For a representation 
            
                $\unicode[STIX]{x1D70B}$
            
          of a connected Lie group
               $\unicode[STIX]{x1D70B}$
            
          of a connected Lie group 
            
                $G$
            
          on a topological vector space
               $G$
            
          on a topological vector space 
            
                $E$
            
          we defined in [Reference Gimperlein, Krötz and SchlichtkrullGKS11] a vector subspace
               $E$
            
          we defined in [Reference Gimperlein, Krötz and SchlichtkrullGKS11] a vector subspace 
            
                $E^{\unicode[STIX]{x1D714}}$
            
          of
               $E^{\unicode[STIX]{x1D714}}$
            
          of 
            
                $E$
            
          of analytic vectors. Further, we equipped
               $E$
            
          of analytic vectors. Further, we equipped 
            
                $E^{\unicode[STIX]{x1D714}}$
            
          with an inductive limit topology. We called a representation
               $E^{\unicode[STIX]{x1D714}}$
            
          with an inductive limit topology. We called a representation 
            
                $(\unicode[STIX]{x1D70B},E)$
            
          
         analytic if
               $(\unicode[STIX]{x1D70B},E)$
            
          
         analytic if 
            
                $E=E^{\unicode[STIX]{x1D714}}$
            
          as topological vector spaces.
               $E=E^{\unicode[STIX]{x1D714}}$
            
          as topological vector spaces.
 Some mistakes in the paper have been pointed out by Glöckner (see [Reference GlöcknerGlö13]). For a representation 
            
                $(\unicode[STIX]{x1D70B},E)$
            
          and a closed
               $(\unicode[STIX]{x1D70B},E)$
            
          and a closed 
            
                $G$
            
         -invariant subspace
               $G$
            
         -invariant subspace 
            
                $F$
            
          of
               $F$
            
          of 
            
                $E$
            
          we asserted in Lemma 3.6(i) that
               $E$
            
          we asserted in Lemma 3.6(i) that 
            
                $F^{\unicode[STIX]{x1D714}}=E^{\unicode[STIX]{x1D714}}\cap F$
            
          as a topological space. Based on that, we further asserted in Lemma 3.6(ii) that the inclusion
               $F^{\unicode[STIX]{x1D714}}=E^{\unicode[STIX]{x1D714}}\cap F$
            
          as a topological space. Based on that, we further asserted in Lemma 3.6(ii) that the inclusion 
            
                $E^{\unicode[STIX]{x1D714}}/F^{\unicode[STIX]{x1D714}}\rightarrow (E/F)^{\unicode[STIX]{x1D714}}$
            
          is continuous and in Lemma 3.11 that if
               $E^{\unicode[STIX]{x1D714}}/F^{\unicode[STIX]{x1D714}}\rightarrow (E/F)^{\unicode[STIX]{x1D714}}$
            
          is continuous and in Lemma 3.11 that if 
            
                $(\unicode[STIX]{x1D70B},E)$
            
          is analytic then so is the restriction to
               $(\unicode[STIX]{x1D70B},E)$
            
          is analytic then so is the restriction to 
            
                $F$
            
         . However, there is a gap in the proof of the first assertion, and presently it is not clear to us whether the above statements are then true in this generality (for unitary representations
               $F$
            
         . However, there is a gap in the proof of the first assertion, and presently it is not clear to us whether the above statements are then true in this generality (for unitary representations 
            
                $(\unicode[STIX]{x1D70B},E)$
            
          they are straightforward). Our proof does give the following weaker version of the two lemmas.
               $(\unicode[STIX]{x1D70B},E)$
            
          they are straightforward). Our proof does give the following weaker version of the two lemmas.
Lemma 1. Let 
                  
                      $(\unicode[STIX]{x1D70B},E)$
                  
                be a representation and let
                     $(\unicode[STIX]{x1D70B},E)$
                  
                be a representation and let 
                  
                      $F\subset E$
                  
                be a closed invariant subspace. Then:
                     $F\subset E$
                  
                be a closed invariant subspace. Then:
- 
                     
                     (i)  $F^{\unicode[STIX]{x1D714}}=E^{\unicode[STIX]{x1D714}}\cap F$
                           
                         as vector spaces and with continuous inclusion $F^{\unicode[STIX]{x1D714}}=E^{\unicode[STIX]{x1D714}}\cap F$
                           
                         as vector spaces and with continuous inclusion $F^{\unicode[STIX]{x1D714}}\rightarrow E^{\unicode[STIX]{x1D714}}$
                           
                        ; $F^{\unicode[STIX]{x1D714}}\rightarrow E^{\unicode[STIX]{x1D714}}$
                           
                        ;
- 
                     
                     (ii)  $E^{\unicode[STIX]{x1D714}}/E^{\unicode[STIX]{x1D714}}\cap F\subset (E/F)^{\unicode[STIX]{x1D714}}$
                           
                         continuously; $E^{\unicode[STIX]{x1D714}}/E^{\unicode[STIX]{x1D714}}\cap F\subset (E/F)^{\unicode[STIX]{x1D714}}$
                           
                         continuously;
- 
                     
                     (iii) if  $(\unicode[STIX]{x1D70B},E)$
                           
                         is an analytic representation, then $(\unicode[STIX]{x1D70B},E)$
                           
                         is an analytic representation, then $\unicode[STIX]{x1D70B}$
                           
                         induces an analytic representation on $\unicode[STIX]{x1D70B}$
                           
                         induces an analytic representation on $E/F$
                           
                        . $E/F$
                           
                        .
 Indeed, for (iii) note that if 
            
                $E$
            
          is analytic,
               $E$
            
          is analytic, 
            
                $E/F=E^{\unicode[STIX]{x1D714}}/E^{\unicode[STIX]{x1D714}}\cap F\subset (E/F)^{\unicode[STIX]{x1D714}}$
            
          continuously by (ii), and
               $E/F=E^{\unicode[STIX]{x1D714}}/E^{\unicode[STIX]{x1D714}}\cap F\subset (E/F)^{\unicode[STIX]{x1D714}}$
            
          continuously by (ii), and 
            
                $(E/F)^{\unicode[STIX]{x1D714}}\subset E/F$
            
          continuously.
               $(E/F)^{\unicode[STIX]{x1D714}}\subset E/F$
            
          continuously.
 Further, we asserted in Proposition 3.7 a general completeness property of the functor which associates 
            
                $E^{\unicode[STIX]{x1D714}}$
            
          to
               $E^{\unicode[STIX]{x1D714}}$
            
          to 
            
                $E$
            
         . However, there is a gap in the proof, which asserts that
               $E$
            
         . However, there is a gap in the proof, which asserts that 
            
                $v_{i}\rightarrow v$
            
          in the topology of
               $v_{i}\rightarrow v$
            
          in the topology of 
            
                $E^{\unicode[STIX]{x1D714}}$
            
         . As statements in this generality are not needed for the main result, we can leave out the proposition (together with Remark 3.8).
               $E^{\unicode[STIX]{x1D714}}$
            
         . As statements in this generality are not needed for the main result, we can leave out the proposition (together with Remark 3.8).
 Attached to 
            
                $G$
            
          we introduced a certain analytic convolution algebra
               $G$
            
          we introduced a certain analytic convolution algebra 
            
                ${\mathcal{A}}(G)$
            
         . A central theme of the paper is the relation of analytic representations of
               ${\mathcal{A}}(G)$
            
         . A central theme of the paper is the relation of analytic representations of 
            
                $G$
            
          to algebra representations of
               $G$
            
          to algebra representations of 
            
                ${\mathcal{A}}(G)$
            
          on
               ${\mathcal{A}}(G)$
            
          on 
            
                $E$
            
         :
               $E$
            
         : 
            
                ${\mathcal{A}}(G)\times E\rightarrow E$
            
         . In Proposition 4.2(ii), we claimed that the bilinear map
               ${\mathcal{A}}(G)\times E\rightarrow E$
            
         . In Proposition 4.2(ii), we claimed that the bilinear map 
            
                ${\mathcal{A}}(G)\times {\mathcal{A}}(G)\rightarrow {\mathcal{A}}(G)$
            
          is continuous. However, the proof shows only separate continuity. For a similar reason, we need to weaken Proposition 4.6 to the following.
               ${\mathcal{A}}(G)\times {\mathcal{A}}(G)\rightarrow {\mathcal{A}}(G)$
            
          is continuous. However, the proof shows only separate continuity. For a similar reason, we need to weaken Proposition 4.6 to the following.
Proposition 2. Let 
                  
                      $(\unicode[STIX]{x1D70B},E)$
                  
                be an
                     $(\unicode[STIX]{x1D70B},E)$
                  
                be an 
                  
                      $F$
                  
               -representation. The assignment
                     $F$
                  
               -representation. The assignment 
 $$\begin{eqnarray}(f,v)\mapsto \unicode[STIX]{x1D6F1}(f)v:=\int _{G}f(g)\unicode[STIX]{x1D70B}(g)v\,dg\end{eqnarray}$$
                     $$\begin{eqnarray}(f,v)\mapsto \unicode[STIX]{x1D6F1}(f)v:=\int _{G}f(g)\unicode[STIX]{x1D70B}(g)v\,dg\end{eqnarray}$$
                  
               defines a continuous bilinear map
 $$\begin{eqnarray}{\mathcal{A}}_{n}(G)\times E\rightarrow E_{n}\end{eqnarray}$$
                     $$\begin{eqnarray}{\mathcal{A}}_{n}(G)\times E\rightarrow E_{n}\end{eqnarray}$$
                  
                for every 
                  
                      $n\in \mathbb{N}$
                  
               , and a separately continuous map
                     $n\in \mathbb{N}$
                  
               , and a separately continuous map 
 $$\begin{eqnarray}{\mathcal{A}}(G)\times E\rightarrow E^{\unicode[STIX]{x1D714}}\end{eqnarray}$$
                     $$\begin{eqnarray}{\mathcal{A}}(G)\times E\rightarrow E^{\unicode[STIX]{x1D714}}\end{eqnarray}$$
                  
                (with convergence of the defining integral in 
                  
                      $E^{\unicode[STIX]{x1D714}}$
                  
               ). Moreover, if
                     $E^{\unicode[STIX]{x1D714}}$
                  
               ). Moreover, if 
                  
                      $(\unicode[STIX]{x1D70B},E)$
                  
                is a Banach representation, then the latter bilinear map is continuous.
                     $(\unicode[STIX]{x1D70B},E)$
                  
                is a Banach representation, then the latter bilinear map is continuous.
Proof. The first statement is proved in the article, and thus only the statement for 
                  
                      $\unicode[STIX]{x1D70B}$
                  
                a Banach representation remains to be proved. We repeat the first part of the proof, now with
                     $\unicode[STIX]{x1D70B}$
                  
                a Banach representation remains to be proved. We repeat the first part of the proof, now with 
                  
                      $p$
                  
                denoting the fixed norm of
                     $p$
                  
                denoting the fixed norm of 
                  
                      $E$
                  
               . The constants
                     $E$
                  
               . The constants 
                  
                      $c,C$
                  
                such that
                     $c,C$
                  
                such that 
 $$\begin{eqnarray}p(\unicode[STIX]{x1D70B}(g)v)\leqslant Ce^{cd(g)}p(v)\quad (g\in G,v\in E)\end{eqnarray}$$
                     $$\begin{eqnarray}p(\unicode[STIX]{x1D70B}(g)v)\leqslant Ce^{cd(g)}p(v)\quad (g\in G,v\in E)\end{eqnarray}$$
                  
                and 
                  
                      $N,C_{1}$
                  
                such that
                     $N,C_{1}$
                  
                such that 
 $$\begin{eqnarray}C_{1}:=\int _{G}e^{(c-N)d(g)}\,dg<\infty\end{eqnarray}$$
                     $$\begin{eqnarray}C_{1}:=\int _{G}e^{(c-N)d(g)}\,dg<\infty\end{eqnarray}$$
                  
                are then all fixed, and so is 
                  
                      $\unicode[STIX]{x1D716}=1/(CC_{1})$
                  
               .
                     $\unicode[STIX]{x1D716}=1/(CC_{1})$
                  
               .
 Let 
                  
                      $n\in \mathbb{N}$
                  
                and an open
                     $n\in \mathbb{N}$
                  
                and an open 
                  
                      $0$
                  
               -neighborhood
                     $0$
                  
               -neighborhood 
                  
                      $W_{n}\subset E_{n}$
                  
                be given. We may assume that
                     $W_{n}\subset E_{n}$
                  
                be given. We may assume that 
 $$\begin{eqnarray}W_{n}=\{v\in E_{n}\mid p(\unicode[STIX]{x1D70B}(K_{n})v)<\unicode[STIX]{x1D716}_{n}\}\end{eqnarray}$$
                     $$\begin{eqnarray}W_{n}=\{v\in E_{n}\mid p(\unicode[STIX]{x1D70B}(K_{n})v)<\unicode[STIX]{x1D716}_{n}\}\end{eqnarray}$$
                  
                with 
                  
                      $K_{n}\subset GV_{n}$
                  
                compact and
                     $K_{n}\subset GV_{n}$
                  
                compact and 
                  
                      $\unicode[STIX]{x1D716}_{n}>0$
                  
               . Let
                     $\unicode[STIX]{x1D716}_{n}>0$
                  
               . Let 
 $$\begin{eqnarray}O_{n}:=\Bigl\{f\in {\mathcal{O}}(V_{n}G)|\sup _{z\in K_{n},g\in G}|f(z^{-1}g)|e^{Nd(g)}<\unicode[STIX]{x1D716}\unicode[STIX]{x1D716}_{n}\Bigr\}\subset {\mathcal{A}}_{n}(G).\end{eqnarray}$$
                     $$\begin{eqnarray}O_{n}:=\Bigl\{f\in {\mathcal{O}}(V_{n}G)|\sup _{z\in K_{n},g\in G}|f(z^{-1}g)|e^{Nd(g)}<\unicode[STIX]{x1D716}\unicode[STIX]{x1D716}_{n}\Bigr\}\subset {\mathcal{A}}_{n}(G).\end{eqnarray}$$
                  
                The computation in the given proof shows that if 
                  
                      $f\in O_{n}$
                  
                and
                     $f\in O_{n}$
                  
                and 
                  
                      $p(v)<1$
                  
               , then
                     $p(v)<1$
                  
               , then 
                  
                      $\unicode[STIX]{x1D6F1}(f)v\in W_{n}$
                  
               . The asserted bi-continuity of
                     $\unicode[STIX]{x1D6F1}(f)v\in W_{n}$
                  
               . The asserted bi-continuity of 
                  
                      ${\mathcal{A}}(G)\times E\rightarrow E^{\unicode[STIX]{x1D714}}$
                  
                follows.◻
                     ${\mathcal{A}}(G)\times E\rightarrow E^{\unicode[STIX]{x1D714}}$
                  
                follows.◻
 As a consequence, we obtain as in Example 4.10(a), but only for Banach representations 
            
                $(\unicode[STIX]{x1D70B},E)$
            
         , that
               $(\unicode[STIX]{x1D70B},E)$
            
         , that 
            
                $E^{\unicode[STIX]{x1D714}}$
            
          is
               $E^{\unicode[STIX]{x1D714}}$
            
          is 
            
                ${\mathcal{A}}(G)$
            
         -tempered. In particular,
               ${\mathcal{A}}(G)$
            
         -tempered. In particular, 
            
                ${\mathcal{A}}(G)$
            
          need not itself be
               ${\mathcal{A}}(G)$
            
          need not itself be 
            
                ${\mathcal{A}}(G)$
            
         -tempered, and we need to replace Lemma 5.1(i) by the following weaker version.
               ${\mathcal{A}}(G)$
            
         -tempered, and we need to replace Lemma 5.1(i) by the following weaker version.
Lemma 3. 
               
                  
                      $V^{\text{min}}$
                  
                is an analytic globalization of
                     $V^{\text{min}}$
                  
                is an analytic globalization of 
                  
                      $V$
                  
                and it carries an algebra action
                     $V$
                  
                and it carries an algebra action 
 $$\begin{eqnarray}(f,v)\mapsto \unicode[STIX]{x1D6F1}(f)v,\quad {\mathcal{A}}(G)\times V^{\text{min}}\rightarrow V^{\text{min}}\end{eqnarray}$$
                     $$\begin{eqnarray}(f,v)\mapsto \unicode[STIX]{x1D6F1}(f)v,\quad {\mathcal{A}}(G)\times V^{\text{min}}\rightarrow V^{\text{min}}\end{eqnarray}$$
                  
                of 
                  
                      ${\mathcal{A}}(G)$
                  
               , which is separately continuous.
                     ${\mathcal{A}}(G)$
                  
               , which is separately continuous.
 The main result of the paper, Theorem 5.7, has two statements concerning a Harish-Chandra module 
            
                $V$
            
          with a globalization
               $V$
            
          with a globalization 
            
                $E$
            
         :
               $E$
            
         :
- 
               
               (1) if  $E$
                     
                   is analytic $E$
                     
                   is analytic ${\mathcal{A}}(G)$
                     
                  -tempered, then ${\mathcal{A}}(G)$
                     
                  -tempered, then $E=V^{\text{min}}$
                     
                  ; $E=V^{\text{min}}$
                     
                  ;
- 
               
               (2) if  $E$
                     
                   is an $E$
                     
                   is an $F$
                     
                  -globalization, then $F$
                     
                  -globalization, then $E^{\unicode[STIX]{x1D714}}=V^{\text{min}}$
                     
                  . $E^{\unicode[STIX]{x1D714}}=V^{\text{min}}$
                     
                  .
 The proof, which relied on Lemma 3.11 and Proposition 4.6, respectively, needs to be corrected. The proof of (1) if 
            
                $V$
            
          is irreducible needs no modification. For the general case it can be adjusted as follows.
               $V$
            
          is irreducible needs no modification. For the general case it can be adjusted as follows.
 Like in the paper, it suffices to consider an exact sequence of Harish-Chandra modules 
            
                $0\rightarrow V_{1}\rightarrow V\rightarrow V_{2}\rightarrow 0$
            
         , where both
               $0\rightarrow V_{1}\rightarrow V\rightarrow V_{2}\rightarrow 0$
            
         , where both 
            
                $V_{1}$
            
          and
               $V_{1}$
            
          and 
            
                $V_{2}$
            
          have unique analytic
               $V_{2}$
            
          have unique analytic 
            
                ${\mathcal{A}}(G)$
            
         -tempered globalizations. We show that the same holds for
               ${\mathcal{A}}(G)$
            
         -tempered globalizations. We show that the same holds for 
            
                $V$
            
         .
               $V$
            
         .
 Let 
            
                $E_{1}$
            
          be the closure of
               $E_{1}$
            
          be the closure of 
            
                $V_{1}$
            
          in
               $V_{1}$
            
          in 
            
                $E$
            
          and
               $E$
            
          and 
            
                $E_{2}=E/E_{1}$
            
         . By Lemma 1(iii),
               $E_{2}=E/E_{1}$
            
         . By Lemma 1(iii), 
            
                $E_{2}$
            
          is an analytic
               $E_{2}$
            
          is an analytic 
            
                ${\mathcal{A}}(G)$
            
         -tempered globalization of
               ${\mathcal{A}}(G)$
            
         -tempered globalization of 
            
                $V_{2}$
            
         , so that by assumption
               $V_{2}$
            
         , so that by assumption 
            
                $E_{2}=V_{2}^{\text{min}}={\mathcal{A}}(G)V_{2}$
            
          as topological vector spaces.
               $E_{2}=V_{2}^{\text{min}}={\mathcal{A}}(G)V_{2}$
            
          as topological vector spaces.
 In a first step we prove that 
            
                $E_{1}=V_{1}^{\text{min}}={\mathcal{A}}(G)V_{1}$
            
          as vector spaces. For that, we note first that
               $E_{1}=V_{1}^{\text{min}}={\mathcal{A}}(G)V_{1}$
            
          as vector spaces. For that, we note first that 
            
                $E_{1}$
            
          is
               $E_{1}$
            
          is 
            
                ${\mathcal{A}}(G)$
            
         -tempered and that
               ${\mathcal{A}}(G)$
            
         -tempered and that 
            
                $V_{1}^{\text{min}}\subset E_{1}$
            
          continuously. Next, by Proposition 5.3 (which holds for any
               $V_{1}^{\text{min}}\subset E_{1}$
            
          continuously. Next, by Proposition 5.3 (which holds for any 
            
                ${\mathcal{A}}(G)$
            
         -tempered representation), we may embed
               ${\mathcal{A}}(G)$
            
         -tempered representation), we may embed 
            
                $E_{1}\subset F_{1}$
            
          continuously into a Banach globalization of
               $E_{1}\subset F_{1}$
            
          continuously into a Banach globalization of 
            
                $F_{1}$
            
          of
               $F_{1}$
            
          of 
            
                $V_{1}$
            
         . Moreover, the proof shows that the embedding is compatible with the action by
               $V_{1}$
            
         . Moreover, the proof shows that the embedding is compatible with the action by 
            
                ${\mathcal{A}}(G)$
            
         . It follows that
               ${\mathcal{A}}(G)$
            
         . It follows that 
            
                $E_{1}^{\unicode[STIX]{x1D714}}\subset F_{1}^{\unicode[STIX]{x1D714}}$
            
          continuously and as
               $E_{1}^{\unicode[STIX]{x1D714}}\subset F_{1}^{\unicode[STIX]{x1D714}}$
            
          continuously and as 
            
                ${\mathcal{A}}(G)$
            
         -modules. Further, note that since
               ${\mathcal{A}}(G)$
            
         -modules. Further, note that since 
            
                $E$
            
          is analytic, from Lemma 1(i), we also obtain
               $E$
            
          is analytic, from Lemma 1(i), we also obtain 
            
                $E_{1}^{\unicode[STIX]{x1D714}}=E^{\unicode[STIX]{x1D714}}\cap E_{1}=E_{1}$
            
          as vector spaces. Hence,
               $E_{1}^{\unicode[STIX]{x1D714}}=E^{\unicode[STIX]{x1D714}}\cap E_{1}=E_{1}$
            
          as vector spaces. Hence, 
            
                $V_{1}^{\text{min}}\subset E_{1}\subset F_{1}^{\unicode[STIX]{x1D714}}$
            
         . By assumption,
               $V_{1}^{\text{min}}\subset E_{1}\subset F_{1}^{\unicode[STIX]{x1D714}}$
            
         . By assumption, 
            
                $V_{1}$
            
          has a unique
               $V_{1}$
            
          has a unique 
            
                ${\mathcal{A}}(G)$
            
         -tempered globalization and hence
               ${\mathcal{A}}(G)$
            
         -tempered globalization and hence 
            
                $F_{1}^{\unicode[STIX]{x1D714}}\simeq V_{1}^{\text{min}}$
            
         . Therefore,
               $F_{1}^{\unicode[STIX]{x1D714}}\simeq V_{1}^{\text{min}}$
            
         . Therefore, 
            
                $V_{1}^{\text{min}}\subset E_{1}\subset F_{1}^{\unicode[STIX]{x1D714}}\simeq V_{1}^{\text{min}}$
            
         . As these maps respect the structure as
               $V_{1}^{\text{min}}\subset E_{1}\subset F_{1}^{\unicode[STIX]{x1D714}}\simeq V_{1}^{\text{min}}$
            
         . As these maps respect the structure as 
            
                ${\mathcal{A}}(G)$
            
         -modules, the inclusion is also surjective:
               ${\mathcal{A}}(G)$
            
         -modules, the inclusion is also surjective: 
            
                $V_{1}^{\text{min}}=E_{1}$
            
         .
               $V_{1}^{\text{min}}=E_{1}$
            
         .
 Being an inductive limit, 
            
                $E_{1}=F_{1}^{\unicode[STIX]{x1D714}}$
            
          is an ultrabornological space, and
               $E_{1}=F_{1}^{\unicode[STIX]{x1D714}}$
            
          is an ultrabornological space, and 
            
                $V_{1}^{\text{min}}$
            
          is webbed (see the reference in the proof of Proposition 4.6). We conclude from the open mapping theorem that
               $V_{1}^{\text{min}}$
            
          is webbed (see the reference in the proof of Proposition 4.6). We conclude from the open mapping theorem that 
            
                $V_{1}^{\text{min}}=E_{1}$
            
          also as topological vector spaces.
               $V_{1}^{\text{min}}=E_{1}$
            
          also as topological vector spaces.
With Lemma 5.2, we now have a diagram of topological vector spaces
 
          
      
 where the vertical arrow in the middle signifies the continuous inclusion 
            
                $V^{\text{min}}={\mathcal{A}}(G)V\subset E$
            
         , and where the rows are exact. The five lemma implies
               $V^{\text{min}}={\mathcal{A}}(G)V\subset E$
            
         , and where the rows are exact. The five lemma implies 
            
                $V^{\text{min}}=E$
            
          as a vector space, and as in the article we conclude from [DS79] that this is then a topological identity.
               $V^{\text{min}}=E$
            
          as a vector space, and as in the article we conclude from [DS79] that this is then a topological identity.
 Finally, for (2) we recall from Corollary 3.5 that 
            
                $(E^{\infty })^{\unicode[STIX]{x1D714}}=E^{\unicode[STIX]{x1D714}}$
            
         . The Casselman–Wallach smooth globalization theorem asserts the existence of a Banach globalization
               $(E^{\infty })^{\unicode[STIX]{x1D714}}=E^{\unicode[STIX]{x1D714}}$
            
         . The Casselman–Wallach smooth globalization theorem asserts the existence of a Banach globalization 
            
                $F$
            
          of
               $F$
            
          of 
            
                $V$
            
          such that
               $V$
            
          such that 
            
                $F^{\infty }=E^{\infty }$
            
          and therefore
               $F^{\infty }=E^{\infty }$
            
          and therefore 
            
                $F^{\unicode[STIX]{x1D714}}=E^{\unicode[STIX]{x1D714}}$
            
         . In particular,
               $F^{\unicode[STIX]{x1D714}}=E^{\unicode[STIX]{x1D714}}$
            
         . In particular, 
            
                $E^{\unicode[STIX]{x1D714}}$
            
          is
               $E^{\unicode[STIX]{x1D714}}$
            
          is 
            
                ${\mathcal{A}}(G)$
            
         -tempered by Proposition 2. Now (1) applies.
               ${\mathcal{A}}(G)$
            
         -tempered by Proposition 2. Now (1) applies.
Acknowledgement
The authors wish to thank Helge Glöckner for pointing out the discussed mistakes.
 
  
                               
                               
                               
                               
                               
                               
                         
                         
                         
                         
                         
                        