal {G}_\Gamma $
.
Theorem 4.8. Let 
 $\Gamma $
 be a singly connected row-finite source-free k-graph. Then the ultrafilters for
$\Gamma $
 be a singly connected row-finite source-free k-graph. Then the ultrafilters for 
 $(\Gamma ^0, \le )$
 are exactly the sets
$(\Gamma ^0, \le )$
 are exactly the sets 
 $[x]^0 := \{r(y) : y \in [x]\}$
 indexed by elements
$[x]^0 := \{r(y) : y \in [x]\}$
 indexed by elements 
 $x \in \Gamma ^\infty $
. Moreover,
$x \in \Gamma ^\infty $
. Moreover, 
 $\Gamma ^\infty /\mathcal {G}_\Gamma $
 is Hausdorff if and only if for every pair
$\Gamma ^\infty /\mathcal {G}_\Gamma $
 is Hausdorff if and only if for every pair 
 $U, V$
 of distinct ultrafilters of
$U, V$
 of distinct ultrafilters of 
 $(\Gamma ^0, \le )$
, there is a pair
$(\Gamma ^0, \le )$
, there is a pair 
 $u \in U$
 and
$u \in U$
 and 
 $v \in V$
 with no common upper bound with respect to
$v \in V$
 with no common upper bound with respect to 
 $\le $
.
$\le $
.
Proof. For the first statement, first fix 
 $x \in \Gamma ^\infty $
. If
$x \in \Gamma ^\infty $
. If 
 $v_1, v_2 \in [x]^0$
, then
$v_1, v_2 \in [x]^0$
, then 
 $v_1 = r(\alpha \sigma ^m(x))$
 and
$v_1 = r(\alpha \sigma ^m(x))$
 and 
 $v_2 = r(\beta \sigma ^n(x))$
 for some
$v_2 = r(\beta \sigma ^n(x))$
 for some 
 $\alpha ,\beta , m,n$
, and then
$\alpha ,\beta , m,n$
, and then 
 $w = r(\sigma ^{m+n}(x)) \in [x]^0$
 satisfies
$w = r(\sigma ^{m+n}(x)) \in [x]^0$
 satisfies 
 ${v_i \Gamma w \not = \emptyset }$
 by definition; so
${v_i \Gamma w \not = \emptyset }$
 by definition; so 
 $[x]^0$
 satisfies part (a). If
$[x]^0$
 satisfies part (a). If 
 $w \in [x]^0$
 and
$w \in [x]^0$
 and 
 $v \in \Gamma ^0$
 satisfy
$v \in \Gamma ^0$
 satisfy 
 $v \le w$
, say
$v \le w$
, say 
 ${\alpha \in v \Gamma w}$
, then since
${\alpha \in v \Gamma w}$
, then since 
 $w \in [x]^0$
, we have
$w \in [x]^0$
, we have 
 $w = r(\beta \sigma ^{n}(x))$
 for some
$w = r(\beta \sigma ^{n}(x))$
 for some 
 $\beta , n$
 and so
$\beta , n$
 and so 
 $v = r(\alpha \beta \sigma ^n(x)) \in [x]^0$
; so
$v = r(\alpha \beta \sigma ^n(x)) \in [x]^0$
; so 
 $[x]^0$
 satisfies part (b). Suppose that F is a filter for
$[x]^0$
 satisfies part (b). Suppose that F is a filter for 
 $(\Gamma ^0, \le )$
 containing
$(\Gamma ^0, \le )$
 containing 
 $[x]^0$
. Fix
$[x]^0$
. Fix 
 $v \in F$
; we must show that
$v \in F$
; we must show that 
 $v \in [x]^0$
. Since
$v \in [x]^0$
. Since 
 $v, x(0) \in F$
, there exists
$v, x(0) \in F$
, there exists 
 $w \in F$
 with
$w \in F$
 with 
 $v \le w$
 and
$v \le w$
 and 
 $x(0) \le w$
, and by part (b), if
$x(0) \le w$
, and by part (b), if 
 $w \in [x]^0$
, then
$w \in [x]^0$
, then 
 $v \in [x]^0$
; so we just have to show that
$v \in [x]^0$
; so we just have to show that 
 $w \in [x]^0$
. Fix
$w \in [x]^0$
. Fix 
 $\alpha \in x(0)\Gamma w$
. Then
$\alpha \in x(0)\Gamma w$
. Then 
 $r(\sigma ^{d(\alpha )}(x)) \in [x]^0 \subseteq F$
. So there exists
$r(\sigma ^{d(\alpha )}(x)) \in [x]^0 \subseteq F$
. So there exists 
 $w' \in F$
 such that
$w' \in F$
 such that 
 $r(\sigma ^{d(\alpha )}(x)), w \le w'$
; say
$r(\sigma ^{d(\alpha )}(x)), w \le w'$
; say 
 $\rho \in r(\sigma ^{d(\alpha )}(x)) \Gamma w'$
 and
$\rho \in r(\sigma ^{d(\alpha )}(x)) \Gamma w'$
 and 
 $\tau \in w \Gamma w'$
. So
$\tau \in w \Gamma w'$
. So 
 $\alpha \tau $
 and
$\alpha \tau $
 and 
 $x(0, d(\alpha ))\rho $
 both belong to
$x(0, d(\alpha ))\rho $
 both belong to 
 $x(0) \Gamma w'$
. Since
$x(0) \Gamma w'$
. Since 
 $\Gamma $
 is singly connected, this forces
$\Gamma $
 is singly connected, this forces 
 $\alpha \tau = x(0, d(\alpha ))\rho $
, so the factorisation property forces
$\alpha \tau = x(0, d(\alpha ))\rho $
, so the factorisation property forces 
 $x(0, d(\alpha )) = \alpha $
; hence,
$x(0, d(\alpha )) = \alpha $
; hence, 
 $w = s(\alpha ) = s(x(0,d(\alpha ))) \in [x]^0$
.
$w = s(\alpha ) = s(x(0,d(\alpha ))) \in [x]^0$
.
 Now, fix an ultrafilter F for 
 $(\Gamma ^0, \le )$
. Enumerate
$(\Gamma ^0, \le )$
. Enumerate 
 $F = (v_1, v_2, \ldots )$
, put
$F = (v_1, v_2, \ldots )$
, put 
 $w_1 = v_1$
 and inductively use part (a) to choose
$w_1 = v_1$
 and inductively use part (a) to choose 
 $w_{i+1} \in F$
 such that
$w_{i+1} \in F$
 such that 
 $v_{i+1}, w_i \le w_{i+1}$
. So
$v_{i+1}, w_i \le w_{i+1}$
. So 
 $(w_i)_i$
 is an increasing sequence such that every
$(w_i)_i$
 is an increasing sequence such that every 
 $v \in F$
 satisfies
$v \in F$
 satisfies 
 $v \le w_i$
 for some i. For each i, use that
$v \le w_i$
 for some i. For each i, use that 
 $w_i \le w_{i+1}$
 to fix
$w_i \le w_{i+1}$
 to fix 
 $\alpha _i \in w_i \Gamma w_{i+1}$
, let
$\alpha _i \in w_i \Gamma w_{i+1}$
, let 
 $\rho _i := \alpha _1\cdots \alpha _i$
 and choose
$\rho _i := \alpha _1\cdots \alpha _i$
 and choose 
 $y_i \in Z(\rho _i) \subseteq \Gamma ^\infty $
. Since
$y_i \in Z(\rho _i) \subseteq \Gamma ^\infty $
. Since 
 $(y_i)_i$
 belongs to the compact set
$(y_i)_i$
 belongs to the compact set 
 $Z(v_1)$
, it has a convergent subsequence
$Z(v_1)$
, it has a convergent subsequence 
 $y_{i_l} \to y \in Z(v_1)$
. We claim that
$y_{i_l} \to y \in Z(v_1)$
. We claim that 
 $F = [y]^0$
. By part (c), it suffices to show that
$F = [y]^0$
. By part (c), it suffices to show that 
 $F \subseteq [y]^0$
. So fix
$F \subseteq [y]^0$
. So fix 
 $v \in F$
. Then
$v \in F$
. Then 
 $v = v_m \le w_m$
 for some
$v = v_m \le w_m$
 for some 
 $m \in \mathbb {N}$
. Choose l so that
$m \in \mathbb {N}$
. Choose l so that 
 $i_l \ge m$
. For
$i_l \ge m$
. For 
 $l' \ge l$
, we have
$l' \ge l$
, we have 
 ${y_{i_{l'}} \in Z(\rho _{i_{l'}}) \subseteq Z(\rho _{i_l})}$
. Hence,
${y_{i_{l'}} \in Z(\rho _{i_{l'}}) \subseteq Z(\rho _{i_l})}$
. Hence, 
 $y \in Z(\rho _{i_l})$
. So
$y \in Z(\rho _{i_l})$
. So 
 $w_{i_l} = s(\rho _{i_l}) = r(\sigma ^{d(\rho _{i_l})}(y)) \in [y]^0$
. By choice of
$w_{i_l} = s(\rho _{i_l}) = r(\sigma ^{d(\rho _{i_l})}(y)) \in [y]^0$
. By choice of 
 $(w_j)_j$
 and l, we have
$(w_j)_j$
 and l, we have 
 $v \le w_m \le w_{i_l}$
. So part (b) gives
$v \le w_m \le w_{i_l}$
. So part (b) gives 
 $v \in [y]^0$
. This proves the first statement.
$v \in [y]^0$
. This proves the first statement.
 For the second statement, by Lemma 4.7, it suffices to show that for all 
 $x,y \in \Gamma ^\infty $
 with
$x,y \in \Gamma ^\infty $
 with 
 $[x] \not = [y]$
, there exists N such that
$[x] \not = [y]$
, there exists N such that 
 $s(x(N)\Gamma ) \cap s(y(N)\Gamma ) = \emptyset $
 if and only if, for all pairs
$s(x(N)\Gamma ) \cap s(y(N)\Gamma ) = \emptyset $
 if and only if, for all pairs 
 $U \not = V$
 of ultrafilters of
$U \not = V$
 of ultrafilters of 
 $(\Gamma ^0, \le )$
, there exist
$(\Gamma ^0, \le )$
, there exist 
 $u \in U$
 and
$u \in U$
 and 
 $v \in V$
 with no common upper bound with respect to
$v \in V$
 with no common upper bound with respect to 
 $\le $
.
$\le $
.
 First, suppose that for every pair 
 $x,y \in \Gamma ^\infty $
, there exists N such that
$x,y \in \Gamma ^\infty $
, there exists N such that 
 $s(\rho ) \not = s(\tau )$
 for every
$s(\rho ) \not = s(\tau )$
 for every 
 $\rho \in x(N)\Gamma $
 and
$\rho \in x(N)\Gamma $
 and 
 $\tau \in y(N)\Gamma $
. Fix ultrafilters
$\tau \in y(N)\Gamma $
. Fix ultrafilters 
 $U \not = V$
, and fix
$U \not = V$
, and fix 
 $x,y \in \Gamma ^\infty $
 with
$x,y \in \Gamma ^\infty $
 with 
 $U = [x]^0$
 and
$U = [x]^0$
 and 
 $V = [y]^0$
. Fix N such that
$V = [y]^0$
. Fix N such that 
 $s(\rho ) \not = s(\tau )$
 for every
$s(\rho ) \not = s(\tau )$
 for every 
 $\rho \in x(N)\Gamma $
 and
$\rho \in x(N)\Gamma $
 and 
 $\tau \in y(N)\Gamma $
. Then
$\tau \in y(N)\Gamma $
. Then 
 $u = x(N) \in U$
 and
$u = x(N) \in U$
 and 
 $v = y(N) \in V$
 have no common upper bound. Now, suppose that for every pair
$v = y(N) \in V$
 have no common upper bound. Now, suppose that for every pair 
 $U \not = V$
 of ultrafilters, there exist
$U \not = V$
 of ultrafilters, there exist 
 $u \in U$
 and
$u \in U$
 and 
 $v \in V$
 with no common upper bound. Fix
$v \in V$
 with no common upper bound. Fix 
 $x,y \in \Gamma ^\infty $
 with
$x,y \in \Gamma ^\infty $
 with 
 $U = [x]^0$
 and
$U = [x]^0$
 and 
 $V = [y]^0$
. Fix
$V = [y]^0$
. Fix 
 $u \in U$
 and
$u \in U$
 and 
 $v \in V$
 with no common upper bound. Fix
$v \in V$
 with no common upper bound. Fix 
 $x' \in [x]$
 and
$x' \in [x]$
 and 
 $y' \in [y]$
 with
$y' \in [y]$
 with 
 $r(x') = u$
 and
$r(x') = u$
 and 
 $r(y') = v$
, and
$r(y') = v$
, and 
 $m, m'$
 and
$m, m'$
 and 
 $n, n'$
 such that
$n, n'$
 such that 
 $\sigma ^m(x) = \sigma ^{m'}(x')$
 and
$\sigma ^m(x) = \sigma ^{m'}(x')$
 and 
 $\sigma ^n(y) = \sigma ^{n'}(y')$
. Fix
$\sigma ^n(y) = \sigma ^{n'}(y')$
. Fix 
 $N \ge m,n$
. Then
$N \ge m,n$
. Then 
 $u \Gamma x(N) \not = \emptyset $
 and
$u \Gamma x(N) \not = \emptyset $
 and 
 $v \Gamma y(N) \not = \emptyset $
. Since
$v \Gamma y(N) \not = \emptyset $
. Since 
 $u,v$
 have no common upper bound, nor do
$u,v$
 have no common upper bound, nor do 
 $x(N)$
 and
$x(N)$
 and 
 $y(N)$
; so
$y(N)$
; so 
 ${s(\rho ) \not = s(\tau )}$
 for all
${s(\rho ) \not = s(\tau )}$
 for all 
 $\rho \in x(N)\Gamma $
 and
$\rho \in x(N)\Gamma $
 and 
 $\tau \in y(N)\Gamma $
.
$\tau \in y(N)\Gamma $
.
Remark 4.9. Lemma 4.7 gels with [Reference Kumjian and Pask25, Proposition 4.3]: if E is a simply connected row-finite source-free directed graph, then 
 $E^\infty /\mathcal {G}_E$
 is Hausdorff. We prove the contrapositive. Suppose that
$E^\infty /\mathcal {G}_E$
 is Hausdorff. We prove the contrapositive. Suppose that 
 $E^\infty /\mathcal {G}_E$
 is not Hausdorff. Since E is a
$E^\infty /\mathcal {G}_E$
 is not Hausdorff. Since E is a 
 $1$
-graph,
$1$
-graph, 
 $i : E^* \to \Pi (E^*)$
 is injective. Corollary 4.7 gives
$i : E^* \to \Pi (E^*)$
 is injective. Corollary 4.7 gives 
 $x,y \in E^\infty $
 such that
$x,y \in E^\infty $
 such that 
 $\sigma ^m(x) \not = \sigma ^n(y)$
 for all
$\sigma ^m(x) \not = \sigma ^n(y)$
 for all 
 $m,n$
, and, for all
$m,n$
, and, for all 
 $N \ge 0$
,
$N \ge 0$
, 
 $\rho _N \in x(N)E^*$
 and
$\rho _N \in x(N)E^*$
 and 
 $\tau _N \in y(N) E^*$
 such that
$\tau _N \in y(N) E^*$
 such that 
 $s(\rho _N) = s(\tau _N) =: w_N$
. We first claim that there exists
$s(\rho _N) = s(\tau _N) =: w_N$
. We first claim that there exists 
 $N_0$
 such that
$N_0$
 such that 
 $x(n) \not = y(m)$
 for all
$x(n) \not = y(m)$
 for all 
 $m,n \ge N_0$
. To see this, suppose that there are increasing sequences
$m,n \ge N_0$
. To see this, suppose that there are increasing sequences 
 $(n_i), (m_i)$
 such that
$(n_i), (m_i)$
 such that 
 $x(n_i) = y(m_i)$
 for all i. Since E is singly connected,
$x(n_i) = y(m_i)$
 for all i. Since E is singly connected, 
 $x(n_i, n_{i+1}) = y(m_i, m_{i+1})$
 for all i; so
$x(n_i, n_{i+1}) = y(m_i, m_{i+1})$
 for all i; so 
 $\sigma ^{n_0}(x) = \sigma ^{n_0}(y)$
, which is a contradiction. So by replacing
$\sigma ^{n_0}(x) = \sigma ^{n_0}(y)$
, which is a contradiction. So by replacing 
 $x, y$
 with
$x, y$
 with 
 $\sigma ^{N_0}(x)$
 and
$\sigma ^{N_0}(x)$
 and 
 $\sigma ^{N_0}(y)$
, we may assume that
$\sigma ^{N_0}(y)$
, we may assume that 
 $x(m) \not = y(n)$
 for all
$x(m) \not = y(n)$
 for all 
 $m,n$
.
$m,n$
.
 Hence, each 
 $w_N$
 is on exactly one of
$w_N$
 is on exactly one of 
 $x, y$
; without loss of generality,
$x, y$
; without loss of generality, 
 $w_0$
 is not on x. Let
$w_0$
 is not on x. Let 
 $\alpha = x(0, |\rho _0|)$
 and
$\alpha = x(0, |\rho _0|)$
 and 
 $\beta = y(0, |\tau _0|)$
. Then
$\beta = y(0, |\tau _0|)$
. Then 
 $\rho _0^{-1}\alpha \rho _{|\rho _0|}\tau _{|\tau _0|}^{-1}\beta ^{-1}\tau _0 \in (\Pi (E))^{w_0}_{w_0}$
. We show that
$\rho _0^{-1}\alpha \rho _{|\rho _0|}\tau _{|\tau _0|}^{-1}\beta ^{-1}\tau _0 \in (\Pi (E))^{w_0}_{w_0}$
. We show that 
 $\rho _0^{-1}\alpha \rho _{|\rho _0|}\tau _{|\tau _0|}^{-1}\beta ^{-1}\tau _0 \not = w_0$
. Since
$\rho _0^{-1}\alpha \rho _{|\rho _0|}\tau _{|\tau _0|}^{-1}\beta ^{-1}\tau _0 \not = w_0$
. Since 
 $r(\rho _{|\rho _0|}) = x(|\rho _0|) \not = y(|\tau _0|) = r(\tau _{|\tau _0|})$
 in reduced form [Reference Higgins20, Proposition 4.9],
$r(\rho _{|\rho _0|}) = x(|\rho _0|) \not = y(|\tau _0|) = r(\tau _{|\tau _0|})$
 in reduced form [Reference Higgins20, Proposition 4.9], 
 $\rho _{|\rho _0|} \tau _{|\tau _0|}^{-1} = e \gamma \lambda ^{-1}$
, where
$\rho _{|\rho _0|} \tau _{|\tau _0|}^{-1} = e \gamma \lambda ^{-1}$
, where 
 $e \in E^1$
 is the first edge of
$e \in E^1$
 is the first edge of 
 $\rho _{|\rho _0|}$
. Similarly, since
$\rho _{|\rho _0|}$
. Similarly, since 
 $w_0 = s(\tau _0) \not = x(|\rho _0|) = s(\alpha )$
 in reduced form,
$w_0 = s(\tau _0) \not = x(|\rho _0|) = s(\alpha )$
 in reduced form, 
 $\rho _0^{-1}\alpha = \zeta ^{-1}\eta f$
, where f is the last edge of
$\rho _0^{-1}\alpha = \zeta ^{-1}\eta f$
, where f is the last edge of 
 $\alpha $
 and
$\alpha $
 and 
 $\zeta ,\eta \in E^*$
. So in reduced form,
$\zeta ,\eta \in E^*$
. So in reduced form, 
 $\rho _0^{-1}\alpha \rho _{|\rho _0|}\tau _{|\tau _0|}^{-1} = \zeta ^{-1} \eta f e \gamma \lambda ^{-1}$
. In particular, the word
$\rho _0^{-1}\alpha \rho _{|\rho _0|}\tau _{|\tau _0|}^{-1} = \zeta ^{-1} \eta f e \gamma \lambda ^{-1}$
. In particular, the word 
 $fe$
 appears in the reduced form of
$fe$
 appears in the reduced form of 
 $\rho _0^{-1}\alpha \rho _{|\rho _0|}\tau _{|\tau _0|}^{-1}\beta ^{-1}\tau _0$
, so this is a nontrivial element of
$\rho _0^{-1}\alpha \rho _{|\rho _0|}\tau _{|\tau _0|}^{-1}\beta ^{-1}\tau _0$
, so this is a nontrivial element of 
 $(\Pi (E))^{w_0}_{w_0}$
. Hence, E is not simply connected.
$(\Pi (E))^{w_0}_{w_0}$
. Hence, E is not simply connected.
Remark 4.10. The argument of the preceding remark does not go through for k-graphs because there is no canonical reduced form for elements of the fundamental groupoid of a k-graph.
 For 
 $1$
-graphs
$1$
-graphs 
 $E^*$
, we can use Remark 4.9 to check Hausdorffness of
$E^*$
, we can use Remark 4.9 to check Hausdorffness of 
 $E^\infty /\mathcal {G}_E \cong C^*(E^*)^{\wedge }$
. So it helps to relate Hausdorffness of the orbit space of a k-graph to that of a natural sub-
$E^\infty /\mathcal {G}_E \cong C^*(E^*)^{\wedge }$
. So it helps to relate Hausdorffness of the orbit space of a k-graph to that of a natural sub-
 $1$
-graph
$1$
-graph
Proposition 4.11. Let 
 $\Gamma $
 be a row-finite source-free k-graph. Suppose that
$\Gamma $
 be a row-finite source-free k-graph. Suppose that 
 $\Gamma $
 is simply connected. Then
$\Gamma $
 is simply connected. Then 
 $\Gamma ^\infty /\mathcal {G}_\Gamma $
 is Hausdorff if and only if
$\Gamma ^\infty /\mathcal {G}_\Gamma $
 is Hausdorff if and only if 
 $(\Gamma ^{\mathbb {N}\mathbf {1}})^\infty /\mathcal {G}_{\Gamma ^{\mathbb {N}\mathbf {1}}}$
 is Hausdorff.
$(\Gamma ^{\mathbb {N}\mathbf {1}})^\infty /\mathcal {G}_{\Gamma ^{\mathbb {N}\mathbf {1}}}$
 is Hausdorff.
 To prove this, we show that 
 $\Gamma ^\infty /\mathcal {G}_\Gamma $
 is homeomorphic to a clopen subset of
$\Gamma ^\infty /\mathcal {G}_\Gamma $
 is homeomorphic to a clopen subset of 
 $(\Gamma ^{\mathbb {N}\mathbf {1}})^\infty /\mathcal {G}_{\Gamma ^{\mathbb {N}\mathbf {1}}}$
.
$(\Gamma ^{\mathbb {N}\mathbf {1}})^\infty /\mathcal {G}_{\Gamma ^{\mathbb {N}\mathbf {1}}}$
.
Lemma 4.12. Let 
 $\Gamma $
 be a row-finite source-free k-graph. Suppose that
$\Gamma $
 be a row-finite source-free k-graph. Suppose that 
 $\Gamma $
 is simply connected. Let
$\Gamma $
 is simply connected. Let 
 $f : \Gamma ^0 \to \mathbb {Z}^k$
 be a function such that
$f : \Gamma ^0 \to \mathbb {Z}^k$
 be a function such that 
 $d(\lambda ) = f(s(\lambda )) - f(r(\lambda ))$
 for all
$d(\lambda ) = f(s(\lambda )) - f(r(\lambda ))$
 for all 
 $\lambda \in \Gamma $
 as in Proposition 4.2. Let E be the directed graph such that
$\lambda \in \Gamma $
 as in Proposition 4.2. Let E be the directed graph such that 
 $E^0 = f^{-1}(\mathbb {Z}\mathbf {1})$
 and
$E^0 = f^{-1}(\mathbb {Z}\mathbf {1})$
 and 
 $E^1 = E^0 \Gamma ^{\mathbf {1}}$
. Let
$E^1 = E^0 \Gamma ^{\mathbf {1}}$
. Let 
 $j : E^\infty \to \Gamma ^\infty $
 be the map such that
$j : E^\infty \to \Gamma ^\infty $
 be the map such that 
 $j(x)$
 is the unique infinite path such that
$j(x)$
 is the unique infinite path such that 
 $j(x)(0, n\cdot \mathbf {1}) = x_1 x_2\cdots x_n$
 for all
$j(x)(0, n\cdot \mathbf {1}) = x_1 x_2\cdots x_n$
 for all 
 $n \in \mathbb {N}$
 (see [Reference Kumjian and Pask26, Remark 2.2]). Then j descends to a homeomorphism
$n \in \mathbb {N}$
 (see [Reference Kumjian and Pask26, Remark 2.2]). Then j descends to a homeomorphism 
 $\widetilde {j} : E^\infty /\mathcal {G}_E \to \Gamma ^\infty /\mathcal {G}_\Gamma $
.
$\widetilde {j} : E^\infty /\mathcal {G}_E \to \Gamma ^\infty /\mathcal {G}_\Gamma $
.
Proof. The map j restricts to a homeomorphism 
 $vE^\infty \to v\Gamma ^\infty $
 for each
$vE^\infty \to v\Gamma ^\infty $
 for each 
 $v \in E^0$
, so is continuous.
$v \in E^0$
, so is continuous.
 We claim that if 
 $x,y \in E^\infty $
, then
$x,y \in E^\infty $
, then 
 $j(x) \sim _{\mathcal {G}_\Gamma } j(y)$
 if and only if
$j(x) \sim _{\mathcal {G}_\Gamma } j(y)$
 if and only if 
 $x \sim _{\mathcal {G}_E} y$
. To see this, fix
$x \sim _{\mathcal {G}_E} y$
. To see this, fix 
 $x,y \in E^\infty $
. Then
$x,y \in E^\infty $
. Then 
 $j(x) \sim _{\mathcal {G}_\Gamma } j(y)$
 if and only if there exist
$j(x) \sim _{\mathcal {G}_\Gamma } j(y)$
 if and only if there exist 
 $m,n \in \mathbb {N}^k$
 such that
$m,n \in \mathbb {N}^k$
 such that 
 $\sigma ^m(j(x)) = \sigma ^n(j(y))$
. Since
$\sigma ^m(j(x)) = \sigma ^n(j(y))$
. Since 
 $f(r(\sigma ^m(j(x)))) = f(r(x)) + m$
 for all
$f(r(\sigma ^m(j(x)))) = f(r(x)) + m$
 for all 
 $m \in \mathbb {N}^k$
 and similarly for y, and since
$m \in \mathbb {N}^k$
 and similarly for y, and since 
 $f(r(x)), f(r(y)) \in \mathbb {Z}\mathbf {1}$
, we deduce that
$f(r(x)), f(r(y)) \in \mathbb {Z}\mathbf {1}$
, we deduce that 
 $j(x) \sim _{\mathcal {G}_\Gamma } j(y)$
 if and only if there exist
$j(x) \sim _{\mathcal {G}_\Gamma } j(y)$
 if and only if there exist 
 $m,n \in \mathbb {N}^k$
 such that
$m,n \in \mathbb {N}^k$
 such that 
 $\sigma ^m(j(x)) = \sigma ^n(j(y))$
 and
$\sigma ^m(j(x)) = \sigma ^n(j(y))$
 and 
 $m - n \in \mathbb {Z}\mathbf {1}$
. Since
$m - n \in \mathbb {Z}\mathbf {1}$
. Since 
 $m - n \in \mathbb {Z}\mathbf {1}$
 if and only if there exists
$m - n \in \mathbb {Z}\mathbf {1}$
 if and only if there exists 
 $p \in \mathbb {N}^k$
 such that
$p \in \mathbb {N}^k$
 such that 
 $m+p, n+p \in \mathbb {N}\mathbf {1}$
, we deduce that
$m+p, n+p \in \mathbb {N}\mathbf {1}$
, we deduce that 
 $j(x) \sim _{\mathcal {G}_\Gamma } j(y)$
 if and only if
$j(x) \sim _{\mathcal {G}_\Gamma } j(y)$
 if and only if 
 $\sigma ^{a\mathbf {1}}(j(x)) = \sigma ^{b\mathbf {1}}(j(y))$
 for some
$\sigma ^{a\mathbf {1}}(j(x)) = \sigma ^{b\mathbf {1}}(j(y))$
 for some 
 $a,b \in \mathbb {N}$
; that is, if and only if
$a,b \in \mathbb {N}$
; that is, if and only if 
 $\sigma ^a(x) = \sigma ^b(y)$
 for some
$\sigma ^a(x) = \sigma ^b(y)$
 for some 
 $a,b \in \mathbb {N}$
. Hence,
$a,b \in \mathbb {N}$
. Hence, 
 $j(x) \sim _{\mathcal {G}_\Gamma } j(y)$
 if and only if
$j(x) \sim _{\mathcal {G}_\Gamma } j(y)$
 if and only if 
 $x \sim _{\mathcal {G}_E} y$
. It follows that j descends to a continuous function
$x \sim _{\mathcal {G}_E} y$
. It follows that j descends to a continuous function 
 $\widetilde {j} : E^\infty /\mathcal {G}_E \to \Gamma ^\infty /\mathcal {G}_\Gamma $
.
$\widetilde {j} : E^\infty /\mathcal {G}_E \to \Gamma ^\infty /\mathcal {G}_\Gamma $
.
 Fix 
 $p : \Gamma ^0 \to \mathbb {N}^k$
 satisfying
$p : \Gamma ^0 \to \mathbb {N}^k$
 satisfying 
 $f(v) + p(v) \in \mathbb {Z}\mathbf {1}$
 for all v. For
$f(v) + p(v) \in \mathbb {Z}\mathbf {1}$
 for all v. For 
 $x \in \Gamma ^\infty $
 and
$x \in \Gamma ^\infty $
 and 
 $j \in \mathbb {N}$
, let
$j \in \mathbb {N}$
, let 
 $\tilde {x}_j := \sigma ^{p(r(x))}((j-1)\mathbf {1}, j\mathbf {1}) \in E^1$
 and define
$\tilde {x}_j := \sigma ^{p(r(x))}((j-1)\mathbf {1}, j\mathbf {1}) \in E^1$
 and define 
 $h(x) := \tilde {x}_1 \tilde {x}_2 \cdots \tilde {x}_n \cdots \in E^\infty $
. As
$h(x) := \tilde {x}_1 \tilde {x}_2 \cdots \tilde {x}_n \cdots \in E^\infty $
. As 
 $x \mapsto p(r(x))$
 is locally constant, h is continuous. Since
$x \mapsto p(r(x))$
 is locally constant, h is continuous. Since 
 $\sigma ^{p(x)}(x) \sim _{\mathcal {G}_\Gamma } x$
 for all x, the claim above shows that
$\sigma ^{p(x)}(x) \sim _{\mathcal {G}_\Gamma } x$
 for all x, the claim above shows that 
 $x \sim _{\mathcal {G}_\Gamma } y$
 if and only if
$x \sim _{\mathcal {G}_\Gamma } y$
 if and only if 
 $h(x) \sim _{\mathcal {G}_E} h(y)$
, so h descends to a continuous function
$h(x) \sim _{\mathcal {G}_E} h(y)$
, so h descends to a continuous function 
 $\tilde {h} : \Gamma ^\infty /\mathcal {G}_\Gamma \to E^\infty /\mathcal {G}_E$
. It is routine to check that
$\tilde {h} : \Gamma ^\infty /\mathcal {G}_\Gamma \to E^\infty /\mathcal {G}_E$
. It is routine to check that 
 $\tilde {h}$
 and
$\tilde {h}$
 and 
 $\tilde {j}$
 are mutually inverse:
$\tilde {j}$
 are mutually inverse: 
 $h \circ j = \operatorname {id}_{E^\infty }$
 and
$h \circ j = \operatorname {id}_{E^\infty }$
 and 
 $[j \circ h(x)] = [\sigma ^{p(x)}(x)] = [x]$
 for all
$[j \circ h(x)] = [\sigma ^{p(x)}(x)] = [x]$
 for all 
 $x \in \Gamma ^\infty $
. In particular, j descends to a homeomorphism as claimed.
$x \in \Gamma ^\infty $
. In particular, j descends to a homeomorphism as claimed.
Proof of Proposition 4.11.
 Resume the notation of Lemma 4.12. It suffices for us to show that 
 $(\Gamma ^{\mathbb {N}\mathbf {1}})^\infty /\mathcal {G}_{\Gamma ^{\mathbb {N}\mathbf {1}}}$
 is Hausdorff if and only if
$(\Gamma ^{\mathbb {N}\mathbf {1}})^\infty /\mathcal {G}_{\Gamma ^{\mathbb {N}\mathbf {1}}}$
 is Hausdorff if and only if 
 $E^\infty /\mathcal {G}_E$
 is Hausdorff.
$E^\infty /\mathcal {G}_E$
 is Hausdorff.
 For 
 $p \in \mathbb {Z}^k$
, let
$p \in \mathbb {Z}^k$
, let 
 $V_p := f^{-1}(p + \mathbb {Z}\mathbf {1}) \subseteq \Gamma ^0$
 (so
$V_p := f^{-1}(p + \mathbb {Z}\mathbf {1}) \subseteq \Gamma ^0$
 (so 
 $V_0$
 is V in Lemma 4.12). If
$V_0$
 is V in Lemma 4.12). If 
 $p-q \not \in \mathbb {Z}\mathbf {1}$
, then
$p-q \not \in \mathbb {Z}\mathbf {1}$
, then 
 $V_p\Gamma ^{\mathbb {N}\mathbf {1}} V_q = \emptyset $
. So if
$V_p\Gamma ^{\mathbb {N}\mathbf {1}} V_q = \emptyset $
. So if 
 $x \in V_p \Gamma ^{\mathbb {N}\mathbf {1}}$
 and
$x \in V_p \Gamma ^{\mathbb {N}\mathbf {1}}$
 and 
 $y \in V_q \Gamma ^{\mathbb {N}\mathbf {1}}$
, then
$y \in V_q \Gamma ^{\mathbb {N}\mathbf {1}}$
, then 
 $\sigma ^{a\mathbf {1}}(x) \not = \sigma ^{b\mathbf {1}}(y)$
 for all
$\sigma ^{a\mathbf {1}}(x) \not = \sigma ^{b\mathbf {1}}(y)$
 for all 
 $a,b \in \mathbb {N}$
 and hence,
$a,b \in \mathbb {N}$
 and hence, 
 $[x]_{\mathcal {G}_{\Gamma ^{\mathbb {N}\mathbf {1}}}} \not = [y]_{\mathcal {G}_{\Gamma ^{\mathbb {N}\mathbf {1}}}}$
. Hence, the sets
$[x]_{\mathcal {G}_{\Gamma ^{\mathbb {N}\mathbf {1}}}} \not = [y]_{\mathcal {G}_{\Gamma ^{\mathbb {N}\mathbf {1}}}}$
. Hence, the sets 
 $\big \{V_p (\Gamma ^{\mathbb {N}\mathbf {1}})^{\infty } : p \in \mathbb {Z}^{k-1} \times \{0\}\big \}$
 have mutually disjoint open images in
$\big \{V_p (\Gamma ^{\mathbb {N}\mathbf {1}})^{\infty } : p \in \mathbb {Z}^{k-1} \times \{0\}\big \}$
 have mutually disjoint open images in 
 $(\Gamma ^{\mathbb {N}\mathbf {1}})^\infty /\mathcal {G}_{\Gamma ^{\mathbb {N}\mathbf {1}}}$
. So it suffices to show that each of these images is Hausdorff.
$(\Gamma ^{\mathbb {N}\mathbf {1}})^\infty /\mathcal {G}_{\Gamma ^{\mathbb {N}\mathbf {1}}}$
. So it suffices to show that each of these images is Hausdorff.
 Let 
 $q : (\Gamma ^{\mathbb {N}\mathbf {1}})^\infty \to (\Gamma ^{\mathbb {N}\mathbf {1}})^\infty /\mathcal {G}_{\Gamma ^{\mathbb {N}\mathbf {1}}}$
 be the quotient map. By assumption,
$q : (\Gamma ^{\mathbb {N}\mathbf {1}})^\infty \to (\Gamma ^{\mathbb {N}\mathbf {1}})^\infty /\mathcal {G}_{\Gamma ^{\mathbb {N}\mathbf {1}}}$
 be the quotient map. By assumption, 
 $E^\infty /\mathcal {G}_E = q(V_0 (\Gamma ^{\mathbb {N}\mathbf {1}})^{\infty })$
 is Hausdorff, so it suffices to fix
$E^\infty /\mathcal {G}_E = q(V_0 (\Gamma ^{\mathbb {N}\mathbf {1}})^{\infty })$
 is Hausdorff, so it suffices to fix 
 $p \in \mathbb {Z}^{k-1} \setminus \{0\}$
 and show that
$p \in \mathbb {Z}^{k-1} \setminus \{0\}$
 and show that 
 $(q(V_p\Gamma ^{\mathbb {N}\mathbf {1}})^\infty ) \cong (q(V_0\Gamma ^{\mathbb {N}\mathbf {1}})^\infty )$
.
$(q(V_p\Gamma ^{\mathbb {N}\mathbf {1}})^\infty ) \cong (q(V_0\Gamma ^{\mathbb {N}\mathbf {1}})^\infty )$
.
 Since 
 $V_p = V_{p + a\mathbf {1}}$
 for all
$V_p = V_{p + a\mathbf {1}}$
 for all 
 $a \in \mathbb {N}$
, we may assume that
$a \in \mathbb {N}$
, we may assume that 
 $p \ge 0$
. Fix
$p \ge 0$
. Fix 
 $n \in \mathbb {N}^k$
 such that
$n \in \mathbb {N}^k$
 such that 
 $p + n \in \mathbb {Z}\mathbf {1}$
. Then
$p + n \in \mathbb {Z}\mathbf {1}$
. Then 
 $\sigma ^p : V_0 \Gamma ^\infty \to V_p\Gamma ^\infty $
 and
$\sigma ^p : V_0 \Gamma ^\infty \to V_p\Gamma ^\infty $
 and 
 $\sigma ^n : V_p \Gamma ^\infty \to V_{p+n}\Gamma ^\infty = V_0\Gamma ^\infty $
 are continuous. Using [Reference Kumjian and Pask26, Remark 2.2], we can identify
$\sigma ^n : V_p \Gamma ^\infty \to V_{p+n}\Gamma ^\infty = V_0\Gamma ^\infty $
 are continuous. Using [Reference Kumjian and Pask26, Remark 2.2], we can identify 
 $V_p \Gamma ^\infty $
 with
$V_p \Gamma ^\infty $
 with 
 $V_p(\Gamma ^{\mathbb {N}\mathbf {1}})^\infty $
 and
$V_p(\Gamma ^{\mathbb {N}\mathbf {1}})^\infty $
 and 
 $V_0 \Gamma ^\infty $
 with
$V_0 \Gamma ^\infty $
 with 
 $V_0 (\Gamma ^{\mathbb {N}\mathbf {1}})^\infty $
, and these identifications are compatible with the shift maps.
$V_0 (\Gamma ^{\mathbb {N}\mathbf {1}})^\infty $
, and these identifications are compatible with the shift maps.
 If 
 $x \sim _{\mathcal {G}_{\Gamma ^{\mathbb {N}\mathbf {1}}}} y$
, then
$x \sim _{\mathcal {G}_{\Gamma ^{\mathbb {N}\mathbf {1}}}} y$
, then 
 $\sigma ^p(x) \sim _{\mathcal {G}_{\Gamma ^{\mathbb {N}\mathbf {1}}}} \sigma ^p(y)$
 and similarly for n, so
$\sigma ^p(x) \sim _{\mathcal {G}_{\Gamma ^{\mathbb {N}\mathbf {1}}}} \sigma ^p(y)$
 and similarly for n, so 
 $\sigma ^p$
 and
$\sigma ^p$
 and 
 $\sigma ^n$
 descend to continuous maps
$\sigma ^n$
 descend to continuous maps 
 $\tilde \sigma ^p : q(V_0\Gamma ^{\mathbb {N}\mathbf {1}})^\infty \to q(V_p\Gamma ^{\mathbb {N}\mathbf {1}})^\infty $
 and
$\tilde \sigma ^p : q(V_0\Gamma ^{\mathbb {N}\mathbf {1}})^\infty \to q(V_p\Gamma ^{\mathbb {N}\mathbf {1}})^\infty $
 and 
 $\tilde \sigma ^n : q(V_p\Gamma ^{\mathbb {N}\mathbf {1}})^\infty \to q(V_0\Gamma ^{\mathbb {N}\mathbf {1}})^\infty $
. Since
$\tilde \sigma ^n : q(V_p\Gamma ^{\mathbb {N}\mathbf {1}})^\infty \to q(V_0\Gamma ^{\mathbb {N}\mathbf {1}})^\infty $
. Since 
 $x \sim _{\mathcal {G}_{\Gamma ^{\mathbb {N}\mathbf {1}}}} \sigma ^{p+n}(x) = \sigma ^p(\sigma ^n(x))$
, we see that
$x \sim _{\mathcal {G}_{\Gamma ^{\mathbb {N}\mathbf {1}}}} \sigma ^{p+n}(x) = \sigma ^p(\sigma ^n(x))$
, we see that 
 $\tilde \sigma ^p \circ \tilde \sigma ^n$
 is the identity map on
$\tilde \sigma ^p \circ \tilde \sigma ^n$
 is the identity map on 
 $q(V_p\Gamma ^{\mathbb {N}\mathbf {1}})^\infty $
 and, similarly,
$q(V_p\Gamma ^{\mathbb {N}\mathbf {1}})^\infty $
 and, similarly, 
 $\tilde \sigma ^p \circ \tilde \sigma ^n$
 is the identity map on
$\tilde \sigma ^p \circ \tilde \sigma ^n$
 is the identity map on 
 $q(V_0\Gamma ^{\mathbb {N}\mathbf {1}})^\infty $
. So
$q(V_0\Gamma ^{\mathbb {N}\mathbf {1}})^\infty $
. So 
 $\tilde \sigma ^p$
 and
$\tilde \sigma ^p$
 and 
 $\tilde \sigma ^n$
 are mutually inverse and hence homeomorphisms.
$\tilde \sigma ^n$
 are mutually inverse and hence homeomorphisms.
Corollary 4.13. Let 
 $\Gamma $
 be a row-finite source-free k-graph. Suppose that both
$\Gamma $
 be a row-finite source-free k-graph. Suppose that both 
 $\Gamma $
 and the sub-
$\Gamma $
 and the sub-
 $1$
-graph
$1$
-graph 
 $\Gamma ^{\mathbb {N}\mathbf {1}}$
 are simply connected. Then
$\Gamma ^{\mathbb {N}\mathbf {1}}$
 are simply connected. Then 
 $\Gamma ^\infty /\mathcal {G}_\Gamma $
 is Hausdorff.
$\Gamma ^\infty /\mathcal {G}_\Gamma $
 is Hausdorff.
Proof. Proposition 4.2 gives 
 $f: \Gamma ^0 \to \mathbb {Z}^k$
 such that
$f: \Gamma ^0 \to \mathbb {Z}^k$
 such that 
 $d(\lambda ) = f(s(\lambda )) - f(r(\lambda ))$
 for all
$d(\lambda ) = f(s(\lambda )) - f(r(\lambda ))$
 for all 
 $\lambda \in \Gamma $
. Let E be the directed graph such that
$\lambda \in \Gamma $
. Let E be the directed graph such that 
 $E^0 = f^{-1}(\mathbb {Z}\mathbf {1})$
 and
$E^0 = f^{-1}(\mathbb {Z}\mathbf {1})$
 and 
 $E^1 = E^0 \Gamma ^{\mathbf {1}}$
. Lemma 4.12 gives
$E^1 = E^0 \Gamma ^{\mathbf {1}}$
. Lemma 4.12 gives 
 $\Gamma ^\infty /\mathcal {G}_\Gamma \cong E^\infty /\mathcal {G}_E$
. Since
$\Gamma ^\infty /\mathcal {G}_\Gamma \cong E^\infty /\mathcal {G}_E$
. Since 
 $E^*$
 is a sub-1-graph of the simply connected graph
$E^*$
 is a sub-1-graph of the simply connected graph 
 $\Gamma ^{\mathbb {N} \mathbf {1}}$
, it is simply connected. Hence,
$\Gamma ^{\mathbb {N} \mathbf {1}}$
, it is simply connected. Hence, 
 $E^\infty /\mathcal {G}_E$
 is Hausdorff by [Reference Kumjian and Pask25, Lemma 4.2] (see Remark 4.9) and thus,
$E^\infty /\mathcal {G}_E$
 is Hausdorff by [Reference Kumjian and Pask25, Lemma 4.2] (see Remark 4.9) and thus, 
 $\Gamma ^\infty /\mathcal {G}_\Gamma $
 is Hausdorff.
$\Gamma ^\infty /\mathcal {G}_\Gamma $
 is Hausdorff.
Example 4.14. Surprisingly, simple connectedness of 
 $\Gamma $
 and of
$\Gamma $
 and of 
 $\Gamma ^{\mathbb {N}\mathbf {1}}$
 are independent conditions. For the monoidal
$\Gamma ^{\mathbb {N}\mathbf {1}}$
 are independent conditions. For the monoidal 
 $2$
-graph
$2$
-graph 
 $\Lambda $
 of [Reference Pask, Raeburn and Quigg32, Example 7.1] (Example 3.1), we have an isomorphism
$\Lambda $
 of [Reference Pask, Raeburn and Quigg32, Example 7.1] (Example 3.1), we have an isomorphism 
 $\Pi (\Lambda ) \cong \mathbb {Z}^2$
 that intertwines
$\Pi (\Lambda ) \cong \mathbb {Z}^2$
 that intertwines 
 $i : \Lambda \to \Pi (\Lambda )$
 with
$i : \Lambda \to \Pi (\Lambda )$
 with 
 ${d : \Lambda \to \mathbb {N}^2 \subseteq \mathbb {Z}^2}$
. So
${d : \Lambda \to \mathbb {N}^2 \subseteq \mathbb {Z}^2}$
. So 
 $\Gamma := \mathbb {Z}^2 \times _d \Lambda \cong \pi ( \Lambda ) \times _i \Lambda $
 is simply connected. However,
$\Gamma := \mathbb {Z}^2 \times _d \Lambda \cong \pi ( \Lambda ) \times _i \Lambda $
 is simply connected. However, 
 $\Gamma ^{\mathbb {N}\mathbf {1}}$
 is the graph with vertices
$\Gamma ^{\mathbb {N}\mathbf {1}}$
 is the graph with vertices 
 $\{v_m : m \in \mathbb {Z}^2\}$
 and six parallel edges from
$\{v_m : m \in \mathbb {Z}^2\}$
 and six parallel edges from 
 $v_{m + \mathbf {1}}$
 to
$v_{m + \mathbf {1}}$
 to 
 $v_m$
 for each
$v_m$
 for each 
 ${m \in \mathbb {Z}^2}$
, so is not simply connected. In the other direction, let
${m \in \mathbb {Z}^2}$
, so is not simply connected. In the other direction, let 
 $\Delta _1$
 be the
$\Delta _1$
 be the 
 $1$
-graph with vertices
$1$
-graph with vertices 
 $\mathbb {Z}$
 and edges
$\mathbb {Z}$
 and edges 
 $e_n$
 with
$e_n$
 with 
 $s(e_n) = n+1$
 and
$s(e_n) = n+1$
 and 
 $r(e_n) = n$
, and define
$r(e_n) = n$
, and define 
 $l : \mathbb {N}^2 \to \mathbb {N}$
 by
$l : \mathbb {N}^2 \to \mathbb {N}$
 by 
 $l(m,n) = m+n$
. Then the
$l(m,n) = m+n$
. Then the 
 $2$
-graph
$2$
-graph 
 $\Gamma := l^*(\Omega _1)$
 has fundamental group
$\Gamma := l^*(\Omega _1)$
 has fundamental group 
 $\mathbb {Z}$
 generated by
$\mathbb {Z}$
 generated by 
 $(e_0, (1,0))(e_0, (0,1))^{-1}$
, so is not simply connected, but
$(e_0, (1,0))(e_0, (0,1))^{-1}$
, so is not simply connected, but 
 $\Gamma ^{\mathbb {N}\mathbf {1}}$
 is a disjoint union of copies of
$\Gamma ^{\mathbb {N}\mathbf {1}}$
 is a disjoint union of copies of 
 $\Omega _1$
, so is simply connected.
$\Omega _1$
, so is simply connected.
Remark 4.15. In the context of Corollary 4.13, simple connectedness of 
 $\Gamma ^{\mathbb {N}\mathbf {1}}$
 is equivalent to that of
$\Gamma ^{\mathbb {N}\mathbf {1}}$
 is equivalent to that of 
 $E^*$
 as in Lemma 4.12. Also, as in the proof of Proposition 4.11, the orbit space
$E^*$
 as in Lemma 4.12. Also, as in the proof of Proposition 4.11, the orbit space 
 $(\Gamma ^{\mathbb {N}\mathbf {1}})^\infty / \mathcal {G}_{\Gamma ^{\mathbb {N}\mathbf {1}}}$
 is a topological disjoint union of copies of
$(\Gamma ^{\mathbb {N}\mathbf {1}})^\infty / \mathcal {G}_{\Gamma ^{\mathbb {N}\mathbf {1}}}$
 is a topological disjoint union of copies of 
 $E^\infty /\mathcal {G}_E$
 indexed
$E^\infty /\mathcal {G}_E$
 indexed 
 $\mathbb {Z}^k/\mathbb {Z}\mathbf {1}$
.
$\mathbb {Z}^k/\mathbb {Z}\mathbf {1}$
.
Proof of Theorem 4.1(iii).
 As in the proof of part (ii), since 
 $\Lambda \to \Pi (\Lambda )$
 is injective,
$\Lambda \to \Pi (\Lambda )$
 is injective, 
 $\Sigma $
 is singly connected, and
$\Sigma $
 is singly connected, and 
 $C^*(\Sigma )$
 is type I
$C^*(\Sigma )$
 is type I
 $_0$
. The proof of Proposition 4.4 shows that
$_0$
. The proof of Proposition 4.4 shows that 
 $\mathcal {G}_\Sigma $
 has trivial isotropy. Hence, the spectrum of
$\mathcal {G}_\Sigma $
 has trivial isotropy. Hence, the spectrum of 
 $C^*(\Sigma )$
 is homeomorphic to the orbit space
$C^*(\Sigma )$
 is homeomorphic to the orbit space 
 $\Sigma ^\infty /\mathcal {G}_\Sigma $
 [Reference Clark11, Corollary 4.2]. Now, since
$\Sigma ^\infty /\mathcal {G}_\Sigma $
 [Reference Clark11, Corollary 4.2]. Now, since 
 $\Sigma ^{\mathbb {N}\mathbf {1}}$
 is simply connected, Corollary 4.13 implies that
$\Sigma ^{\mathbb {N}\mathbf {1}}$
 is simply connected, Corollary 4.13 implies that 
 $\Sigma ^\infty /\mathcal {G}_\Sigma $
 is Hausdorff. So
$\Sigma ^\infty /\mathcal {G}_\Sigma $
 is Hausdorff. So 
 $C^*(\Sigma )$
 is a continuous-trace
$C^*(\Sigma )$
 is a continuous-trace 
 $C^*$
-algebra. Since
$C^*$
-algebra. Since 
 $X := \Sigma ^\infty /\mathcal {G}_\Sigma $
 is zero-dimensional,
$X := \Sigma ^\infty /\mathcal {G}_\Sigma $
 is zero-dimensional, 
 $\check {H}_3(X, \mathbb {Z}) = \{0\}$
, and hence the Dixmier–Douady invariant
$\check {H}_3(X, \mathbb {Z}) = \{0\}$
, and hence the Dixmier–Douady invariant 
 $\delta (C^*(\Sigma )) \in \check {H}_3(X, \mathbb {Z})$
 is trivial. So by the Dixmier–Douady theorem [Reference Raeburn and Williams37, Corollary 5.58],
$\delta (C^*(\Sigma )) \in \check {H}_3(X, \mathbb {Z})$
 is trivial. So by the Dixmier–Douady theorem [Reference Raeburn and Williams37, Corollary 5.58], 
 $C^*(\Sigma )$
 is Rieffel–Morita equivalent to
$C^*(\Sigma )$
 is Rieffel–Morita equivalent to 
 $C(\Sigma ^\infty /\mathcal {G}_\Sigma )$
.
$C(\Sigma ^\infty /\mathcal {G}_\Sigma )$
.
Remark 4.16. A related realisation of 
 $C^*$
-algebras of k-graphs (and more general categories) as crossed products of abelian algebras by partial actions of their fundamental groups appears in [Reference Brix, Bruce and Dor On7, Theorem 4.17]. Interestingly, embeddability also crops up there for different reasons.
$C^*$
-algebras of k-graphs (and more general categories) as crossed products of abelian algebras by partial actions of their fundamental groups appears in [Reference Brix, Bruce and Dor On7, Theorem 4.17]. Interestingly, embeddability also crops up there for different reasons.
Remark 4.17. It seems hard to nail down the relationships between the key hypotheses in this section: simple connectedness of 
 $\Gamma $
 and of
$\Gamma $
 and of 
 $\Gamma ^{\mathbb {N}\mathbf {1}}$
, and embedding of
$\Gamma ^{\mathbb {N}\mathbf {1}}$
, and embedding of 
 $\Gamma $
 in
$\Gamma $
 in 
 $\Pi (\Gamma )$
.
$\Pi (\Gamma )$
.
 For example, the following two assertions both seem reasonable: that if 
 $\Gamma $
 is simply connected, then the
$\Gamma $
 is simply connected, then the 
 $\mathbf {1}$
-dual
$\mathbf {1}$
-dual 
 $\mathbf {1}\Gamma $
 obtained from Proposition 2.7 for
$\mathbf {1}\Gamma $
 obtained from Proposition 2.7 for 
 $f : n \mapsto n + \mathbf {1}$
 is also simply connected; and that
$f : n \mapsto n + \mathbf {1}$
 is also simply connected; and that 
 $\mathbf {1}\Gamma $
 always embeds in
$\mathbf {1}\Gamma $
 always embeds in 
 $\Pi (\mathbf {1}\Gamma )$
 (after all,
$\Pi (\mathbf {1}\Gamma )$
 (after all, 
 $\mathbf {1}\Gamma \owns \lambda \mapsto (r(\lambda ), d(\lambda ), s(\lambda ))$
 is injective on
$\mathbf {1}\Gamma \owns \lambda \mapsto (r(\lambda ), d(\lambda ), s(\lambda ))$
 is injective on 
 $\bigcup _{n \le \mathbf {1}} \Gamma ^n$
, and this map descends to
$\bigcup _{n \le \mathbf {1}} \Gamma ^n$
, and this map descends to 
 $\Pi (\Gamma )$
, so the skeleton and factorisation rules are preserved in
$\Pi (\Gamma )$
, so the skeleton and factorisation rules are preserved in 
 $\Pi (\Gamma )$
). However, at most one of these assertions is true in general: consider the skew-product
$\Pi (\Gamma )$
). However, at most one of these assertions is true in general: consider the skew-product 
 $\Gamma := \mathbb {Z}^2 \times _d \Lambda $
 of Example 3.1; we show that if
$\Gamma := \mathbb {Z}^2 \times _d \Lambda $
 of Example 3.1; we show that if 
 $\mathbf {1}\Gamma $
 is simply connected, then it does not embed in
$\mathbf {1}\Gamma $
 is simply connected, then it does not embed in 
 $\Pi (\mathbf {1}\Gamma )$
.
$\Pi (\mathbf {1}\Gamma )$
.
 Since 
 $\mathbf {1}\Gamma $
 is canonically isomorphic to the skew-product
$\mathbf {1}\Gamma $
 is canonically isomorphic to the skew-product 
 $\mathbb {Z}^2 \times _d (\mathbf {1}\Lambda )$
, if
$\mathbb {Z}^2 \times _d (\mathbf {1}\Lambda )$
, if 
 $\mathbf {1}\Gamma $
 is simply connected, then
$\mathbf {1}\Gamma $
 is simply connected, then 
 $\mathbb {Z}^2 \times _d (\mathbf {1}\Lambda )$
 is simply connected, forcing
$\mathbb {Z}^2 \times _d (\mathbf {1}\Lambda )$
 is simply connected, forcing 
 $\pi _1(\Lambda , v) \cong \mathbb {Z}^2$
. However, inspection of the skeleton of
$\pi _1(\Lambda , v) \cong \mathbb {Z}^2$
. However, inspection of the skeleton of 
 $\mathbf {1}\Lambda $
 shows that
$\mathbf {1}\Lambda $
 shows that 
 $eeec$
 and
$eeec$
 and 
 $eedec$
 are distinct blue cycles based at the vertex
$eedec$
 are distinct blue cycles based at the vertex 
 $ec \in \mathbf {1}\Lambda $
, so generate a sub-semigroup of
$ec \in \mathbf {1}\Lambda $
, so generate a sub-semigroup of 
 $\mathbf {1}\Lambda $
 isomorphic to
$\mathbf {1}\Lambda $
 isomorphic to 
 $\mathbb {F}^+_2$
, which cannot embed in
$\mathbb {F}^+_2$
, which cannot embed in 
 $\mathbb {Z}^2$
.
$\mathbb {Z}^2$
.
Remark 4.18. The preceding remark is exemplary of a number of seemingly elementary questions that we have been unable to resolve.
- 
(i) If  $\Gamma $
 is simply connected and embeds in $\Gamma $
 is simply connected and embeds in $\Pi (\Gamma )$
, is $\Pi (\Gamma )$
, is $\Gamma ^\infty /\mathcal {G}_\Gamma $
 Hausdorff? $\Gamma ^\infty /\mathcal {G}_\Gamma $
 Hausdorff?
- 
(ii) If both  $\Gamma $
 and $\Gamma $
 and $\Gamma ^{\mathbb {N}\mathbf {1}}$
 are simply connected, does $\Gamma ^{\mathbb {N}\mathbf {1}}$
 are simply connected, does $\Gamma $
 necessarily embed in $\Gamma $
 necessarily embed in $\Pi (\Gamma )$
? $\Pi (\Gamma )$
?
- 
(iii) Which, if either, of the two assertions mentioned in Remark 4.17 is correct? 
- 
(iv) Does  $\mathbf {1}\Gamma $
 always embed in $\mathbf {1}\Gamma $
 always embed in $\Pi (\mathbf {1}\Gamma )$
? $\Pi (\mathbf {1}\Gamma )$
?
5 
 $\tilde{A_2}$
-groups
$\tilde{A_2}$
-groups
 In this section, we construct coverings 
 $\Sigma _{\mathcal {T}} \to \Lambda _{\mathcal {T}}$
 of
$\Sigma _{\mathcal {T}} \to \Lambda _{\mathcal {T}}$
 of 
 $2$
-graphs corresponding to
$2$
-graphs corresponding to 
 $\tilde {A_2}$
-groups
$\tilde {A_2}$
-groups 
 $\Gamma _{\mathcal {T}}$
. These groups arise from free, vertex-transitive actions on buildings. We show that
$\Gamma _{\mathcal {T}}$
. These groups arise from free, vertex-transitive actions on buildings. We show that 
 $\Sigma _{\mathcal {T}}$
 and
$\Sigma _{\mathcal {T}}$
 and 
 $\Lambda _{\mathcal {T}}$
 both embed in their fundamental groupoids, and that
$\Lambda _{\mathcal {T}}$
 both embed in their fundamental groupoids, and that 
 $\Sigma _{\mathcal {T}}$
 is always singly connected so that its
$\Sigma _{\mathcal {T}}$
 is always singly connected so that its 
 $C^*$
-algebra is of Type I
$C^*$
-algebra is of Type I
 $_0$
.
$_0$
.
 The 
 $\tilde {A_2}$
-groups are built from finite projective planes. A finite projective plane
$\tilde {A_2}$
-groups are built from finite projective planes. A finite projective plane 
 $(P,L)$
 of order q consists of finite sets P of points and L of lines with
$(P,L)$
 of order q consists of finite sets P of points and L of lines with 
 $|P| = |L| = q^2 + q + 1$
, and a relation
$|P| = |L| = q^2 + q + 1$
, and a relation 
 $\in $
 from P to L—if
$\in $
 from P to L—if 
 $p \in l$
, we say p lies on l and that l contains p—such that any two points lie on exactly one common line, any two lines contain exactly one common point and there exist four distinct points of which no single line contains more than two. Each line necessarily contains exactly q points and each point necessarily lies on exactly q lines.
$p \in l$
, we say p lies on l and that l contains p—such that any two points lie on exactly one common line, any two lines contain exactly one common point and there exist four distinct points of which no single line contains more than two. Each line necessarily contains exactly q points and each point necessarily lies on exactly q lines.
We begin with a brief introduction of the groups we wish to study and by collecting some structural results that we need for our construction.
5.1 
 $\tilde{A_2}$
-group basics
$\tilde{A_2}$
-group basics
 Following [Reference Cartwright, Mantero, Steger and Zappa8, Section 2], given a finite projective plane 
 $(P,L)$
 and a bijection
$(P,L)$
 and a bijection 
 $\lambda : P \to L$
, we define a triella compatible with
$\lambda : P \to L$
, we define a triella compatible with 
 $\lambda $
 to be a set
$\lambda $
 to be a set 
 $\mathcal {T} \subset P \times P \times P$
 such that:
$\mathcal {T} \subset P \times P \times P$
 such that: 
- 
(T1) given  $x,y \in P$
, there exists $x,y \in P$
, there exists $z \in P$
 such that $z \in P$
 such that $(x,y,z) \in \mathcal {T}$
 if and only if $(x,y,z) \in \mathcal {T}$
 if and only if $y \in \lambda (x)$
; $y \in \lambda (x)$
;
- 
(T2)  $(x,y,z) \in \mathcal {T} \Rightarrow (y,z,x) \in \mathcal {T}$
; $(x,y,z) \in \mathcal {T} \Rightarrow (y,z,x) \in \mathcal {T}$
;
- 
(T3) for any  $x,y \in P$
, there is at most one $x,y \in P$
, there is at most one $z \in P$
 such that $z \in P$
 such that $(x,y,z) \in \mathcal {T}$
. $(x,y,z) \in \mathcal {T}$
.
Definition 5.1. Given a finite projective plane 
 $(P,L)$
, a bijection
$(P,L)$
, a bijection 
 $\lambda : P \to L$
 and a triella
$\lambda : P \to L$
 and a triella 
 $\mathcal {T}$
 compatible with
$\mathcal {T}$
 compatible with 
 $\lambda $
 as above, we define the associated
$\lambda $
 as above, we define the associated 
 $\tilde {A_2}$
-group by
$\tilde {A_2}$
-group by 
 $$ \begin{align*} \Gamma = \Gamma_{\mathcal{T}} := \langle a_x, x \in P \mid a_x a_y a_z = 1 \text{ for each } (x,y,z) \in \mathcal{T} \rangle. \end{align*} $$
$$ \begin{align*} \Gamma = \Gamma_{\mathcal{T}} := \langle a_x, x \in P \mid a_x a_y a_z = 1 \text{ for each } (x,y,z) \in \mathcal{T} \rangle. \end{align*} $$
Remarks 5.2.
- 
(i) The associated  $\tilde {A_2}$
-building is an oriented simplicial $\tilde {A_2}$
-building is an oriented simplicial $2$
-complex constructed from the Cayley graph of $2$
-complex constructed from the Cayley graph of $\Gamma _{\mathcal {T}}$
: the vertices or 0-simplices are identified with $\Gamma _{\mathcal {T}}$
: the vertices or 0-simplices are identified with $\Gamma _{\mathcal {T}}$
, the $\Gamma _{\mathcal {T}}$
, the $1$
-simplices are identified with pairs $1$
-simplices are identified with pairs $(w, wa_x)$
 where $(w, wa_x)$
 where $w \in \Gamma _{\mathcal {T}}$
 and $w \in \Gamma _{\mathcal {T}}$
 and $x \in P$
. The $x \in P$
. The $2$
-simplices are identified with triples $2$
-simplices are identified with triples $(w, wa_x, wa_xa_y)$
 where $(w, wa_x, wa_xa_y)$
 where $w \in \Gamma _{\mathcal {T}}$
, $w \in \Gamma _{\mathcal {T}}$
, $x \in P$
 and $x \in P$
 and $y \in \lambda (x)$
. The free and transitive action of $y \in \lambda (x)$
. The free and transitive action of $\Gamma _{\mathcal {T}}$
 on 0-simplices by left multiplication extends to a free action on the building. $\Gamma _{\mathcal {T}}$
 on 0-simplices by left multiplication extends to a free action on the building.
- 
(ii) In [Reference Konter and Vdovina24, Reference Vdovina45], Vdovina et al. start with similar data to produce an object they call a polyhedron satisfying rules that have the flavour of a triella. We discovered this point of view late in our investigation and plan to look into it more deeply in future work. 
Example 5.3. Many examples are considered in [Reference Cartwright, Mantero, Steger and Zappa9]. The following illustrative example with 
 $q = 2$
 was first described in [Reference Cartwright, Mantero, Steger and Zappa9, Section 4]:
$q = 2$
 was first described in [Reference Cartwright, Mantero, Steger and Zappa9, Section 4]: 
 $$ \begin{align*} \Gamma_{A.1} = \langle a_0 , \ldots , a_6: a_{[i]_7} a_{[i+1]_7} a_{[i+3]_7} =1 \rangle \quad\text{where }[i]_7 = (i \text{ mod }7). \end{align*} $$
$$ \begin{align*} \Gamma_{A.1} = \langle a_0 , \ldots , a_6: a_{[i]_7} a_{[i+1]_7} a_{[i+3]_7} =1 \rangle \quad\text{where }[i]_7 = (i \text{ mod }7). \end{align*} $$
 We describe elements of 
 $\Gamma _{\mathcal {T}}$
 as products of generators and their inverses. The following standard terminology for finitely generated groups helps us discuss such expressions.
$\Gamma _{\mathcal {T}}$
 as products of generators and their inverses. The following standard terminology for finitely generated groups helps us discuss such expressions.
Definition 5.4. Let 
 $\Gamma _{\mathcal {T}}$
 be an
$\Gamma _{\mathcal {T}}$
 be an 
 $\tilde {A_2}$
-group with generators
$\tilde {A_2}$
-group with generators 
 $\{ a_x : x \in P\}$
. By a word in
$\{ a_x : x \in P\}$
. By a word in 
 $\Gamma _{\mathcal {T}}$
, we mean a string of the form
$\Gamma _{\mathcal {T}}$
, we mean a string of the form 
 $g_1 g_2 \cdots g_k$
 such that each
$g_1 g_2 \cdots g_k$
 such that each 
 $g_i \in \{a_x, a_x^{-1} : x \in P\}$
. The word
$g_i \in \{a_x, a_x^{-1} : x \in P\}$
. The word 
 $g_1 \cdots g_k$
 represents the element
$g_1 \cdots g_k$
 represents the element 
 $w \in \Gamma _{\mathcal {T}}$
 if the product
$w \in \Gamma _{\mathcal {T}}$
 if the product 
 $\prod ^k_{i=1} g_i$
 in
$\prod ^k_{i=1} g_i$
 in 
 $\Gamma _{\mathcal {T}}$
 is equal to w. We typically indicate the group law by juxtaposition, so we write
$\Gamma _{\mathcal {T}}$
 is equal to w. We typically indicate the group law by juxtaposition, so we write 
 $w = g_1 \cdots g_k$
 when the word
$w = g_1 \cdots g_k$
 when the word 
 $g_1 \cdots g_k$
 represents w. Context dictates whether a string
$g_1 \cdots g_k$
 represents w. Context dictates whether a string 
 $g_1 \cdots g_k$
 is being regarded as a word or as a product.
$g_1 \cdots g_k$
 is being regarded as a word or as a product.
 It is helpful to express elements of 
 $\Gamma _{\mathcal {T}}$
 in a standard form.
$\Gamma _{\mathcal {T}}$
 in a standard form.
Proposition 5.5. Let 
 $\Gamma _{\mathcal {T}}$
 be an
$\Gamma _{\mathcal {T}}$
 be an 
 $\tilde {A_2}$
-group with generators
$\tilde {A_2}$
-group with generators 
 $\{ a_x : x \in P \}$
. Let
$\{ a_x : x \in P \}$
. Let 
 $w \in \Gamma _{\mathcal {T}}$
. Then there are unique integers
$w \in \Gamma _{\mathcal {T}}$
. Then there are unique integers 
 $m, n \ge 0$
 and unique elements
$m, n \ge 0$
 and unique elements 
 $x_1 , \ldots , x_m, y_1 , \ldots , y_n \in P$
 such that
$x_1 , \ldots , x_m, y_1 , \ldots , y_n \in P$
 such that 
 $$ \begin{align} w = a_{x_1} \cdots a_{x_{m}} a_{y_1}^{-1} \cdots a_{y_{n}}^{-1}, \text{ and } \end{align} $$
$$ \begin{align} w = a_{x_1} \cdots a_{x_{m}} a_{y_1}^{-1} \cdots a_{y_{n}}^{-1}, \text{ and } \end{align} $$
 $$ \begin{align*} &\text{(a) } x_{i+1} \not\in \lambda (x_{i} ) \text{ for }1 \le i < m;\quad \text{(b) } y_{j} \not\in \lambda ( y_{j+1} ) \text{ for }1 \le j < n;\text{ and}\quad\\ &\text{(c) } x_m \neq y_1 \text{ if }m,n \geq 1. \end{align*} $$
$$ \begin{align*} &\text{(a) } x_{i+1} \not\in \lambda (x_{i} ) \text{ for }1 \le i < m;\quad \text{(b) } y_{j} \not\in \lambda ( y_{j+1} ) \text{ for }1 \le j < n;\text{ and}\quad\\ &\text{(c) } x_m \neq y_1 \text{ if }m,n \geq 1. \end{align*} $$
For the same 
 $m,n$
, there are also unique
$m,n$
, there are also unique 
 $t_1 , \ldots , t_n, s_1 , \ldots , s_m \in P$
 such that
$t_1 , \ldots , t_n, s_1 , \ldots , s_m \in P$
 such that 
 $$ \begin{align} w = a_{t_1}^{-1} \cdots a_{t_{n}}^{-1} a_{s_1} \cdots a_{s_{m}}, \text{ and } \end{align} $$
$$ \begin{align} w = a_{t_1}^{-1} \cdots a_{t_{n}}^{-1} a_{s_1} \cdots a_{s_{m}}, \text{ and } \end{align} $$
 $$ \begin{align*} &(\text{a})^\prime s_{i+1} \not\in \lambda (s_{i}) \text{ for }1 \le i < m;\quad (\text{b})^\prime t_{j} \not\in \lambda ( t_{j+1} ) \text{ for }1 \le j < n;\text{ and}\quad\\ &(\text{c})^{\prime} t_{\ell} \neq s_1 \text{ if }m, n \geq 1. \end{align*} $$
$$ \begin{align*} &(\text{a})^\prime s_{i+1} \not\in \lambda (s_{i}) \text{ for }1 \le i < m;\quad (\text{b})^\prime t_{j} \not\in \lambda ( t_{j+1} ) \text{ for }1 \le j < n;\text{ and}\quad\\ &(\text{c})^{\prime} t_{\ell} \neq s_1 \text{ if }m, n \geq 1. \end{align*} $$
We call the expressions above the right normal form and left normal form of w, respectively. Both have minimal length amongst words in the generators and their inverses that represent w. Moreover, every minimal-length word in the generators and their inverses that represents w contains m generators and n generator-inverses.
Proof. See [Reference Cartwright, Mantero, Steger and Zappa8, Proposition 3.2] and [Reference Cartwright and Młotkowski10, Lemma 6.2].
Corollary 5.6. Let 
 $\Gamma _{\mathcal {T}}$
 be an
$\Gamma _{\mathcal {T}}$
 be an 
 $\tilde {A_2}$
-group with generators
$\tilde {A_2}$
-group with generators 
 $\{ a_x : x \in P\}$
. For all
$\{ a_x : x \in P\}$
. For all 
 $x , y \in P$
 such that
$x , y \in P$
 such that 
 $x \neq y$
, there exist unique
$x \neq y$
, there exist unique 
 $s, t \in P$
 with
$s, t \in P$
 with 
 $s \ne t$
 such that
$s \ne t$
 such that 
 $a_x^{-1} a_y= a_s a_t^{-1}$
.
$a_x^{-1} a_y= a_s a_t^{-1}$
.
 Proposition 5.5 allows us to define a degree functor for a 
 $2$
-graph structure on
$2$
-graph structure on 
 $\Gamma _{\mathcal {T}}$
 in terms of the number of generators and their inverses in a minimal representative of an element.
$\Gamma _{\mathcal {T}}$
 in terms of the number of generators and their inverses in a minimal representative of an element.
Definition 5.7. Let 
 $\Gamma _{\mathcal {T}}$
 be an
$\Gamma _{\mathcal {T}}$
 be an 
 $\tilde {A_2}$
-group. Define
$\tilde {A_2}$
-group. Define 
 $\delta : \Gamma _{\mathcal {T}} \to \mathbb {N}^2$
 by
$\delta : \Gamma _{\mathcal {T}} \to \mathbb {N}^2$
 by 
 $\delta (w) = (m,n)$
 if its right normal form is as in (5-1) (equivalently, its left normal form is as in (5-2)). We define the length of w to be
$\delta (w) = (m,n)$
 if its right normal form is as in (5-1) (equivalently, its left normal form is as in (5-2)). We define the length of w to be 
 $|\delta (w)| = m + n$
. We call
$|\delta (w)| = m + n$
. We call 
 $\delta $
 the shape function.
$\delta $
 the shape function.
Remark 5.8. The shape function 
 $\delta $
 is not additive. For example, in the
$\delta $
 is not additive. For example, in the 
 $\widetilde{A}_2$
-group
$\widetilde{A}_2$
-group 
 $\Gamma _{A.1} = \langle a_0 , \ldots , a_6: a_{[i]_7} a_{[i+1]_7} a_{[i+3]_7} =1 \rangle $
,
$\Gamma _{A.1} = \langle a_0 , \ldots , a_6: a_{[i]_7} a_{[i+1]_7} a_{[i+3]_7} =1 \rangle $
, 
 $$ \begin{align*} \delta (a_1 a_2) = \delta ( a_4^{-1} ) = (0,1) \neq (2,0) = \delta ( a_1 ) + \delta ( a_2 ). \end{align*} $$
$$ \begin{align*} \delta (a_1 a_2) = \delta ( a_4^{-1} ) = (0,1) \neq (2,0) = \delta ( a_1 ) + \delta ( a_2 ). \end{align*} $$
 The shape function 
 $\delta $
 gives rise to a natural notion of a reduced word.
$\delta $
 gives rise to a natural notion of a reduced word.
Definition 5.9. A word 
 $g_1 \cdots g_k$
 in
$g_1 \cdots g_k$
 in 
 $\Gamma _{\mathcal {T}}$
 is said to be reduced if it has minimal length among words that represent the same element of
$\Gamma _{\mathcal {T}}$
 is said to be reduced if it has minimal length among words that represent the same element of 
 $\Gamma _{\mathcal {T}}$
. That is,
$\Gamma _{\mathcal {T}}$
. That is, 
 $g_1 \cdots g_k$
 is reduced if
$g_1 \cdots g_k$
 is reduced if 
 $|\delta (g_1 \cdots g_k)| = k$
.
$|\delta (g_1 \cdots g_k)| = k$
.
Remarks 5.10.
- 
(i) The final statement of Proposition 5.5 shows that words in right normal form or left normal form are reduced words. 
- 
(ii) Not all words that have no ‘obvious cancellations’ are reduced: the word  ${w_1 = a_0{a_4}^{-1}a_6}$
 in ${w_1 = a_0{a_4}^{-1}a_6}$
 in $\Gamma _{A.1} = \langle a_0 , \ldots , a_6: a_{[i]_7} a_{[i+1]_7} a_{[i+3]_7} =1 \rangle $
 is not reduced since $\Gamma _{A.1} = \langle a_0 , \ldots , a_6: a_{[i]_7} a_{[i+1]_7} a_{[i+3]_7} =1 \rangle $
 is not reduced since $$ \begin{align*} a_0 {a_4}^{-1} a_6 = a_0 a_1a _2 a_6 = a_0 a_1{a_0}^{-1} = {a_3}^{-1}{a_0}^{-1}. \end{align*} $$ $$ \begin{align*} a_0 {a_4}^{-1} a_6 = a_0 a_1a _2 a_6 = a_0 a_1{a_0}^{-1} = {a_3}^{-1}{a_0}^{-1}. \end{align*} $$
- 
(iii) Every subword of a reduced word is reduced. 
- 
(iv) If  $w = g_1 \cdots g_k$
 is reduced and for some i, $w = g_1 \cdots g_k$
 is reduced and for some i, $g_i = a_x$
 and $g_i = a_x$
 and $g_{i+1}= a_y^{-1}$
 for some $g_{i+1}= a_y^{-1}$
 for some ${x, y \in P}$
 with ${x, y \in P}$
 with $x \ne y$
, then by Corollary 5.6, there exist unique $x \ne y$
, then by Corollary 5.6, there exist unique $s, t \in P$
 with $s, t \in P$
 with $s \ne t$
 such that $s \ne t$
 such that $a_x{a_y}^{-1} = {a_s}^{-1}a_t$
. The word obtained from w by replacing $a_x{a_y}^{-1} = {a_s}^{-1}a_t$
. The word obtained from w by replacing $g_ig_{i+1}= a_x a_y^{-1}$
 with $g_ig_{i+1}= a_x a_y^{-1}$
 with ${a_s}^{-1}a_t$
 is also reduced. ${a_s}^{-1}a_t$
 is also reduced.
Example 5.11. Consider 
 $\Gamma _{\mathcal {T}} := \Gamma _{A.1} = \langle a_0 , \ldots , a_6: a_{[i]_7} a_{[i+1]_7} a_{[i+3]_7} =1 \rangle $
 from Example 5.3. For
$\Gamma _{\mathcal {T}} := \Gamma _{A.1} = \langle a_0 , \ldots , a_6: a_{[i]_7} a_{[i+1]_7} a_{[i+3]_7} =1 \rangle $
 from Example 5.3. For 
 $w = a_0 a_2^{-1} a_5^{-1} \in \Gamma _{\mathcal {T}}$
, we have
$w = a_0 a_2^{-1} a_5^{-1} \in \Gamma _{\mathcal {T}}$
, we have 
 $\delta (w) = (1,2)$
; the reduced expressions for w and the corresponding segment of the reversed Cayley graph of
$\delta (w) = (1,2)$
; the reduced expressions for w and the corresponding segment of the reversed Cayley graph of 
 $\Gamma _{\mathcal {T}}$
 (the Cayley graph of
$\Gamma _{\mathcal {T}}$
 (the Cayley graph of 
 $\Gamma _{\mathcal {T}}^{\mathrm{op}}$
) are illustrated below.
$\Gamma _{\mathcal {T}}^{\mathrm{op}}$
) are illustrated below. 

 To obtain 
 $2$
-graphs from
$2$
-graphs from 
 $\tilde {A_2}$
 groups, we relate the shape function
$\tilde {A_2}$
 groups, we relate the shape function 
 $\delta $
 to the group law.
$\delta $
 to the group law.
Lemma 5.12 (Unique factorisation).
 Let 
 $\Gamma _{\mathcal {T}}$
 be an
$\Gamma _{\mathcal {T}}$
 be an 
 $\tilde {A_2}$
-group and suppose that
$\tilde {A_2}$
-group and suppose that 
 ${m,n \in \mathbb {N}^2}$
 and
${m,n \in \mathbb {N}^2}$
 and 
 $w \in \Gamma _{\mathcal {T}}$
 satisfy
$w \in \Gamma _{\mathcal {T}}$
 satisfy 
 $\delta (w) = m+n$
. Then there exist unique
$\delta (w) = m+n$
. Then there exist unique 
 $h,k \in \Gamma _{\mathcal {T}}$
 such that
$h,k \in \Gamma _{\mathcal {T}}$
 such that 
 $\delta (h)= m$
,
$\delta (h)= m$
, 
 $\delta (k)=n$
 and
$\delta (k)=n$
 and 
 $w=hk$
. More generally, if
$w=hk$
. More generally, if 
 $n_i \in \mathbb {N}^2$
 satisfy
$n_i \in \mathbb {N}^2$
 satisfy 
 $\delta (w) = n_1 + \cdots + n_k$
, then there exist unique
$\delta (w) = n_1 + \cdots + n_k$
, then there exist unique 
 $h_i \in \Gamma _{\mathcal {T}}$
 such that each
$h_i \in \Gamma _{\mathcal {T}}$
 such that each 
 $\delta (h_i)= n_i$
 and
$\delta (h_i)= n_i$
 and 
 $w= h_1 \cdots h_k$
.
$w= h_1 \cdots h_k$
.
 Given 
 $w, h, k \in \Gamma _{\mathcal {T}}$
 such that
$w, h, k \in \Gamma _{\mathcal {T}}$
 such that 
 $\delta (whk) = \delta (w) + \delta (h) + \delta (k)$
, we have
$\delta (whk) = \delta (w) + \delta (h) + \delta (k)$
, we have 
 $\delta (wh) = \delta (w) + \delta (h)$
 and
$\delta (wh) = \delta (w) + \delta (h)$
 and 
 $\delta (hk) = \delta (h) + \delta (k)$
.
$\delta (hk) = \delta (h) + \delta (k)$
.
Proof. This follows from repeated applications of Corollary 5.6.
Notation 5.13. If 
 $\delta (w) = (m,n) \ge \mathbf {1}$
, then Lemma 5.12 yields unique
$\delta (w) = (m,n) \ge \mathbf {1}$
, then Lemma 5.12 yields unique 
 $a,b,c,d\in \Gamma _{\mathcal {T}}$
 such that
$a,b,c,d\in \Gamma _{\mathcal {T}}$
 such that 
 $$ \begin{align*} w = bd = c a, \quad \delta ( a ) = \delta( b ) = \mathbf{1} \quad\text{and} \quad \delta ( d ) = \delta (c) = \delta (w) - \mathbf{1}. \end{align*} $$
$$ \begin{align*} w = bd = c a, \quad \delta ( a ) = \delta( b ) = \mathbf{1} \quad\text{and} \quad \delta ( d ) = \delta (c) = \delta (w) - \mathbf{1}. \end{align*} $$
 We adopt the notation 
 $s(w)=a$
,
$s(w)=a$
, 
 $r(w)=b$
,
$r(w)=b$
, 
 $c(w)=c$
,
$c(w)=c$
, 
 $d(w)=d$
. Note that if
$d(w)=d$
. Note that if 
 $\delta (w) = \mathbf {1}$
, then
$\delta (w) = \mathbf {1}$
, then 
 $r (w)= s (w)$
 and
$r (w)= s (w)$
 and 
 $b(w) = c(w)= 1$
.
$b(w) = c(w)= 1$
.
We provide a criterion for determining when a concatenation of three reduced words is reduced.
Proposition 5.14. Let 
 $\Gamma _{\mathcal {T}}$
 be an
$\Gamma _{\mathcal {T}}$
 be an 
 $\tilde {A_2}$
-group and fix
$\tilde {A_2}$
-group and fix 
 $w_0, w_1, w_2 \in \Gamma _{\mathcal {T}}$
. Suppose that
$w_0, w_1, w_2 \in \Gamma _{\mathcal {T}}$
. Suppose that 
 $\delta (w_0w_1) = \delta (w_0) + \delta (w_1)$
,
$\delta (w_0w_1) = \delta (w_0) + \delta (w_1)$
, 
 $\delta (w_1w_2) = \delta (w_1) + \delta (w_2)$
 and
$\delta (w_1w_2) = \delta (w_1) + \delta (w_2)$
 and 
 $\delta (w_1) \ge \mathbf {1}$
. Then
$\delta (w_1) \ge \mathbf {1}$
. Then 
 $$ \begin{align*} \delta(w_0w_1w_2) = \delta(w_0) + \delta(w_1) + \delta(w_2). \end{align*} $$
$$ \begin{align*} \delta(w_0w_1w_2) = \delta(w_0) + \delta(w_1) + \delta(w_2). \end{align*} $$
Proof. We induct on 
 $|\delta (w_2)|$
. Suppose that
$|\delta (w_2)|$
. Suppose that 
 $|\delta (w_2)|=1$
, so
$|\delta (w_2)|=1$
, so 
 $\delta (w_2) \in \{(1,0), (0,1)\}$
. If
$\delta (w_2) \in \{(1,0), (0,1)\}$
. If 
 $\delta (w_2) = (1, 0)$
, then
$\delta (w_2) = (1, 0)$
, then 
 $w_2 = a_x$
 for some
$w_2 = a_x$
 for some 
 $x \in P$
, so
$x \in P$
, so 
 $w_0w_1w_2 = w_0w_1a_x$
. By Proposition 5.5, if
$w_0w_1w_2 = w_0w_1a_x$
. By Proposition 5.5, if 
 $\delta ( w_0w_1 ) = (m, n)$
, then in left normal form,
$\delta ( w_0w_1 ) = (m, n)$
, then in left normal form, 
 $w_0w_1 = a_{s_1}^{-1} \cdots a_{s_{n}}^{-1} a_{t_1} \cdots a_{t_{m}}$
 and
$w_0w_1 = a_{s_1}^{-1} \cdots a_{s_{n}}^{-1} a_{t_1} \cdots a_{t_{m}}$
 and 
 ${w_1 = a_{p_1}^{-1} \cdots a_{p_{k}}^{-1} a_{q_1} \cdots a_{q_{\ell }}}$
. Lemma 5.12 gives
${w_1 = a_{p_1}^{-1} \cdots a_{p_{k}}^{-1} a_{q_1} \cdots a_{q_{\ell }}}$
. Lemma 5.12 gives 
 $q_{\ell } = t_m$
 (as
$q_{\ell } = t_m$
 (as 
 $\delta (w_0w_1) = \delta (w_0) + \delta (w_1)$
) and
$\delta (w_0w_1) = \delta (w_0) + \delta (w_1)$
) and 
 $x \notin \lambda (q_{\ell })$
 (as
$x \notin \lambda (q_{\ell })$
 (as 
 $\delta (w_1w_2) = \delta (w_1) + \delta (w_2)$
). Hence,
$\delta (w_1w_2) = \delta (w_1) + \delta (w_2)$
). Hence, 
 $$ \begin{align*} w_0w_1w_2= a_{s_1}^{-1} \cdots a_{s_{n}}^{-1} a_{t_1} \cdots a_{t_{m}}a_x \end{align*} $$
$$ \begin{align*} w_0w_1w_2= a_{s_1}^{-1} \cdots a_{s_{n}}^{-1} a_{t_1} \cdots a_{t_{m}}a_x \end{align*} $$
is the left normal form of 
 $w_0w_1w_2$
 and so
$w_0w_1w_2$
 and so 
 $$ \begin{align*} \delta(w_0w_1w_2) = (m+1, n)= (m, n) + (1, 0) = \delta(w_0w_1) + \delta(w_2)= \delta(w_0) + \delta(w_1) + \delta(w_2). \end{align*} $$
$$ \begin{align*} \delta(w_0w_1w_2) = (m+1, n)= (m, n) + (1, 0) = \delta(w_0w_1) + \delta(w_2)= \delta(w_0) + \delta(w_1) + \delta(w_2). \end{align*} $$
If 
 $\delta (w_2) = (0,1)$
, arguing similarly with right normal forms gives
$\delta (w_2) = (0,1)$
, arguing similarly with right normal forms gives 
 $\delta (w_0w_1w_2) = \delta (w_0) + \delta (w_1) + \delta (w_2)$
.
$\delta (w_0w_1w_2) = \delta (w_0) + \delta (w_1) + \delta (w_2)$
.
 Now suppose that the result holds for 
 $|\delta (w_2)| = n \ge 1$
, suppose that
$|\delta (w_2)| = n \ge 1$
, suppose that 
 $|\delta (w_2)| = n + 1$
. Then there exist unique
$|\delta (w_2)| = n + 1$
. Then there exist unique 
 $h, k \in \Gamma _{\mathcal {T}}$
 such that
$h, k \in \Gamma _{\mathcal {T}}$
 such that 
 $w_2 = hk$
,
$w_2 = hk$
, 
 $\delta (w_2) = \delta (h) + \delta (k)$
 and
$\delta (w_2) = \delta (h) + \delta (k)$
 and 
 $|\delta (k)|= 1$
. Since
$|\delta (k)|= 1$
. Since 
 $$ \begin{align*} \delta(w_1hk) = \delta(w_1w_2) = \delta(w_1) + \delta(w_2) = \delta(w_1) + \delta(h) + \delta(k), \end{align*} $$
$$ \begin{align*} \delta(w_1hk) = \delta(w_1w_2) = \delta(w_1) + \delta(w_2) = \delta(w_1) + \delta(h) + \delta(k), \end{align*} $$
Lemma 5.12 gives 
 $\delta (w_1h) = \delta (w_1) + \delta (h)$
. Since
$\delta (w_1h) = \delta (w_1) + \delta (h)$
. Since 
 $|\delta (h)| = n$
, the induction hypothesis gives
$|\delta (h)| = n$
, the induction hypothesis gives 
 $\delta (w_0(w_1h)) = \delta (w_0) + \delta (w_1) + \delta (h) = \delta (w_0) + \delta (w_1h)$
. Moreover,
$\delta (w_0(w_1h)) = \delta (w_0) + \delta (w_1) + \delta (h) = \delta (w_0) + \delta (w_1h)$
. Moreover, 
 $$ \begin{align*} \delta((w_1h)k) &= \delta(w_1w_2) = \delta(w_1) + \delta(w_2) = \delta(w_1) + \delta(h) + \delta(k) = \delta(w_1h) + \delta(k). \end{align*} $$
$$ \begin{align*} \delta((w_1h)k) &= \delta(w_1w_2) = \delta(w_1) + \delta(w_2) = \delta(w_1) + \delta(h) + \delta(k) = \delta(w_1h) + \delta(k). \end{align*} $$
Therefore, since 
 $\delta (w_1h) \ge \mathbf {1}$
 and
$\delta (w_1h) \ge \mathbf {1}$
 and 
 $|\delta (k)| = 1$
, it follows that
$|\delta (k)| = 1$
, it follows that 
 $$ \begin{align*} \delta(w_0w_1w_2) &= \delta(w_0(w_1h)k) = \delta(w_0) + \delta(w_1h) + \delta(k) = \delta(w_0) + \delta(w_1) + \delta(h)+ \delta(k) \\ &= \delta(w_0) + \delta(w_1) + \delta(w_2).\\[-35pt] \end{align*} $$
$$ \begin{align*} \delta(w_0w_1w_2) &= \delta(w_0(w_1h)k) = \delta(w_0) + \delta(w_1h) + \delta(k) = \delta(w_0) + \delta(w_1) + \delta(h)+ \delta(k) \\ &= \delta(w_0) + \delta(w_1) + \delta(w_2).\\[-35pt] \end{align*} $$
The following extends the above criterion to an arbitrary concatenation of reduced words.
Corollary 5.15. Fix 
 $w_0, w_1, \ldots , w_n \in \Gamma _{\mathcal {T}}$
. Suppose that
$w_0, w_1, \ldots , w_n \in \Gamma _{\mathcal {T}}$
. Suppose that 
 $\delta (w_iw_{i+1}) = \delta (w_i) + \delta (w_{i+1})$
 for all
$\delta (w_iw_{i+1}) = \delta (w_i) + \delta (w_{i+1})$
 for all 
 $0 \le i < n$
 and
$0 \le i < n$
 and 
 $\delta (w_i) \ge \mathbf {1}$
 for all
$\delta (w_i) \ge \mathbf {1}$
 for all 
 $0 < i < n$
. Then
$0 < i < n$
. Then 
 $$ \begin{align*} \delta(w_0w_1 \cdots w_{n-1} w_n) = \delta(w_0) + \delta(w_1) + \cdots + \delta(w_{n-1}) + \delta(w_{n}). \end{align*} $$
$$ \begin{align*} \delta(w_0w_1 \cdots w_{n-1} w_n) = \delta(w_0) + \delta(w_1) + \cdots + \delta(w_{n-1}) + \delta(w_{n}). \end{align*} $$
Proof. We induct on n. This is trivial for 
 $n = 1$
. Fix
$n = 1$
. Fix 
 $n \ge 1$
, suppose the result holds for all
$n \ge 1$
, suppose the result holds for all 
 $k \le n$
, and fix
$k \le n$
, and fix 
 $w_0, w_1, \ldots , w_n, w_{n+1} \in \Gamma _{\mathcal {T}}$
 with
$w_0, w_1, \ldots , w_n, w_{n+1} \in \Gamma _{\mathcal {T}}$
 with 
 $\delta (w_iw_{i+1}) = \delta (w_i) + \delta (w_{i+1})$
 for all
$\delta (w_iw_{i+1}) = \delta (w_i) + \delta (w_{i+1})$
 for all 
 $i = 0, 1, \ldots , n$
 and
$i = 0, 1, \ldots , n$
 and 
 $\delta (w_i) \ge \mathbf {1}$
 for all
$\delta (w_i) \ge \mathbf {1}$
 for all 
 $i = 1, \ldots , n$
. Then
$i = 1, \ldots , n$
. Then 
 $$ \begin{align*} \delta(w_0w_1 \cdots w_n) = \delta(w_0) + \delta(w_1) + \cdots + \delta(w_n) = \delta(w_0w_1 \cdots w_{n-1}) + \delta(w_{n}), \end{align*} $$
$$ \begin{align*} \delta(w_0w_1 \cdots w_n) = \delta(w_0) + \delta(w_1) + \cdots + \delta(w_n) = \delta(w_0w_1 \cdots w_{n-1}) + \delta(w_{n}), \end{align*} $$
and since 
 $\delta (w_n w_{n+1}) = \delta (w_n)+\delta (w_{n+1}) $
,
$\delta (w_n w_{n+1}) = \delta (w_n)+\delta (w_{n+1}) $
, 
 $$ \begin{align*} \delta(w_0w_1 \cdots w_nw_{n+1}) &= \delta(w_0w_1 \cdots w_{n-1}) + \delta(w_{n}) + \delta ( w_{n+1})\\ &= \delta(w_0) + \delta(w_1) + \cdots + \delta(w_n) + \delta ( w_{n+1}) \end{align*} $$
$$ \begin{align*} \delta(w_0w_1 \cdots w_nw_{n+1}) &= \delta(w_0w_1 \cdots w_{n-1}) + \delta(w_{n}) + \delta ( w_{n+1})\\ &= \delta(w_0) + \delta(w_1) + \cdots + \delta(w_n) + \delta ( w_{n+1}) \end{align*} $$
by Proposition 5.14. Thus, the result holds by induction.
5.2 The 
 $2$
-graph associated to an
$2$
-graph associated to an 
 $\tilde {A_2}$
-group
$\tilde {A_2}$
-group
 Given an 
 $\tilde {A_2}$
-group
$\tilde {A_2}$
-group 
 $\Gamma _{\mathcal {T}}$
, we now construct a
$\Gamma _{\mathcal {T}}$
, we now construct a 
 $2$
-graph
$2$
-graph 
 $\Lambda _{\mathcal {T}}$
 using the relation between the multiplicative structure of its reduced words and the shape function discussed in the previous section.
$\Lambda _{\mathcal {T}}$
 using the relation between the multiplicative structure of its reduced words and the shape function discussed in the previous section.
Definition 5.16. Fix an 
 $\tilde {A_2}$
-group
$\tilde {A_2}$
-group 
 $\Gamma _{\mathcal {T}}$
. We define
$\Gamma _{\mathcal {T}}$
. We define 
 $$ \begin{align*} \Lambda_{\mathcal{T}} = \{ w \in \Gamma_{\mathcal{T}} : \delta (w) \ge \mathbf{1} \} \quad\text{and} \quad \Lambda_{\mathcal{T}}^0 = \{ u \in \Gamma_{\mathcal{T}} : \delta (u) = \mathbf{1} \}. \end{align*} $$
$$ \begin{align*} \Lambda_{\mathcal{T}} = \{ w \in \Gamma_{\mathcal{T}} : \delta (w) \ge \mathbf{1} \} \quad\text{and} \quad \Lambda_{\mathcal{T}}^0 = \{ u \in \Gamma_{\mathcal{T}} : \delta (u) = \mathbf{1} \}. \end{align*} $$
We define 
 $r, s : \Lambda _{\mathcal {T}} \to \Lambda _{\mathcal {T}}^0$
 as in Notation 5.13 and
$r, s : \Lambda _{\mathcal {T}} \to \Lambda _{\mathcal {T}}^0$
 as in Notation 5.13 and 
 $d : \Lambda _{\mathcal {T}} \to \mathbb {N}^2$
 by
$d : \Lambda _{\mathcal {T}} \to \mathbb {N}^2$
 by 
 $d(\lambda ) = \delta (\lambda ) -\mathbf {1}$
. For
$d(\lambda ) = \delta (\lambda ) -\mathbf {1}$
. For 
 $\lambda ,\mu \in \Lambda _{\mathcal {T}}$
 such that
$\lambda ,\mu \in \Lambda _{\mathcal {T}}$
 such that 
 $s(\lambda ) = r(\mu )$
, we define
$s(\lambda ) = r(\mu )$
, we define 
 $\lambda \circ \mu $
 as follows: write
$\lambda \circ \mu $
 as follows: write 
 $\lambda = c(\lambda ) s(\lambda )$
 and
$\lambda = c(\lambda ) s(\lambda )$
 and 
 $\mu = r (\mu ) b(\mu )$
 as in Notation 5.13; we define
$\mu = r (\mu ) b(\mu )$
 as in Notation 5.13; we define 
 $$ \begin{align} \lambda \circ \mu := c(\lambda)s (\lambda) b(\mu). \end{align} $$
$$ \begin{align} \lambda \circ \mu := c(\lambda)s (\lambda) b(\mu). \end{align} $$
 Our definition of 
 $\lambda \circ \mu $
 in (5-3) emphasises the overlap of
$\lambda \circ \mu $
 in (5-3) emphasises the overlap of 
 $\lambda = c(\lambda )s(\lambda )$
 and
$\lambda = c(\lambda )s(\lambda )$
 and 
 ${\mu = r(\mu )c(\mu )}$
 in the element
${\mu = r(\mu )c(\mu )}$
 in the element 
 $s(\lambda ) = r(\mu )$
 of
$s(\lambda ) = r(\mu )$
 of 
 $\delta ^{-1}(\mathbf {1}) \subseteq \Gamma _{\mathcal {T}}$
. We can also express it to emphasise its compatibility with the maps b and c: for
$\delta ^{-1}(\mathbf {1}) \subseteq \Gamma _{\mathcal {T}}$
. We can also express it to emphasise its compatibility with the maps b and c: for 
 $\lambda , \mu \in \Lambda _{\mathcal {T}}$
 as above with
$\lambda , \mu \in \Lambda _{\mathcal {T}}$
 as above with 
 $s(\lambda ) = r(\mu )$
,
$s(\lambda ) = r(\mu )$
, 
 $$ \begin{align} \lambda \circ \mu = c(\lambda)s(\lambda)b(\mu) = r(\lambda) b(\lambda) b(\mu) \quad\text{and}\quad \lambda \circ \mu = c(\lambda) r ( \mu ) b(\mu) = c(\lambda) c(\mu) s(\mu). \end{align} $$
$$ \begin{align} \lambda \circ \mu = c(\lambda)s(\lambda)b(\mu) = r(\lambda) b(\lambda) b(\mu) \quad\text{and}\quad \lambda \circ \mu = c(\lambda) r ( \mu ) b(\mu) = c(\lambda) c(\mu) s(\mu). \end{align} $$
 Our main result in this subsection is that Definition 5.16 defines a 
 $2$
-graph.
$2$
-graph.
Theorem 5.17. With definitions and notation as above, 
 $(\Lambda _{\mathcal {T}}, d )$
 is a
$(\Lambda _{\mathcal {T}}, d )$
 is a 
 $2$
-graph and the maps
$2$
-graph and the maps 
 $b, c : \Lambda _{\mathcal {T}} \to \Gamma _{\mathcal {T}}$
 of Notation 5.13 are
$b, c : \Lambda _{\mathcal {T}} \to \Gamma _{\mathcal {T}}$
 of Notation 5.13 are 
 $1$
-cocycles.
$1$
-cocycles.
Proof. Associativity of multiplication in 
 $\Gamma _{\mathcal {T}}$
 ensures that
$\Gamma _{\mathcal {T}}$
 ensures that 
 $\Lambda _{\mathcal {T}}$
 is a category under
$\Lambda _{\mathcal {T}}$
 is a category under 
 $\circ $
. To see that
$\circ $
. To see that 
 $d : \Lambda _{\mathcal {T}} \to \mathbb {N}^2$
 is a functor, fix
$d : \Lambda _{\mathcal {T}} \to \mathbb {N}^2$
 is a functor, fix 
 $\lambda ,\mu \in \Lambda _{\mathcal {T}}$
 with
$\lambda ,\mu \in \Lambda _{\mathcal {T}}$
 with 
 $s(\lambda )=r(\mu )$
. We have
$s(\lambda )=r(\mu )$
. We have 
 ${\lambda \circ \mu = c(\lambda )s(\lambda )b(\mu )}$
, where
${\lambda \circ \mu = c(\lambda )s(\lambda )b(\mu )}$
, where 
 $\delta (s(\lambda ))) = \mathbf {1}$
. So the first part of Lemma 5.12 gives
$\delta (s(\lambda ))) = \mathbf {1}$
. So the first part of Lemma 5.12 gives 
 $$ \begin{align*} \delta(c(\lambda)s(\lambda)) &= d(\lambda) + \mathbf{1} = \delta(c(\lambda)) + \delta(s(\lambda)) \\ \delta(s(\lambda)b(\mu)) &= d(\mu) + \mathbf{1} = \delta(s(\lambda)) + \delta(b(\mu)). \end{align*} $$
$$ \begin{align*} \delta(c(\lambda)s(\lambda)) &= d(\lambda) + \mathbf{1} = \delta(c(\lambda)) + \delta(s(\lambda)) \\ \delta(s(\lambda)b(\mu)) &= d(\mu) + \mathbf{1} = \delta(s(\lambda)) + \delta(b(\mu)). \end{align*} $$
Hence, by Proposition 5.14 and since 
 $\delta (s(\lambda )) = \mathbf {1}$
 by definition,
$\delta (s(\lambda )) = \mathbf {1}$
 by definition, 
 $$ \begin{align*} d(\lambda \circ \mu) = \delta(c(\lambda)s(\lambda) b(\mu)) - \mathbf{1} = \delta(c(\lambda)) + \delta(s(\lambda)) + \delta( b(\mu)) - \mathbf{1} = d(\lambda) + d(\mu). \end{align*} $$
$$ \begin{align*} d(\lambda \circ \mu) = \delta(c(\lambda)s(\lambda) b(\mu)) - \mathbf{1} = \delta(c(\lambda)) + \delta(s(\lambda)) + \delta( b(\mu)) - \mathbf{1} = d(\lambda) + d(\mu). \end{align*} $$
 It remains to show that 
 $( \Lambda _{\mathcal {T}},d)$
 satisfies the factorisation property. Suppose that
$( \Lambda _{\mathcal {T}},d)$
 satisfies the factorisation property. Suppose that 
 $d(\lambda ) = (m_1+m_2,n_1+n_2)$
. Then
$d(\lambda ) = (m_1+m_2,n_1+n_2)$
. Then 
 $\delta ( \lambda ) = (m_1+m_2,n_1+n_2)+\mathbf {1}$
. Hence, by Lemma 5.12, there exist unique
$\delta ( \lambda ) = (m_1+m_2,n_1+n_2)+\mathbf {1}$
. Hence, by Lemma 5.12, there exist unique 
 $g, h, k$
 such that
$g, h, k$
 such that 
 $ \lambda = ghk$
,
$ \lambda = ghk$
, 
 $\delta (g) = (m_1, n_1)$
,
$\delta (g) = (m_1, n_1)$
, 
 $\delta (h) = \mathbf {1}$
 and
$\delta (h) = \mathbf {1}$
 and 
 ${\delta (k) = (m_2, n_2)}$
. Thus,
${\delta (k) = (m_2, n_2)}$
. Thus, 
 $\lambda = \mu \circ \nu $
, where
$\lambda = \mu \circ \nu $
, where 
 $\mu = gh$
,
$\mu = gh$
, 
 $\nu = hk$
,
$\nu = hk$
, 
 $d(\mu ) = (m_1, n_1)$
 and
$d(\mu ) = (m_1, n_1)$
 and 
 $d(\nu ) = (m_2, n_2)$
, and this is the unique such factorisation.
$d(\nu ) = (m_2, n_2)$
, and this is the unique such factorisation.
 Fix 
 $\lambda , \mu \in \Lambda _{\mathcal {T}}$
 with
$\lambda , \mu \in \Lambda _{\mathcal {T}}$
 with 
 $s(\lambda ) = r(\mu )$
. Equation (5-4) and the definition of c give
$s(\lambda ) = r(\mu )$
. Equation (5-4) and the definition of c give 
 $c(\lambda \circ \mu )s(\lambda \circ \mu ) = \lambda \circ \mu = c(\lambda )c(\mu )s(\mu )$
 and
$c(\lambda \circ \mu )s(\lambda \circ \mu ) = \lambda \circ \mu = c(\lambda )c(\mu )s(\mu )$
 and 
 $r(\lambda \circ \mu )b(\lambda \circ \mu ) = \lambda \circ \mu = r(\lambda ) b(\lambda )b(\mu )$
. We already saw that
$r(\lambda \circ \mu )b(\lambda \circ \mu ) = \lambda \circ \mu = r(\lambda ) b(\lambda )b(\mu )$
. We already saw that 
 $s(\lambda \circ \mu ) = s(\mu )$
 and
$s(\lambda \circ \mu ) = s(\mu )$
 and 
 $r(\lambda \circ \mu ) = r(\lambda )$
, so cancellativity in
$r(\lambda \circ \mu ) = r(\lambda )$
, so cancellativity in 
 $\Gamma _{\mathcal {T}}$
 gives
$\Gamma _{\mathcal {T}}$
 gives 
 $c(\lambda )c(\mu ) = c(\lambda \circ \mu )$
 and
$c(\lambda )c(\mu ) = c(\lambda \circ \mu )$
 and 
 $b(\lambda )b(\mu ) = b(\lambda \circ \mu )$
.
$b(\lambda )b(\mu ) = b(\lambda \circ \mu )$
.
Remark 5.18. Resume the notation of [Reference Robertson and Steger38, Section 7]. Let 
 $M_1, M_2$
 be the matrices [Reference Robertson and Steger38, page 135] obtained from the Cayley graph
$M_1, M_2$
 be the matrices [Reference Robertson and Steger38, page 135] obtained from the Cayley graph 
 $\mathscr {B}_{\mathcal {T}}$
 of
$\mathscr {B}_{\mathcal {T}}$
 of 
 $\Gamma _{\mathcal {T}}$
 regarded as a building as in [Reference Cartwright, Mantero, Steger and Zappa8]. Then
$\Gamma _{\mathcal {T}}$
 regarded as a building as in [Reference Cartwright, Mantero, Steger and Zappa8]. Then 
 $\Lambda _{\mathcal {T}}$
 is isomorphic to the
$\Lambda _{\mathcal {T}}$
 is isomorphic to the 
 $2$
-graph
$2$
-graph 
 $\Lambda _{M_1, M_2}$
 obtained from the
$\Lambda _{M_1, M_2}$
 obtained from the 
 $M_i$
 as in [Reference Kumjian and Pask26, Example 1.7(iv)]. Indeed, as
$M_i$
 as in [Reference Kumjian and Pask26, Example 1.7(iv)]. Indeed, as 
 $\Gamma _{\mathcal {T}}$
 acts transitively on vertices of
$\Gamma _{\mathcal {T}}$
 acts transitively on vertices of 
 $\mathscr {B}_{\mathcal {T}}$
, we can identify the alphabet
$\mathscr {B}_{\mathcal {T}}$
, we can identify the alphabet 
 $A = \Gamma /\mathcal {I}$
 [Reference Robertson and Steger38, page 135] with type-rotating isometries
$A = \Gamma /\mathcal {I}$
 [Reference Robertson and Steger38, page 135] with type-rotating isometries 
 ${i : t \to \mathscr {B}_{\mathcal {T}}}$
 such that
${i : t \to \mathscr {B}_{\mathcal {T}}}$
 such that 
 $i((0,0)) = e_{\Gamma _{\mathcal {T}}}$
. By Proposition 5.5,
$i((0,0)) = e_{\Gamma _{\mathcal {T}}}$
. By Proposition 5.5, 
 $i \mapsto i((1,1))$
 is a bijection between such isometries and
$i \mapsto i((1,1))$
 is a bijection between such isometries and 
 $\delta ^{-1}(\mathbf {1}) = \Lambda _{\mathcal {T}}^0$
. Likewise, for
$\delta ^{-1}(\mathbf {1}) = \Lambda _{\mathcal {T}}^0$
. Likewise, for 
 $w_1, w_2 \in \Lambda _{\mathcal {T}}^0$
, the set
$w_1, w_2 \in \Lambda _{\mathcal {T}}^0$
, the set 
 $w_1\Lambda _{\mathcal {T}}^{\varepsilon _i}w_2$
 is in bijection with type-rotating isometries
$w_1\Lambda _{\mathcal {T}}^{\varepsilon _i}w_2$
 is in bijection with type-rotating isometries 
 $i : \mathfrak {p}_{\varepsilon _i} \to \mathscr {B}_{\mathcal {T}}$
 such that
$i : \mathfrak {p}_{\varepsilon _i} \to \mathscr {B}_{\mathcal {T}}$
 such that 
 $i((0,0)) = e_{\Gamma _{\mathcal {T}}}$
,
$i((0,0)) = e_{\Gamma _{\mathcal {T}}}$
, 
 $t(\mathbf {1}) = w_1$
 and
$t(\mathbf {1}) = w_1$
 and 
 $t(\mathbf {1}+\varepsilon _i)t(\varepsilon _i)^{-1} = w_2$
; that is, diagrams as in [Reference Robertson and Steger38, Figure 9]. So the adjacency matrices of
$t(\mathbf {1}+\varepsilon _i)t(\varepsilon _i)^{-1} = w_2$
; that is, diagrams as in [Reference Robertson and Steger38, Figure 9]. So the adjacency matrices of 
 $\Lambda _{\mathcal {T}}$
 are the
$\Lambda _{\mathcal {T}}$
 are the 
 $M_i$
. Since
$M_i$
. Since 
 $M_1, M_2$
 satisfy (H0)–(H3) [Reference Robertson and Steger38, Proposition 7.9 and Theorem 7.10],
$M_1, M_2$
 satisfy (H0)–(H3) [Reference Robertson and Steger38, Proposition 7.9 and Theorem 7.10], 
 $M_1M_2$
 is a
$M_1M_2$
 is a 
 $0,1$
-matrix, so [Reference Hazlewood, Raeburn, Sims and Webster19, Theorems 4.4 and 4.5] gives
$0,1$
-matrix, so [Reference Hazlewood, Raeburn, Sims and Webster19, Theorems 4.4 and 4.5] gives 
 $\Lambda _{\mathcal {T}} \cong \Lambda _{M_1, M_2}$
.
$\Lambda _{\mathcal {T}} \cong \Lambda _{M_1, M_2}$
.
Corollary 5.19. With notation as above, the cocycle 
 $c: \Lambda _{\mathcal {T}} \to \Gamma _{\mathcal {T}}$
 of Theorem 5.17 is essential and the canonical map
$c: \Lambda _{\mathcal {T}} \to \Gamma _{\mathcal {T}}$
 of Theorem 5.17 is essential and the canonical map 
 $i : \Lambda _{\mathcal {T}} \to \Pi (\Lambda _{\mathcal {T}})$
 is injective.
$i : \Lambda _{\mathcal {T}} \to \Pi (\Lambda _{\mathcal {T}})$
 is injective.
5.3 The covering 
 $2$
-graph
$2$
-graph 
 $\Sigma _{\mathcal {T}}$
$\Sigma _{\mathcal {T}}$
 In this section, we construct a covering 
 $2$
-graph
$2$
-graph 
 $\Sigma _{\mathcal {T}}$
 for
$\Sigma _{\mathcal {T}}$
 for 
 $\Lambda _{\mathcal {T}}$
.
$\Lambda _{\mathcal {T}}$
.
 We define 
 $\Sigma _{\mathcal {T}} \subseteq \Gamma _{\mathcal {T}} \times \Gamma _{\mathcal {T}}$
 as follows. Let
$\Sigma _{\mathcal {T}} \subseteq \Gamma _{\mathcal {T}} \times \Gamma _{\mathcal {T}}$
 as follows. Let 
 $$ \begin{align*} \Sigma_{\mathcal{T}} := \{ (x, y) \in \Gamma_{\mathcal{T}} \times \Gamma_{\mathcal{T}} : \mathbf{1} \le \delta(x^{-1}y) \} \quad\text{and} \quad \Sigma^0_{\mathcal{T}} := \{ (x, y) \in \Gamma_{\mathcal{T}} \times \Gamma_{\mathcal{T}} : \mathbf{1} = \delta(x^{-1}y) \} \end{align*} $$
$$ \begin{align*} \Sigma_{\mathcal{T}} := \{ (x, y) \in \Gamma_{\mathcal{T}} \times \Gamma_{\mathcal{T}} : \mathbf{1} \le \delta(x^{-1}y) \} \quad\text{and} \quad \Sigma^0_{\mathcal{T}} := \{ (x, y) \in \Gamma_{\mathcal{T}} \times \Gamma_{\mathcal{T}} : \mathbf{1} = \delta(x^{-1}y) \} \end{align*} $$
with 
 $d(x, y) := \delta (x^{-1}y) - \mathbf {1}$
 for all
$d(x, y) := \delta (x^{-1}y) - \mathbf {1}$
 for all 
 $(x, y) \in \Sigma _{\mathcal {T}}$
. By Lemma 5.12, for each
$(x, y) \in \Sigma _{\mathcal {T}}$
. By Lemma 5.12, for each 
 $(x, y) \in \Sigma _{\mathcal {T}}$
, there exist unique
$(x, y) \in \Sigma _{\mathcal {T}}$
, there exist unique 
 $z_{x,y}, w_{x,y} \in \Gamma _{\mathcal {T}}$
 such that
$z_{x,y}, w_{x,y} \in \Gamma _{\mathcal {T}}$
 such that 
 $$ \begin{align} \delta(x^{-1}z_{x,y}) = \delta(w_{x,y}^{-1}y) = \mathbf{1} \quad\text{and} \quad \delta(x^{-1}y) = \delta(x^{-1}z_{x,y}) + \delta(z_{x,y}^{-1}y) = \delta(x^{-1}w_{x,y}) + \delta(w_{x,y}^{-1}y). \end{align} $$
$$ \begin{align} \delta(x^{-1}z_{x,y}) = \delta(w_{x,y}^{-1}y) = \mathbf{1} \quad\text{and} \quad \delta(x^{-1}y) = \delta(x^{-1}z_{x,y}) + \delta(z_{x,y}^{-1}y) = \delta(x^{-1}w_{x,y}) + \delta(w_{x,y}^{-1}y). \end{align} $$
We define 
 $r(x, y) := (x, z_{x,y})$
 and
$r(x, y) := (x, z_{x,y})$
 and 
 $s(x, y) := (w_{x,y}, y)$
. If
$s(x, y) := (w_{x,y}, y)$
. If 
 $(u, v) \in \Sigma _{\mathcal {T}}$
 satisfies
$(u, v) \in \Sigma _{\mathcal {T}}$
 satisfies 
 ${s(x, y) = r(u, v)}$
, we define
${s(x, y) = r(u, v)}$
, we define 
 $(x, y)(u, v) := (x, v)$
. We show that
$(x, y)(u, v) := (x, v)$
. We show that 
 $\Sigma _{\mathcal {T}} \cong \Gamma _{\mathcal {T}} \times _{c} \Lambda _{\mathcal {T}}$
 (see Definition 2.4).
$\Sigma _{\mathcal {T}} \cong \Gamma _{\mathcal {T}} \times _{c} \Lambda _{\mathcal {T}}$
 (see Definition 2.4).
Proposition 5.20. With the above structure, 
 $\Sigma _{\mathcal {T}}$
 is a
$\Sigma _{\mathcal {T}}$
 is a 
 $2$
-graph. Let
$2$
-graph. Let 
 $c : \Lambda _{\mathcal {T}} \to \Gamma _{\mathcal {T}}$
 be the cocycle of Theorem 5.17. There is an isomorphism
$c : \Lambda _{\mathcal {T}} \to \Gamma _{\mathcal {T}}$
 be the cocycle of Theorem 5.17. There is an isomorphism 
 $\phi : \Sigma _{\mathcal {T}} \to \Gamma _{\mathcal {T}} \times _{c} \Lambda _{\mathcal {T}}$
 such that
$\phi : \Sigma _{\mathcal {T}} \to \Gamma _{\mathcal {T}} \times _{c} \Lambda _{\mathcal {T}}$
 such that 
 $\phi (x, y) = (x, x^{-1}y)$
 for all
$\phi (x, y) = (x, x^{-1}y)$
 for all 
 $(x, y) \in \Sigma _{\mathcal {T}}$
. The inverse satisfies
$(x, y) \in \Sigma _{\mathcal {T}}$
. The inverse satisfies 
 $\phi ^{-1}(x, \lambda ) = (x, x\lambda )$
. There is a free action of
$\phi ^{-1}(x, \lambda ) = (x, x\lambda )$
. There is a free action of 
 $\Gamma _{\mathcal {T}}$
 on
$\Gamma _{\mathcal {T}}$
 on 
 $\Sigma _{\mathcal {T}}$
 given by
$\Sigma _{\mathcal {T}}$
 given by 
 $g \cdot (x, y) := (gx, gy)$
, and
$g \cdot (x, y) := (gx, gy)$
, and 
 $\phi $
 is equivariant for this action and the left action of
$\phi $
 is equivariant for this action and the left action of 
 $\Gamma _{\mathcal {T}}$
 on
$\Gamma _{\mathcal {T}}$
 on 
 $\Gamma _{\mathcal {T}} \times _{c} \Lambda _{\mathcal {T}}$
 by translation in the first coordinate. In particular,
$\Gamma _{\mathcal {T}} \times _{c} \Lambda _{\mathcal {T}}$
 by translation in the first coordinate. In particular, 
 $\phi $
 descends to an isomorphism
$\phi $
 descends to an isomorphism 
 $\widetilde {\phi } : \Gamma _{\mathcal {T}} \backslash \Sigma _{\mathcal {T}} \to \Lambda _{\mathcal {T}}$
 such that
$\widetilde {\phi } : \Gamma _{\mathcal {T}} \backslash \Sigma _{\mathcal {T}} \to \Lambda _{\mathcal {T}}$
 such that 
 $\widetilde {\phi }([x,y]) = x^{-1}y$
.
$\widetilde {\phi }([x,y]) = x^{-1}y$
.
Proof. We prove that 
 $\psi : \Gamma _{\mathcal {T}} \times _{c} \Lambda _{\mathcal {T}} \to \Sigma _{\mathcal {T}}$
 defined by
$\psi : \Gamma _{\mathcal {T}} \times _{c} \Lambda _{\mathcal {T}} \to \Sigma _{\mathcal {T}}$
 defined by 
 $\psi (x, \lambda ) = (x, x\lambda )$
 for
$\psi (x, \lambda ) = (x, x\lambda )$
 for 
 ${(x, \lambda ) \in \Gamma _{\mathcal {T}} \times _{c} \Lambda _{\mathcal {T}}}$
 is an isomorphism, and deduce that
${(x, \lambda ) \in \Gamma _{\mathcal {T}} \times _{c} \Lambda _{\mathcal {T}}}$
 is an isomorphism, and deduce that 
 $\phi = \psi ^{-1}$
 has the desired properties. To see that
$\phi = \psi ^{-1}$
 has the desired properties. To see that 
 $\psi $
 is a functor, fix
$\psi $
 is a functor, fix 
 $(x, \lambda ) \in \Gamma _{\mathcal {T}} \times _{c} \Lambda _{\mathcal {T}}$
. Then
$(x, \lambda ) \in \Gamma _{\mathcal {T}} \times _{c} \Lambda _{\mathcal {T}}$
. Then 
 $d(x, \lambda ) = d(\lambda ) = d(x, x\lambda )= d(\psi (x, \lambda ) )$
. Recall that
$d(x, \lambda ) = d(\lambda ) = d(x, x\lambda )= d(\psi (x, \lambda ) )$
. Recall that 
 $c(\lambda )s(\lambda ) = \lambda = r(\lambda )b(\lambda )$
,
$c(\lambda )s(\lambda ) = \lambda = r(\lambda )b(\lambda )$
, 
 $s(x, \lambda ) = (xc(\lambda ), s(\lambda ))$
 and
$s(x, \lambda ) = (xc(\lambda ), s(\lambda ))$
 and 
 $s(x, x\lambda ) = (xc(\lambda ), x\lambda )$
 since
$s(x, x\lambda ) = (xc(\lambda ), x\lambda )$
 since 
 $w = xc(\lambda )$
 satisfies
$w = xc(\lambda )$
 satisfies 
 $\delta (w^{-1}x\lambda ) = \delta (s(\lambda )) = \mathbf {1}$
 and
$\delta (w^{-1}x\lambda ) = \delta (s(\lambda )) = \mathbf {1}$
 and 
 $$ \begin{align*} \delta(x^{-1}x\lambda) = \delta(\lambda) =\delta(c(\lambda)) + \delta(s(\lambda)) = \delta(x^{-1}w) + \delta(w^{-1}x\lambda). \end{align*} $$
$$ \begin{align*} \delta(x^{-1}x\lambda) = \delta(\lambda) =\delta(c(\lambda)) + \delta(s(\lambda)) = \delta(x^{-1}w) + \delta(w^{-1}x\lambda). \end{align*} $$
Hence,
 $$ \begin{align*} \psi(s(x, \lambda)) = \psi(xc(\lambda), s(\lambda)) = (xc(\lambda), xc(\lambda)s(\lambda)) = (xc(\lambda), x\lambda) = s(x, x\lambda) = s(\psi(x, \lambda)). \end{align*} $$
$$ \begin{align*} \psi(s(x, \lambda)) = \psi(xc(\lambda), s(\lambda)) = (xc(\lambda), xc(\lambda)s(\lambda)) = (xc(\lambda), x\lambda) = s(x, x\lambda) = s(\psi(x, \lambda)). \end{align*} $$
A similar computation shows that 
 $\psi (r(x, \lambda )) = (x, xr(\lambda )) = r(\psi (x, \lambda ))$
.
$\psi (r(x, \lambda )) = (x, xr(\lambda )) = r(\psi (x, \lambda ))$
.
 Given composable elements 
 $(x, \lambda ), (xc(\lambda ), \mu ) \in \Gamma _{\mathcal {T}} \times _{c} \Lambda _{\mathcal {T}}$
, the above argument shows that
$(x, \lambda ), (xc(\lambda ), \mu ) \in \Gamma _{\mathcal {T}} \times _{c} \Lambda _{\mathcal {T}}$
, the above argument shows that 
 $\psi (x, \lambda ), \psi (xc(\lambda ), \mu )$
 are composable in
$\psi (x, \lambda ), \psi (xc(\lambda ), \mu )$
 are composable in 
 $\Sigma _{\mathcal {T}}$
. We have
$\Sigma _{\mathcal {T}}$
. We have 
 $$ \begin{align*} \psi((x, \lambda) (xc(\lambda), \mu)) &= \psi(x, \lambda\circ\mu) = (x, x(\lambda\circ\mu))\\ &= (x, xc(\lambda)\mu) = (x, x\lambda)(xc(\lambda), xc(\lambda)\mu) = \psi(x, \lambda) \psi(xc(\lambda), \mu). \end{align*} $$
$$ \begin{align*} \psi((x, \lambda) (xc(\lambda), \mu)) &= \psi(x, \lambda\circ\mu) = (x, x(\lambda\circ\mu))\\ &= (x, xc(\lambda)\mu) = (x, x\lambda)(xc(\lambda), xc(\lambda)\mu) = \psi(x, \lambda) \psi(xc(\lambda), \mu). \end{align*} $$
Hence, 
 $\psi $
 is an isomorphism and thus
$\psi $
 is an isomorphism and thus 
 $\Sigma _{\mathcal {T}}$
 is a
$\Sigma _{\mathcal {T}}$
 is a 
 $2$
-graph. That
$2$
-graph. That 
 $\phi $
 is equivariant follows from its definition and the last assertion follows from [Reference Kumjian and Pask26, Remark 5.6].
$\phi $
 is equivariant follows from its definition and the last assertion follows from [Reference Kumjian and Pask26, Remark 5.6].
Proposition 5.21. Let 
 $(x, z), (w, y) \in \Sigma _{\mathcal {T}}^0$
. Then
$(x, z), (w, y) \in \Sigma _{\mathcal {T}}^0$
. Then 
 $(x, z)\Sigma _{\mathcal {T}}(w, y) \not = \emptyset $
 if and only if
$(x, z)\Sigma _{\mathcal {T}}(w, y) \not = \emptyset $
 if and only if 
 $$ \begin{align*} \delta(x^{-1}w) + \mathbf{1} = \delta(x^{-1}y) = \delta(z^{-1}y) + \mathbf{1}, \end{align*} $$
$$ \begin{align*} \delta(x^{-1}w) + \mathbf{1} = \delta(x^{-1}y) = \delta(z^{-1}y) + \mathbf{1}, \end{align*} $$
and then 
 $(x, z)\Sigma _{\mathcal {T}}(w, y) = \{(x, y)\}$
. In particular,
$(x, z)\Sigma _{\mathcal {T}}(w, y) = \{(x, y)\}$
. In particular, 
 $\Sigma _{\mathcal {T}}$
 is singly connected and
$\Sigma _{\mathcal {T}}$
 is singly connected and 
 $C^*(\Sigma _{\mathcal {T}})$
 is type I
$C^*(\Sigma _{\mathcal {T}})$
 is type I
 $_0$
.
$_0$
.
Proof. If 
 $\sigma \in (x, z)\Sigma _{\mathcal {T}}(w, y)$
, then
$\sigma \in (x, z)\Sigma _{\mathcal {T}}(w, y)$
, then 
 $r(\sigma ) = (x, z)$
 and
$r(\sigma ) = (x, z)$
 and 
 $s(\sigma ) = (w, y)$
, so
$s(\sigma ) = (w, y)$
, so 
 $\sigma = (x, y)$
,
$\sigma = (x, y)$
, 
 $w = w_{x, y}$
 and
$w = w_{x, y}$
 and 
 $z = z_{x, y}$
 by (5-5). In particular,
$z = z_{x, y}$
 by (5-5). In particular, 
 $(x, z)\Sigma _{\mathcal {T}}(w, y)$
 is either empty or equal to
$(x, z)\Sigma _{\mathcal {T}}(w, y)$
 is either empty or equal to 
 $\{(x, y)\}$
.
$\{(x, y)\}$
.
 If 
 $\delta (x^{-1}y) \ge \mathbf {1}$
, then
$\delta (x^{-1}y) \ge \mathbf {1}$
, then 
 $(x,y) \in \Sigma _{\mathcal {T}}$
 if and only if
$(x,y) \in \Sigma _{\mathcal {T}}$
 if and only if 
 $s(x, y) = (w, y)$
 and
$s(x, y) = (w, y)$
 and 
 $r(x, y) = (x, z)$
. Moreover,
$r(x, y) = (x, z)$
. Moreover, 
 $s(x, y) = (w, y)$
 if and only if
$s(x, y) = (w, y)$
 if and only if 
 $w = w_{x, y}$
, that is (see (5-5)),
$w = w_{x, y}$
, that is (see (5-5)), 
 $$ \begin{align*} \delta(x^{-1}y) &= \delta(x^{-1}w) + \delta(w^{-1}y) = \delta(x^{-1}w) + \mathbf{1} \end{align*} $$
$$ \begin{align*} \delta(x^{-1}y) &= \delta(x^{-1}w) + \delta(w^{-1}y) = \delta(x^{-1}w) + \mathbf{1} \end{align*} $$
and 
 $r(x, y) = (x, z)$
 if and only if
$r(x, y) = (x, z)$
 if and only if 
 $z = z_{x, y}$
, that is,
$z = z_{x, y}$
, that is, 
 $$ \begin{align*} \delta(x^{-1}y) &= \delta(x^{-1}z) + \delta(z^{-1}y) = \delta(z^{-1}y) + \mathbf{1}. \end{align*} $$
$$ \begin{align*} \delta(x^{-1}y) &= \delta(x^{-1}z) + \delta(z^{-1}y) = \delta(z^{-1}y) + \mathbf{1}. \end{align*} $$
The final assertion follows from the first paragraph of the proof and Proposition 4.4.
Remark 5.22. That 
 $\Sigma _{\mathcal {T}}$
 is singly connected also follows from the facts that
$\Sigma _{\mathcal {T}}$
 is singly connected also follows from the facts that 
 ${\Sigma _{\mathcal {T}} \cong \Gamma _{\mathcal {T}} \times _{c} \Lambda _{\mathcal {T}}}$
 (by Proposition 5.20), c is essential and
${\Sigma _{\mathcal {T}} \cong \Gamma _{\mathcal {T}} \times _{c} \Lambda _{\mathcal {T}}}$
 (by Proposition 5.20), c is essential and 
 $\Gamma _{\mathcal {T}} \times _{c} \Lambda _{\mathcal {T}}$
 is singly connected (by Corollary 5.19).
$\Gamma _{\mathcal {T}} \times _{c} \Lambda _{\mathcal {T}}$
 is singly connected (by Corollary 5.19).
 
 







 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
